/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 31 Factor completely. $$12 c^{3}+... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Factor completely. $$12 c^{3}+3 c^{2}+27 c$$

Short Answer

Expert verified
The completely factored expression is: \(3(4c^3 + c^2 + 9c)\).

Step by step solution

01

Find the Greatest Common Divisor (GCD) of the coefficients

To find the GCD of the coefficients (12, 3, and 27), list their factors and find the largest factor they have in common. The factors of 12 are: 1, 2, 3, 4, 6, and 12 The factors of 3 are: 1, and 3 The factors of 27 are: 1, 3, 9, and 27 The largest (greatest) factor they all have in common is 3.
02

Factor out the GCD

Factor out the GCD found in the previous step (3) from each term in the given expression: \(3(4c^3 + c^2 + 9c)\)
03

Check for further factoring of the expression in parentheses

Observe the expression in parentheses: \(4c^3 + c^2 + 9c\). There are no further common factors among these terms, and it cannot be factored further.
04

Final Answer

The completely factored expression is: \(3(4c^3 + c^2 + 9c)\).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Greatest Common Divisor
When factoring polynomials, one of the first steps is to identify and factor out the greatest common divisor (GCD) of the terms. The GCD is the largest factor that divides each term of a polynomial without leaving a remainder. By determining this factor, we simplify the polynomial expression.

To find the GCD of the coefficients of a polynomial, list the factors of each coefficient.
  • For 12, the factors are 1, 2, 3, 4, 6, 12.
  • For 3, the factors are 1, 3.
  • For 27, the factors are 1, 3, 9, 27.
The largest factor common to 12, 3, and 27 is 3. Hence, 3 is the GCD for this polynomial.

This step is crucial as it reduces the polynomial, making it easier to work with and further factor if possible.
Polynomial Expressions
Polynomial expressions are mathematical expressions made up of variables and coefficients, combined using addition, subtraction, and multiplication. A polynomial can have multiple terms, each consisting of a coefficient and a variable raised to a power.

In the exercise, the polynomial expression is given as: \(12c^3 + 3c^2 + 27c\). Each term in this polynomial consists of a coefficient (like 12, 3, or 27) and a variable part (like \(c^3\), \(c^2\), or \(c\)).

Polynomials are often written in standard form, which means the terms are arranged from highest to lowest degree of the variable. Understanding the structure of polynomial expressions is important, as it helps to simplify, evaluate, and manipulate these mathematical expressions effectively.
Factoring Techniques
Factoring polynomials involves breaking them down into simpler 'pieces' or factors that, when multiplied together, give you the original polynomial. This process begins with finding the greatest common divisor but may extend to more complex techniques.

### Methods of Factoring:
  • **Factoring out the GCD:** This is the simplest form, where you remove the largest common factor of all terms.
  • **Grouping:** This method involves rearranging and grouping terms to find common factors.
  • **Quadratic trinomials:** Recognizing patterns can allow further factoring, especially with expressions resembling quadratics.
For the problem given, the expression after factoring out the GCD looks like this: \(3(4c^3 + c^2 + 9c)\). Here, no further simplification was possible using advanced techniques, as the remaining polynomial is already in its simplest form.

Mastering these techniques allows solving a wide range of polynomial equations efficiently by reducing them into basic, solvable units.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Organizers of fireworks shows use quadratic and linear equations to help them design their programs. Shells contain the chemicals which produce the bursts we see in the sky. At a fireworks show the shells are shot from mortars and when the chemicals inside the shells ignite they explode, producing the brilliant bursts we see in the night sky. Shell size determines how high a shell will travel before exploding and how big its burst will be when it does explode. Large shell sizes go higher and produce larger bursts than small shell sizes. Pyrotechnicians take these factors into account when designing the shows so that they can determine the size of the safe zone for spectators and so that shows can be synchronized with music. At a fireworks show, a 3 -in. shell is shot from a mortar at an angle of \(75^{\circ} .\) The height, \(y\) (in feet), of the shell \(t\) sec after being shot from the mortar is given by the quadratic equation $$y=-16 t^{2}+144 t$$ and the horizontal distance of the shell from the mortar, \(x\) (in feet), is given by the linear equation $$x=39 t$$ a) How high is the shell after 3 sec? b) What is the shell's horizontal distance from the mortar after 3 sec? c) The maximum height is reached when the shell explodes. How high is the shell when it bursts after 4.5 sec? d) What is the shell's horizontal distance from its launching point when it explodes? (Round to the nearest foot.) When a 10 -in. shell is shot from a mortar at an angle of \(75^{\circ},\) the height, \(y\) (in feet), of the shell \(t\) sec after being shot from the mortar is given by $$y=-16 t^{2}+264 t$$and the horizontal distance of the shell from the mortar, \(x\) (in feet), is given by$$x=71 t$$ e) How high is the shell after 3 sec? f) Find the shell's horizontal distance from the mortar after 3 sec. g) The shell explodes after 8.25 sec. What is its height when it bursts? h) What is the shell's horizontal distance from its launching point when it explodes? (Round to the nearest foot.) i) Compare your answers to a) and e). What is the difference in their heights after 3 sec? j) Compare your answers to c) and g.). What is the difference in the shells' heights when they burst? k) Assuming that the technicians timed the firings of the 3-in. shell and the 10 -in. shell so that they exploded at the same time, how far apart would their respective mortars need to be so that the 10 -in. shell would burst directly above the 3 -in. shell?

Factor completely. $$n^{3}+125$$

Find the indicated values for the following polynomial functions. \(f(x)=x^{2}+10 x+21 .\) Find \(x\) so that $f(x)=0$$

Factor completely. $$144 m^{2}-n^{4}$$

A rock is dropped from a cliff and into the ocean. The height \(h\) (in feet) of the rock after \(t\) sec is given by \(h=-16 t^{2}+144\)

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.