Chapter 10: Problem 65
Simplify each radical. Assume that all variables represent positive real numbers. $$\sqrt[4]{a^{16} b^{4}}$$
Short Answer
Expert verified
The simplified expression is \(a^4 b\).
Step by step solution
01
Identifying the Expression
The expression given is \(\sqrt[4]{a^{16} b^{4}}\), which involves a fourth root. Our goal is to simplify this expression.
02
Simplifying the Fourth Root
To simplify \(\sqrt[4]{a^{16} b^{4}}\), understand that finding the fourth root of a number is equivalent to raising it to the power of \(\frac{1}{4}\). For any base \(x\), \(\sqrt[4]{x} = x^{\frac{1}{4}}\).
03
Breaking Down the Exponentials
Apply the fourth root to each component inside the radical: \(\sqrt[4]{a^{16}}\) and \(\sqrt[4]{b^4}\). This can be rewritten using exponents as \((a^{16})^{\frac{1}{4}}\) and \((b^4)^{\frac{1}{4}}\).
04
Applying the Power Rule
Using the power rule \((x^{m})^{n} = x^{m \cdot n}\), calculate each part: \((a^{16})^{\frac{1}{4}} = a^{16 \times \frac{1}{4}} = a^4\) and \((b^4)^{\frac{1}{4}} = b^{4 \times \frac{1}{4}} = b^1 = b\).
05
Combining the Results
Combine the simplified results to get the final answer: \(a^4 b\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Fourth Root
The fourth root of a number or expression is a special type of radical. It involves taking a number and figuring out which value, multiplied by itself four times, arrives at the original number. In simpler terms, if you have a number \( x \) and you want \( \sqrt[4]{x} \), you are essentially asking, 'What number times itself four times gives \( x \)?' This is different from the more common square root where the number is multiplied by itself only twice. For example, the fourth root of 16 is 2 because \( 2 \times 2 \times 2 \times 2 = 16 \). Fourth roots are often rewritten in exponential form to ease calculations, as \( \sqrt[4]{x} = x^{\frac{1}{4}} \).
In the context of simplifying the expression \( \sqrt[4]{a^{16} b^{4}} \), this means that we need to address the coefficients and exponents separately and simplify using the properties of exponents.
In the context of simplifying the expression \( \sqrt[4]{a^{16} b^{4}} \), this means that we need to address the coefficients and exponents separately and simplify using the properties of exponents.
Exponential Notation
Exponential notation allows us to express repeated multiplication of a number in a concise form. When thinking about exponentials in mathematics, it helps to remember that an exponent tells you how many times a number, known as the base, is multiplied by itself. For example, \( a^3 = a \times a \times a \).
- It's useful for simplifying expressions and performing operations like multiplication and division quickly.
- Convert roots into exponents to simplify roots easier. For example, \( \sqrt{a} \) becomes \( a^{\frac{1}{2}} \).
- In the fourth root problem \( \sqrt[4]{a^{16} b^4} \), express each radical part as an exponent: \( a^{16} \) and \( b^4 \).
Power Rule
The power rule is an important algebraic rule when dealing with exponents. It states that when you raise a power to another power, you multiply the exponents together. Mathematically, this is expressed as \( (x^m)^n = x^{m \cdot n} \). This rule simplifies complex expressions and helps in handling radicals rewritten in exponential form.
When approaching the simplification of \( (a^{16})^{\frac{1}{4}} \) for instance:
Utilizing the power rule simplifies calculating radicals in exponential notation, transforming a problem that might look complex at first into straightforward calculations and making the simplification process intuitive.
When approaching the simplification of \( (a^{16})^{\frac{1}{4}} \) for instance:
- Multiply the exponents: \( 16 \times \frac{1}{4} \).
- This results in \( a^4 \) since \( 16 \times \frac{1}{4} = 4 \).
- For \( (b^4)^{\frac{1}{4}} \), apply the same logic: \( 4 \times \frac{1}{4} = 1 \).
Utilizing the power rule simplifies calculating radicals in exponential notation, transforming a problem that might look complex at first into straightforward calculations and making the simplification process intuitive.