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Use the quadratic formula to solve each equation. These equations have real solutions and complex, but not real, solutions. See Examples 1 through 4. $$ \frac{1}{8} x^{2}+x+\frac{5}{2}=0 $$

Short Answer

Expert verified
The solutions to the equation are complex: \( x = -4 + 2i \) and \( x = -4 - 2i \).

Step by step solution

01

Identify a, b, and c

Start with the quadratic equation given: \( \frac{1}{8}x^2 + x + \frac{5}{2} = 0 \). Identify the coefficients for the standard form \( ax^2 + bx + c = 0 \). Here, \( a = \frac{1}{8} \), \( b = 1 \), and \( c = \frac{5}{2} \).
02

Recall the Quadratic Formula

The quadratic formula is \( x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \). We will use this formula to find the solutions for \( x \).
03

Calculate the Discriminant

The discriminant \( \Delta \) is calculated as \( b^2 - 4ac \). Substitute \( a = \frac{1}{8} \), \( b = 1 \), and \( c = \frac{5}{2} \) into the formula: \( \Delta = 1^2 - 4 \cdot \frac{1}{8} \cdot \frac{5}{2} = 1 - 1.25 = -0.25 \).
04

Analyze Discriminant

The discriminant \( \Delta = -0.25 \) is less than zero, indicating that the solutions are complex numbers (not real).
05

Substitute into the Quadratic Formula

Substitute \( a \), \( b \), and \( \Delta \) into the quadratic formula: \( x = \frac{-1 \pm \sqrt{-0.25}}{2 \times \frac{1}{8}} \).
06

Simplify the Solutions

Simplify \( \sqrt{-0.25} \), which is \( 0.5i \), where \( i \) is the imaginary unit. The expression becomes \( x = \frac{-1 \pm 0.5i}{\frac{1}{4}} \). Simplifying further, \( x = -4 \pm 2i \). Thus, the solutions are \( x = -4 + 2i \) and \( x = -4 - 2i \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Complex Solutions
When solving quadratic equations, you may sometimes encounter complex solutions. These occur when there's no real number solution to the equation. Instead, we find complex numbers, which have both a real part and an imaginary part. In our example, we have the solutions:
  • \( x = -4 + 2i \)
  • \( x = -4 - 2i \)
Here, the real part is \(-4\) and the imaginary part is \(2i\). Complex solutions like these often appear when the discriminant is negative. In simple terms, when you can't get a solution using real numbers alone, it's time to embrace the beauty and mystery of complex numbers.
Discriminant
The discriminant is a key part of the quadratic formula, represented by \( b^2 - 4ac \). It tells us what type of solutions we can expect. By examining its value:
  • If it's greater than zero, you have two distinct real solutions.
  • If it's zero, there's exactly one real solution (a repeated root).
  • If it's less than zero, as in our example where \( \Delta = -0.25 \), expect complex solutions.
This means we can't solve the quadratic by real numbers only because the square root of a negative is undefined in the real number system. Thus, the discriminant's role is crucial in determining not only the existence but the nature of the solutions.
Imaginary Numbers
Imaginary numbers are numbers that we define as products of real numbers and the imaginary unit \(i\). This unit is special because \( i^2 = -1 \). When we face a negative discriminant, like \(-0.25\), we extract the square root as an imaginary number, making our problem solvable. In our case, \( \sqrt{-0.25} = 0.5i \). Imaginary numbers open the door to complex solutions, integrating with real numbers to give us expressions like \(-4 \pm 2i\). Although these numbers might seem strange, they are incredibly useful in mathematics, science, and engineering, where they help describe phenomena that regular numbers can't. They allow us to maintain solutions when real numbers would fail, thereby greatly expanding the field of our understanding.

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Most popular questions from this chapter

Sketch the graph of each function. See Section 11.5 $$ f(x)=x^{2}+2 $$

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Sketch the graph of each quadratic function. Label the vertex, and sketch and label the axis of symmetry. See Examples 6 and 7 . $$ H(x)=2 x^{2} $$

Sketch the graph of each quadratic function. Label the vertex, and sketch and label the axis of symmetry. See Examples I through 5 . $$ h(x)=(x+2)^{2} $$

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