Chapter 8: Problem 83
Determine the domain of each rational function. $$g(t)=\frac{3 t-4}{t^{2}-9 t+8}$$
Short Answer
Expert verified
The domain of the function \(g(t)=\frac{3 t-4}{t^{2}-9 t+8}\) is all real numbers except for t=1 and t=8. In interval notation, the domain is given by: \((-\infty, 1) \cup (1, 8) \cup (8, \infty)\).
Step by step solution
01
Identify the denominator of the function
The denominator of the given function is \(t^2 - 9t + 8\).
02
Set the denominator equal to zero
To find the values of t for which the function is not defined, we set the denominator equal to zero:
\(t^2 - 9t + 8 = 0\)
03
Solve the quadratic equation
We can solve the quadratic equation in step 2 by factoring:
\((t - 8)(t - 1) = 0\)
04
Find the values of t that make the denominator zero
From the factored equation, we can determine which values of t make the denominator zero:
1. Set \(t - 8 = 0\) and solve for t: \(t = 8\)
2. Set \(t - 1 = 0\) and solve for t: \(t = 1\)
05
Determine the domain of the function
Since the function is not defined when the denominator equals zero, we need to exclude the values of t found in step 4 from the domain. The domain of the function \(g(t)=\frac{3 t-4}{t^{2}-9 t+8}\) is all real numbers except for t=1 and t=8. In interval notation, the domain is given by:
\((-\infty, 1) \cup (1, 8) \cup (8, \infty)\)
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Domain of a Function
Understanding the domain of a function is crucial because it determines all the input values for which the function is defined. When dealing with rational functions, like \( g(t) = \frac{3t - 4}{t^2 - 9t + 8} \), we need to be extra attentive to the denominator. Rational functions can become undefined when their denominators equal zero, as division by zero is not allowed.
To find the domain of a rational function, follow these steps:
To find the domain of a rational function, follow these steps:
- Identify the denominator of the rational function.
- Set the denominator equal to zero and solve the resulting equation.
- Exclude the solutions from the set of all real numbers to find the domain.
Quadratic Equations
Quadratic equations are equations of the form \( ax^2 + bx + c = 0 \). They are fundamental in algebra and arise naturally in various mathematical problems. In this exercise, the denominator of the rational function \( t^2 - 9t + 8 \) is a quadratic expression.
Quadratic equations can be solved using several methods:
Quadratic equations can be solved using several methods:
- Factoring: If the quadratic can be factored into two binomial expressions, set each binomial to zero to find the solutions.
- Quadratic formula: For any quadratic equation \( ax^2 + bx + c = 0 \), the roots can be found using the formula \( x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \).
- Completing the square: This method involves rearranging the equation to form a perfect square trinomial, making it easier to solve.
Factoring
Factoring is a technique used to simplify expressions and solve equations, especially useful for quadratic equations. The goal of factoring is to rewrite the expression as a product of simpler expressions.
For quadratic expressions like \( t^2 - 9t + 8 \), factoring involves finding two numbers that multiply to the constant term, 8, and add up to the linear coefficient, -9.
Steps for factoring a simple quadratic are:
For quadratic expressions like \( t^2 - 9t + 8 \), factoring involves finding two numbers that multiply to the constant term, 8, and add up to the linear coefficient, -9.
Steps for factoring a simple quadratic are:
- Write down the equation in standard form \( ax^2 + bx + c \).
- Determine pairs of numbers that multiply to \( c \) (the constant term).
- Out of these pairs, find the one that adds up to \( b \) (the coefficient of x).
- Rewrite the quadratic as a product of two binomials using these numbers.