Chapter 4: Problem 41
Graph each function using the slope and \(y\) -intercept. $$g(x)=2 x+\frac{1}{2}$$
Short Answer
Expert verified
The slope of the given function is \(m=2\) and the y-intercept is \(b=\frac{1}{2}\). Plot the y-intercept (0, \(\frac{1}{2}\)) and use the slope to find another point (1, \(\frac{5}{2}\)). Connect these points with a line to graph the function \(g(x) = 2x + \frac{1}{2}\).
Step by step solution
01
Identify slope and y-intercept
The given function is \(g(x) = 2x + \frac{1}{2}\). We can notice it's already in slope-intercept form: \(g(x) = mx + b\). Comparing the given function to this form, we find that the slope is \(m=2\) and the y-intercept is \(b = \frac{1}{2}\).
02
Plot the y-intercept
Now that we know the y-intercept is \(\frac{1}{2}\), plot a point at (0, \(\frac{1}{2}\)) on the y-axis. This represents the point where the function intersects the y-axis.
03
Use slope to plot another point
The slope 2 can be represented as a fraction \(\frac{2}{1}\), which means that for every 1 unit moved to the right on the x-axis, we move 2 units up on the y-axis. Starting from the y-intercept (0, \(\frac{1}{2}\)), move 1 unit to the right and 2 units up. This brings us to the point (1, \(\frac{5}{2}\)). Plot this point on the graph.
04
Draw a line through the points
Connect the two points (0, \(\frac{1}{2}\)) and (1, \(\frac{5}{2}\)) with a straight line. This line represents the graph of the function \(g(x) = 2x + \frac{1}{2}\).
Unlock Step-by-Step Solutions & Ace Your Exams!
-
Full Textbook Solutions
Get detailed explanations and key concepts
-
Unlimited Al creation
Al flashcards, explanations, exams and more...
-
Ads-free access
To over 500 millions flashcards
-
Money-back guarantee
We refund you if you fail your exam.
Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Slope-Intercept Form
The slope-intercept form is a way of writing the equation of a straight line. This form is super handy because it allows you to see immediately both the slope of the line and where it crosses the y-axis.
The general format is \( y = mx + b \), where:
Understanding the slope-intercept form helps you quickly figure out the key parts of the line without needing to rearrange or solve anything.
The general format is \( y = mx + b \), where:
- \( m \) is the slope, which tells us how slanted the line is.
- \( b \) is the y-intercept, showing the point where the line crosses the y-axis.
Understanding the slope-intercept form helps you quickly figure out the key parts of the line without needing to rearrange or solve anything.
Slope of a Line
The slope of a line is all about how steep or flat the line is. It helps us know how much the line rises or falls as it moves across a graph. If we have a slope of \( m \) in the equation \( y = mx + b \), this tells us that for each step we move on the x-axis, the line will rise or fall by \( m \) units.
For example, in our function \( g(x) = 2x + \frac{1}{2} \), the slope \( m \) is 2. This means for every 1 unit we go to the right on the x-axis, the line goes up 2 units on the y-axis.
Knowing the slope is crucial because:
For example, in our function \( g(x) = 2x + \frac{1}{2} \), the slope \( m \) is 2. This means for every 1 unit we go to the right on the x-axis, the line goes up 2 units on the y-axis.
Knowing the slope is crucial because:
- A positive slope means the line goes up as it moves right.
- A negative slope would make the line go down as it moves right.
- A zero slope means the line is completely flat and horizontal.
Y-Intercept
The y-intercept is the point where the line crosses the y-axis on a graph. This spot is where the x-value is zero, making it an extremely useful point to start plotting your graph.
In the slope-intercept form of \( y = mx + b \), the y-intercept is represented by \( b \). For our function \( g(x) = 2x + \frac{1}{2} \), the y-intercept is \( \frac{1}{2} \). This means the graph will touch the y-axis at the point \( (0, \frac{1}{2}) \).
This point is crucial because:
In the slope-intercept form of \( y = mx + b \), the y-intercept is represented by \( b \). For our function \( g(x) = 2x + \frac{1}{2} \), the y-intercept is \( \frac{1}{2} \). This means the graph will touch the y-axis at the point \( (0, \frac{1}{2}) \).
This point is crucial because:
- It gives a solid starting point to begin drawing the line.
- It helps confirm the accuracy of your graphing as the first plotted point.
- It ensures you understand one primary feature of the line, even before graphing completely.
Plotting Points
Plotting points is the essential skill needed to graph a line accurately, and it ensures you have a precise visual representation of a function.
Start by plotting the y-intercept, which is your first guaranteed point. For \( g(x) = 2x + \frac{1}{2} \), the y-intercept is \( (0, \frac{1}{2}) \). Make sure you accurately mark this on the y-axis.
Next, use the slope to find another point. From the y-intercept, use the slope as a guide: with a slope of \( 2 \), move 1 unit right on the x-axis, and 2 units up on the y-axis, landing at the new point \( (1, \frac{5}{2}) \). Plot this point as well.
The final step is to connect these points with a straight line.
Here's why plotting points is vital:
Start by plotting the y-intercept, which is your first guaranteed point. For \( g(x) = 2x + \frac{1}{2} \), the y-intercept is \( (0, \frac{1}{2}) \). Make sure you accurately mark this on the y-axis.
Next, use the slope to find another point. From the y-intercept, use the slope as a guide: with a slope of \( 2 \), move 1 unit right on the x-axis, and 2 units up on the y-axis, landing at the new point \( (1, \frac{5}{2}) \). Plot this point as well.
The final step is to connect these points with a straight line.
Here's why plotting points is vital:
- It allows for accuracy in drawing the entire graph.
- It gives you a clear picture of how the function behaves.
- It helps make sense of additional changes or shifts in the graph.