Chapter 11: Problem 22
Sketch the graph of each quadratic function. Label the vertex, and sketch and label the axis of symmetry. See Examples 6 and 7 . $$ f(x)=-\frac{1}{4} x^{2} $$
Short Answer
Expert verified
Vertex: (0,0). Axis of symmetry: x=0. Parabola opens downwards.
Step by step solution
01
Identify the Standard Form
The function given is \( f(x) = -\frac{1}{4}x^2 \). This is in the standard form of a quadratic equation, which is \( f(x) = ax^2 + bx + c \). Here, \( a = -\frac{1}{4} \), \( b = 0 \), and \( c = 0 \).
02
Find the Vertex
The vertex of a parabola given in standard form \( ax^2 + bx + c \) is at \( x = \frac{-b}{2a} \). Plugging in \( b = 0 \) and \( a = -\frac{1}{4} \), we have \( x = \frac{0}{2 \times -\frac{1}{4}} = 0 \). So, the x-coordinate of the vertex is 0. Substitute back to find \( f(0) = -\frac{1}{4} \times 0^2 = 0 \). Thus, the vertex is at the point \((0, 0)\).
03
Determine the Axis of Symmetry
The axis of symmetry for a parabola given by \( ax^2 + bx + c \) is a vertical line through \( x = \frac{-b}{2a} \). We found this to be \( x = 0 \) in Step 2. Therefore, the axis of symmetry is the line \( x = 0 \).
04
Sketch the Graph
Sketch the parabola degined by the function \( f(x) = -\frac{1}{4}x^2 \). Begin by plotting the vertex at (0, 0). Since \( a = -\frac{1}{4} \) is negative, the parabola opens downwards. Use small values of \( x \) to plot other points; at \( x = 1 \), \( f(1) = f(-1) = -\frac{1}{4} \), and at \( x = 2 \), \( f(2) = f(-2) = -1 \). Draw the parabola through these points.
05
Label the Vertex and Axis
On your sketch, make sure to label the vertex at \((0, 0)\) and draw the axis of symmetry, a dashed line, at \( x = 0 \). Indicate that the parabola opens downwards.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Vertex of a Parabola
In a quadratic function, the vertex of a parabola is the point where the curve changes direction. This is either the highest or the lowest point of the parabola. To find the vertex in the standard form of a quadratic equation, which is \( ax^2 + bx + c \), you use the formula:
- x-coordinate: \( x = \frac{-b}{2a} \)
Axis of Symmetry
The axis of symmetry of a parabola is a vertical line that runs through the vertex. It divides the parabola into two mirror-image halves. For any quadratic equation in the form \( ax^2 + bx + c \), the axis of symmetry can be found using the formula:
- \( x = \frac{-b}{2a} \)
Standard Form of a Quadratic Equation
Understanding the standard form of a quadratic equation is crucial in graphing parabolas effectively. The standard form is:
- \( ax^2 + bx + c \)