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Factor by grouping. Find the polynomial which factors to \((3 x-8)(x+2)\)

Short Answer

Expert verified
The polynomial which factors to \((3x-8)(x+2)\) is \(3x^2 - 2x - 16\).

Step by step solution

01

Expand the expression using the distributive property

In this step, we will multiply each term of the first expression by each term of the second expression using the distributive property. \((3x-8)(x+2) = 3x \cdot (x+2) - 8 \cdot (x+2)\)
02

Multiply each term in the expressions individually

Now, we will multiply each term in the expressions: \(3x(x+2) = 3x^2 + 6x\) \(-8(x+2) = -8x -16\)
03

Combine the results of the multiplication

Now that we have the products of each term, we can combine them to get the polynomial: \(3x^2 + 6x - 8x - 16\)
04

Simplify the polynomial

Combine like terms to get the simplified polynomial: \(3x^2 - 2x - 16\) So, the polynomial which factors to \((3x-8)(x+2)\) is \(3x^2 - 2x - 16\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Distributive Property
The distributive property is like a shopping at a market where you wish to distribute your purchases equally. This property allows us to expand an expression by distributing each term of one factor to each term in another factor. It's why we call it a property of distribution.
In math, to use the distributive property, we multiply each term in one set of parentheses by every term in another set of parentheses. This is expressed mathematically as:
  • If you have an expression: \((a+b)(c+d)\), the expansion involves: \(a(c+d) + b(c+d)\).
In this way, every term in the first group is combined with every term in the second group. It’s an essential property that lays the foundation for polynomial expansion, as seen in the given step-by-step solution.
In our example, we distribute:
  • \(3x\) across \((x+2)\)
  • \(-8\) across \((x+2)\).
This method enables the transformation of the expression \((3x-8)(x+2)\) into expanded terms that can be further simplified.
Polynomial Expansion
Polynomial expansion is like opening up a packed suitcase. Each item inside needs to be laid out so you can see everything clearly. Here, once we apply the distributive property, we multiply terms and express the result as a single polynomial.
The transformation from a product to a sum or difference of terms is called polynomial expansion. It involves taking the originally compact form of an expression and writing it as a series of separate terms.
  • For instance, from the original product \((3x-8)(x+2)\), the expansion walks us through individual multiplications like \(3x \cdot x, 3x \cdot 2, -8 \cdot x\), and \(-8 \cdot 2\).
Each result from this multiplication becomes its own term in a polynomial. This is how we get \(3x^2 + 6x - 8x - 16\) from our example. These new terms combine to form an expanded version of the earlier product, expressed as a polynomial, clearly showing each part.
Combining Like Terms
After expanding a polynomial, the equation may look "cluttered" because of similar terms. Combining like terms is akin to grouping similar items together.
When we say "like terms," we refer to terms that have the same variables raised to the same power. Only coefficients can differ. This simplification step keeps our mathematical work neat and concise.
  • For example, in the expression \(3x^2 + 6x - 8x - 16\), the terms \(6x\) and \(-8x\) are like terms with the variable \(x\).
  • Similarly, constant terms or plain numbers are also considered like terms in expressions such as \(3 + 4\).
By combining \(6x\) and \(-8x\), we simplify this polynomial to \(3x^2 - 2x - 16\). It's more concise and easier to understand. This simplification is crucial in reducing errors and can make further operations clearer and simpler.

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Organizers of fireworks shows use quadratic and linear equations to help them design their programs. Shells contain the chemicals which produce the bursts we see in the sky. At a fireworks show the shells are shot from mortars and when the chemicals inside the shells ignite they explode, producing the brilliant bursts we see in the night sky. Shell size determines how high a shell will travel before exploding and how big its burst will be when it does explode. Large shell sizes go higher and produce larger bursts than small shell sizes. Pyrotechnicians take these factors into account when designing the shows so that they can determine the size of the safe zone for spectators and so that shows can be synchronized with music. At a fireworks show, a 3 -in. shell is shot from a mortar at an angle of \(75^{\circ} .\) The height, \(y\) (in feet), of the shell \(t\) sec after being shot from the mortar is given by the quadratic equation $$y=-16 t^{2}+144 t$$ and the horizontal distance of the shell from the mortar, \(x\) (in feet), is given by the linear equation $$x=39 t$$ a) How high is the shell after 3 sec? b) What is the shell's horizontal distance from the mortar after 3 sec? c) The maximum height is reached when the shell explodes. How high is the shell when it bursts after 4.5 sec? d) What is the shell's horizontal distance from its launching point when it explodes? (Round to the nearest foot.) When a 10 -in. shell is shot from a mortar at an angle of \(75^{\circ},\) the height, \(y\) (in feet), of the shell \(t\) sec after being shot from the mortar is given by $$y=-16 t^{2}+264 t$$and the horizontal distance of the shell from the mortar, \(x\) (in feet), is given by$$x=71 t$$ e) How high is the shell after 3 sec? f) Find the shell's horizontal distance from the mortar after 3 sec. g) The shell explodes after 8.25 sec. What is its height when it bursts? h) What is the shell's horizontal distance from its launching point when it explodes? (Round to the nearest foot.) i) Compare your answers to a) and e). What is the difference in their heights after 3 sec? j) Compare your answers to c) and g.). What is the difference in the shells' heights when they burst? k) Assuming that the technicians timed the firings of the 3-in. shell and the 10 -in. shell so that they exploded at the same time, how far apart would their respective mortars need to be so that the 10 -in. shell would burst directly above the 3 -in. shell?

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