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Write an equation of the line perpendicular to the given line and containing the given point. Write the answer in slope-intercept form or in standard form, as indicated. $$y=\frac{2}{3} x+4 ;(6,-3) ; \text { slope-intercept form }$$

Short Answer

Expert verified
The equation of the line perpendicular to the given line and containing the point \((6, -3)\), written in the slope-intercept form, is \(y = -\frac{3}{2}x + 6\).

Step by step solution

01

Find the slope of the given line

We have the given line equation in the slope-intercept form, which is: \(y = mx + c\), where \(m\) is the slope and \(c\) is the y-intercept. In our case, the given line is: \(y = \frac{2}{3}x + 4\), so the slope is \(m = \frac{2}{3}\).
02

Calculate the negative reciprocal of the slope

If two lines are perpendicular, their slopes are negative reciprocals of each other, i.e. \(m_1m_2 = -1\). In our case, we have the slope of the given line as \(m_1 = \frac{2}{3}\). Let's find the negative reciprocal for this slope: \(m_2 = -\frac{1}{m_1} = -\frac{1}{\frac{2}{3}} = -\frac{3}{2}\)
03

Use the point-slope form to write the equation of the perpendicular line

Now, we have the slope of the perpendicular line and a point it goes through \((6, -3)\). Let's use the point-slope form, which is: \(y - y_1 = m_2(x - x_1)\), where \((x_1, y_1) = (6, -3)\) and \(m_2 = -\frac{3}{2}\). Plug in the values and we get: \(y - (-3) = -\frac{3}{2}(x - 6)\)
04

Transform the obtained equation into the slope-intercept form

Finally, let's rewrite the equation in the slope-intercept form by solving for \(y\): \[ \begin{aligned} y + 3 &= -\frac{3}{2}(x - 6) \\ y + 3 &= -\frac{3}{2}x + 9 \\ y &= -\frac{3}{2}x + 6 \end{aligned} \] Hence, the equation of the line perpendicular to the given line and containing the point \((6, -3)\), written in the slope-intercept form, is \(y = -\frac{3}{2}x + 6\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Slope-Intercept Form
In mathematics, the slope-intercept form of a linear equation is one of the most common ways to represent a line. It is written as:
\[ y = mx + c \]where:
  • \(m\) represents the slope of the line.
  • \(c\) is the y-intercept, which is the point where the line crosses the y-axis.
This form of the equation is particularly useful because it quickly provides two key pieces of information about the line: its slope and its y-intercept.
An important aspect of the slope \(m\) is that it indicates the steepness and the direction of the line. If \(m\) is positive, the line ascends; if negative, it descends. The y-intercept \(c\) is easy to spot in this form, which makes it straightforward to graph the line with these clear parameters.
The slope-intercept form is very handy when you need to express a linear relationship and is frequently used in various fields, including physics, economics, and statistics.
Negative Reciprocal
In geometry, two lines are defined as perpendicular if they intersect at a 90-degree angle. A fascinating property of perpendicular lines is related to their slopes. The slopes of perpendicular lines are negative reciprocals of each other. This means, if one line has a slope \(m\), the perpendicular line will have a slope \( -\frac{1}{m} \).
This concept is crucial when solving problems involving perpendicular lines. It helps in finding the equation of a line that is perpendicular to a given line when you know the slope of the original line. For instance, if a line has a slope of \(\frac{2}{3}\), the slope of a line perpendicular to it will be \(-\frac{3}{2}\).
This relationship comes from the fact that multiplying the slope of one line by the slope of the perpendicular line gives \(-1\). Thus, knowing how to find the negative reciprocal can be incredibly helpful in determining the characteristics of lines and solving coordinate geometry problems.
Point-Slope Form
The point-slope form is another way to express the equation of a line. It is especially useful when you know the slope of the line and one of its points. The point-slope form is expressed as:
\[ y - y_1 = m(x - x_1) \]where:
  • \((x_1, y_1)\) is a specific point on the line.
  • \(m\) is the slope of the line.
This form allows you to quickly plug in the slope and the coordinates of a point to find the equation of the line.
For example, when finding the equation of a line that is perpendicular to another line, you might start by determining the new line's slope using the negative reciprocal method and then use the point-slope form with a known point.
Once you have the equation in point-slope form, it can be converted into the slope-intercept form. This versatility makes the point-slope form a powerful tool for analyzing and constructing linear equations. It highlights how a line can be described based on movement from a known point along the slope, providing clarity in a visual and analytical geometry context.

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