Chapter 9: Problem 19
Solve each inequality. Graph the solution set and write the answer in interval notation. $$|5 q+11|<0$$
Short Answer
Expert verified
The solution to the inequality \(|8c-3|+15<20\) is \((-\frac{1}{4}, 1)\).
Step by step solution
01
Isolate the absolute value term on the left side
To isolate the absolute value term, subtract 15 from both sides of the equation:
\( |8c - 3| + 15 - 15 < 20 - 15 \)
\( |8c - 3| < 5 \)
02
Create and solve two separate inequalities
This step involves solving for two cases: one where the expression inside the absolute value is positive, and one where it is negative.
Case 1: \((8c - 3) \ge 0\)
\(8c - 3 < 5\)
Add \(3\) to both sides:
\(8c < 8\)
Divide by \(8\):
\(c < 1\)
Case 2: \((8c - 3) < 0\)
\(-8c + 3 < 5\)
Add \(8c\) to both sides:
\(3 < 5 + 8c\)
Subtract \(5\) from both sides:
\(-2 < 8c\)
Divide by \(8\):
\(-\frac{1}{4} < c\)
03
Graph the solution set
Plot the solutions on a number line. The solution \( c < 1 \) is represented by a line with an open circle at 1 and extends to the left. The solution \( -\frac{1}{4} < c \) is represented by an open circle at \(-\frac{1}{4}\) and extends to the right. The overlapping region is the solution set, which is between \(-\frac{1}{4}\) and \(1\).
04
Write the answer in interval notation
Using interval notation, the solution set is expressed as:
\((-\frac{1}{4}, 1)\)
So the answer is \((-\frac{1}{4}, 1)\).
Unlock Step-by-Step Solutions & Ace Your Exams!
-
Full Textbook Solutions
Get detailed explanations and key concepts
-
Unlimited Al creation
Al flashcards, explanations, exams and more...
-
Ads-free access
To over 500 millions flashcards
-
Money-back guarantee
We refund you if you fail your exam.
Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Absolute Value Inequalities
Understanding absolute value inequalities is a key skill in algebra. Absolute values represent the distance a number is from zero, regardless of direction on the number line. In inequalities, this means you're determining a range of values that an expression can take rather than a single solution. For example, with an inequality like \(|x| < a\), you're actually dealing with two scenarios:
- First, where the expression inside is less than the chosen threshold, i.e., \(x < a\)
- Second, considering the expression could also be greater in the opposite direction, i.e., \(-a < x\)
Interval Notation
Interval notation provides a concise way to describe a range of numbers, which is especially useful after solving inequalities. It reflects all possible solutions succinctly, conveying the idea of inequalities without explicitly writing them out.
When you have a solution such as \(-\frac{1}{4} < c < 1\), it can be written using interval notation by stating the minimum and maximum values:
When you have a solution such as \(-\frac{1}{4} < c < 1\), it can be written using interval notation by stating the minimum and maximum values:
- \((-\frac{1}{4}, 1)\)
Graphing Inequalities
Graphing inequalities involves depicting possible solutions on a number line or coordinate plane, illustrating the solution set visually. This graphical approach offers a clear view of the solution's range and relationships, such as overlapping regions or gaps.
When you graph a simple inequality like \(-\frac{1}{4} < c < 1\), use open circles at the endpoints to signal that these points are not part of the solution itself. A solid line or highlighted section indicates the continuous range of solutions.
When you graph a simple inequality like \(-\frac{1}{4} < c < 1\), use open circles at the endpoints to signal that these points are not part of the solution itself. A solid line or highlighted section indicates the continuous range of solutions.
- For \(-\frac{1}{4} < c < 1\), place an open circle at \(-\frac{1}{4}\) and another at \(1\).
- Draw a line connecting these, showing that all numbers in between satisfy the inequality.