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Solve. $$|5 b+3|+6=19$$

Short Answer

Expert verified
The two possible solutions for the given equation are \(b = 2\) and \(b = \frac{-16}{5}\).

Step by step solution

01

Isolate the absolute value

Subtract 6 from both sides of the equation to isolate the absolute value: \(|5b + 3| = 19 - 6\)
02

Simplify

Simplify the right-hand side of the equation: \(|5b + 3| = 13\)
03

Write separate equations for negative and positive cases

Since the absolute value left inside it can be either negative or positive, we can write two separate equations: Case 1: \(5b + 3 = 13\) Case 2: \(5b + 3 = -13\)
04

Solve for b in Case 1

Subtract three from both sides in Case 1 equation to isolate the term with b: \(5b = 13 - 3\) Simplify and solve for b: \(5b = 10\) \(b = \frac{10}{5}\) \(b = 2\)
05

Solve for b in Case 2

Subtract three from both sides in Case 2 equation to isolate the term with b: \(5b = -13 - 3\) Simplify and solve for b: \(5b = -16\) \(b = \frac{-16}{5}\) So, the two possible solutions for b are: \(b = 2\) and \(b = \frac{-16}{5}\)

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Solving Equations
When faced with absolute value equations like \(|5b + 3| + 6 = 19\), the first step towards solving them is to isolate the absolute value on one side of the equation. This helps to simplify the problem.
In this exercise, begin by subtracting 6 from both sides: \(|5b + 3| = 19 - 6\). This leaves us with \(|5b + 3| = 13\). Understanding the properties of absolute value is crucial here. The absolute value function, represented by two vertical bars, measures the distance of a number from zero on the number line. It can never be negative, and it behaves in a piecewise manner, meaning that it splits the function into two separate cases based on whether the inside of the absolute value is positive or negative.
Thus, you will create two equations: one where the inside is positive \(5b + 3 = 13\) and another where it is negative \(5b + 3 = -13\). Each scenario is then solved separately for the variable \(b\).
Algebraic Solutions
Algebraic solutions involve finding the value of variables that satisfy the given equations. In our original exercise, solving both cases of the absolute value equation leads us to two different solutions.
In **Case 1**, where \(5b +3 = 13\), you subtract 3 from both sides to get \(5b = 10\). Then you divide both sides by 5 to isolate \(b\), giving \( b = 2 \). In **Case 2**, where \(5b + 3 = -13\), the process is similar. Subtracting 3 from both sides results in \(5b = -16\). After dividing both sides by 5, you reach \( b = \frac{-16}{5} \).
Both solutions are valid algebraic answers. This means that plugging these values back into the original equation should satisfy it, reinforcing the importance of checking your answers in algebra.
Step by Step Solutions
Getting to a solution using a step by step method ensures accurate and understandable results. Absolute value equations can be tricky because they involve two potential equations.
Initially, the absolute value needs to be isolated. Then, separate the equation into two logical cases, reflecting the dual nature of absolute values. Solve each resulting equation methodically.
  • Subtract Constant: Start by simplifying both sides to disconnect constants from the absolute value.
  • Create Separate Cases: Write two equations – one for the positive case and one for the negative case of the absolute value expression.
  • Solve Each Equation: Use basic algebraic techniques to solve each equation and determine all possible solutions for the variable.
Following each step not only builds confidence but also assures a well-rounded understanding of the processes involved. This approach can be applied widely, ensuring all potential solutions are discovered and checked for correctness.

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Most popular questions from this chapter

A machine in a factory can be calibrated to fill either large or small bags of potato chips. The machine will run at most 12 hr per day. Let \(x=\) number of hours the machine fills large bags \(y=\) number of hours the machine fills small bags a) Write a system of linear inequalities to describe the constraints on the number of hours the machine fills the bags each day. b) Graph the feasible region that describes how the hours can be distributed between filling the large and small bags of chips. c) Find three points in the feasible region and discuss their meanings. d) Find one point outside the feasible region and discuss its meaning.

Dawn buys a 27 -oz box of cereal. The possible error in this amount, however, is \(\pm 0.5\) oz. Let \(c\) represent the range of values for the amount of cereal in the box. Write an absolute value inequality to represent the range for the number of ounces of cereal in the box, then solve the inequality and explain the meaning of the answer.

Solve each inequality. Graph the solution set and write the answer in interval notation. $$|2 m-1|+4>5$$

The following exercises contain absolute value equations, linear inequalities, and both types of absolute value inequalities. Solve each. Write the solution set for equations in set notation and use interval notation for inequalities. $$\left|\frac{2}{3} y-1\right|=\left|\frac{3}{2} y+4\right|$$

Solve each system using Gaussian elimination. $$\begin{aligned}x-2 y+z &=-2 \\\2 x-3 y+z &=3 \\\3 x-6 y+2 z &=1\end{aligned}$$

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