Chapter 11: Problem 34
Find the vertex of the graph of each quadratic function. Determine whether the graph opens upward or downward, find any intercepts, and sketch the graph. See Examples I through \(4 .\) (IMAGE CANNOT COPY) \(f(x)=x^{2}-x-12\)
Short Answer
Expert verified
Vertex: \((\frac{1}{2}, -\frac{47}{4})\); opens upward; x-intercepts: 4, -3; y-intercept: -12.
Step by step solution
01
Identify the Form of the Quadratic
The given quadratic function is \( f(x) = x^2 - x - 12 \). This is in standard form, \( ax^2 + bx + c \), where \( a = 1 \), \( b = -1 \), and \( c = -12 \).
02
Determine the Direction of Parabola Opening
The parabola opens upwards if \( a > 0 \) and downwards if \( a < 0 \). Since \( a = 1 > 0 \), the graph opens upwards.
03
Find the Vertex of the Quadratic Function
The vertex \((h, k)\) of the quadratic function in standard form can be calculated using the formula \( h = -\frac{b}{2a} \). Therefore, \( h = -\frac{-1}{2 \times 1} = \frac{1}{2} \). Substituting \( h \) back to find \( k \): \( k = f(\frac{1}{2}) = (\frac{1}{2})^2 - (\frac{1}{2}) - 12 = \frac{1}{4} - \frac{1}{2} - 12 = -\frac{47}{4} \). So, the vertex is \( (\frac{1}{2}, -\frac{47}{4}) \).
04
Calculate the x-intercepts
To find the x-intercepts, set \( f(x) = 0 \): \( x^2 - x - 12 = 0 \). Factoring the quadratic gives \((x - 4)(x + 3) = 0\). Thus, \( x = 4 \) and \( x = -3 \) are the x-intercepts.
05
Calculate the y-intercept
The y-intercept is found by evaluating \( f(0) \). Thus, \( y = f(0) = 0^2 - 0 - 12 = -12 \). The y-intercept is \( (0, -12) \).
06
Sketch the Graph
Using the vertex \((\frac{1}{2}, -\frac{47}{4})\), x-intercepts \((4, 0)\) and \((-3, 0)\), and the y-intercept \((0, -12)\), sketch the parabola. It should be symmetrical around the vertex, opening upward.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Vertex of a Parabola
The vertex of a parabola is a key point that helps us understand the shape and direction of the quadratic function's graph. For a quadratic equation in standard form, expressed as \( ax^2 + bx + c \), the vertex \(h, k\) can be found using a straightforward formula:
The vertex is not just a point on the graph; it represents the maximum or minimum value of the function, crucial for understanding how the parabola behaves and where it is located relative to the axes.
- \( h = -\frac{b}{2a} \)
- \( k \) is calculated by substituting \( h \) back into the function \( f(h) \)
The vertex is not just a point on the graph; it represents the maximum or minimum value of the function, crucial for understanding how the parabola behaves and where it is located relative to the axes.
X-Intercepts
The x-intercepts of a parabola are the points where the graph cuts through the x-axis. These intercepts are crucial for sketching the graph accurately and understanding where the function has zero values. For quadratic functions, finding the x-intercepts involves solving the equation \( f(x) = 0 \).
For \( f(x) = x^2 - x - 12 \), you can factor the quadratic equation as \( (x - 4)(x + 3) = 0 \). Solving these factors reveals the x-intercepts:
For \( f(x) = x^2 - x - 12 \), you can factor the quadratic equation as \( (x - 4)(x + 3) = 0 \). Solving these factors reveals the x-intercepts:
- \( x = 4 \)
- \( x = -3 \)
Y-Intercept
The y-intercept is where the graph crosses the y-axis, representing the output of the function when the input \( x \) is zero. It is a straightforward calculation because it involves simply substituting zero into the function for \( x \).
For the quadratic \( f(x) = x^2 - x - 12 \), calculate the y-intercept by evaluating \( f(0) \):
For the quadratic \( f(x) = x^2 - x - 12 \), calculate the y-intercept by evaluating \( f(0) \):
- \( f(0) = 0^2 - 0 - 12 = -12 \)
Parabola Direction
The direction in which a parabola opens is determined by the quadratic coefficient \( a \) in its standard form \( ax^2 + bx + c \). This direction tells us whether the function's values become larger (open upwards) or smaller (open downwards) as it moves away from the vertex.
This trait has a profound influence on the parabola's shape and means that the vertex is at the parabola's lowest point, making it a minimum of the function. Identifying the direction is crucial, as it plays a vital role in understanding the overall behavior of the function and the orientation of the graph.
- If \( a > 0 \), the parabola opens upwards.
- If \( a < 0 \), the parabola opens downwards.
This trait has a profound influence on the parabola's shape and means that the vertex is at the parabola's lowest point, making it a minimum of the function. Identifying the direction is crucial, as it plays a vital role in understanding the overall behavior of the function and the orientation of the graph.