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Write an equation of the line perpendicular to the given line and containing the given point. Write the answer in slopeintercept form or in standard form, as indicated. $$-2 x+3 y=15 ;(-5,7) ; \text { standard form }$$

Short Answer

Expert verified
The equation of the line perpendicular to \(-2x + 3y = 15\) and containing the point \((-5, 7)\) is given in standard form as: \[\boxed{3x + 2y = -1}\]

Step by step solution

01

Find the slope of the given line

To find the slope of the given line, we can rewrite the line in the slope-intercept form (y = mx + b), where m is the slope, and b is the y-intercept. The given line is -2x + 3y = 15. To rewrite it in the slope-intercept form, we need to isolate y: \(3y = 2x + 15\) \(y = \frac{2}{3}x + 5\) Now, we can read off the slope of the given line, m, which is \(\frac{2}{3}\).
02

Find the slope of the perpendicular line

To find the slope of a line perpendicular to the given line, we will use the fact that the slopes of perpendicular lines are negative reciprocals of each other. Since the given line has a slope of \(\frac{2}{3}\), the slope of the perpendicular line, m_perp, will be: \(m_{\text{perp}} = -\frac{3}{2}\)
03

Write the equation of the perpendicular line in point-slope form

To write the equation of the perpendicular line in point-slope form, we will use the formula \(y - y_1 = m(x - x_1)\), where m is the slope and (x_1, y_1) is the given point. Our slope is -3/2 and the given point is (-5, 7), so we have: \(y - 7 = -\frac{3}{2}(x + 5)\)
04

Rewrite the equation in the standard form

Now, let's rewrite the equation of the perpendicular line in the standard form. First, we will clear the fraction by multiplying both sides by 2: \(2(y - 7) = -3(x + 5)\) Now, we will distribute and rearrange the equation: \(2y - 14 = -3x -15\) Add 14 and 3x to both sides: \(3x + 2y = -1\) So, the equation of the line perpendicular to -2x + 3y = 15 and containing the point (-5, 7) is given in standard form as: \(\boxed{3x + 2y = -1}\)

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Slope-Intercept Form
Slope-intercept form is a very popular way to write the equation of a line because it gives us clear information about the line's slope and where it crosses the y-axis. The general formula looks like this: \( y = mx + b \). Here, \( m \) represents the slope of the line, and \( b \) is the y-intercept – the point where the line crosses the y-axis.

To convert any linear equation into this format, you need to solve for \( y \). For instance, given the equation \(-2x + 3y = 15\), you first isolate \( y \):
  • Add \(2x\) to both sides to get \(3y = 2x + 15\).
  • Then divide each side by \(3\) to get \(y = \frac{2}{3}x + 5\).
This equation is now in slope-intercept form with a slope of \(\frac{2}{3}\) and a y-intercept of \(5\).

This form is useful for quickly identifying how a line behaves, making it easier to predict changes and understand its relationship with other lines.
Standard Form
Standard form is another way of writing the equation of a line, and it has a specific structure: \( Ax + By = C \), where \( A \), \( B \), and \( C \) are integers, and \( A \) should be a non-negative value.

Standard form is particularly useful in some mathematical situations such as solving simultaneous equations or identifying x- and y-intercepts quickly. For the equation \(3x + 2y = -1\), we observe:
  • \( A = 3 \)
  • \( B = 2 \)
  • \( C = -1 \)
Here, by setting \( x = 0 \), you can directly find the y-intercept, and vice versa for the x-intercept, which can be helpful in graphing.

Converting from slope-intercept form to standard form requires rearranging the terms and ensuring you have no fractions and that the coefficient of \( x \) is positive.
Negative Reciprocals
When two lines are perpendicular, their slopes are negative reciprocals of each other. This means if you have the slope of one line, you can find the slope of a line perpendicular to it by flipping the fraction and changing the sign. For instance, if a line has a slope of \(\frac{2}{3}\), then the perpendicular line’s slope will be \(-\frac{3}{2}\).

This relationship helps in determining the orientation of lines relative to each other, a crucial aspect when solving geometric problems or understanding the structure of graphs. Here’s a quick way to calculate it:
  • Take your initial slope, for example, \( \frac{a}{b} \).
  • Flip the fraction to become \( \frac{b}{a} \).
  • Change the sign, turning \( \frac{b}{a} \) to \(-\frac{b}{a} \).
This method ensures the two lines are perpendicular to each other, a unique property that maintains a 90-degree angle between them. Thus, recognizing negative reciprocals is a key mathematical skill when dealing with perpendicular lines.

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