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Chapter 3: Problem 51

Solve for \(d\). a) \(8 d-7=17\) b) \(k d-a=z\)

Short Answer

Expert verified
a) \(d = 3\) b) \(d = \frac{(z + a)}{k}\)

Step by step solution

01

Solve the first equation

To solve the first equation, we need to isolate the variable \(d\). We do this by first adding \(7\) to both sides of the equation: \(8d - 7 + 7 = 17 + 7\) which simplifies to: \(8d = 24\) Now, we need to divide both sides of the equation by \(8\): \(d = \frac{24}{8}\) Simplifying the fraction, we get: \(d = 3\) So, the solution for the first equation is \(d = 3\).
02

Solve the second equation

To solve the second equation, we need to isolate the variable \(d\). We do this by first adding \(a\) to both sides of the equation: \(kd - a + a = z + a\) which simplifies to: \(kd = z + a\) Now, we need to divide both sides of the equation by \(k\): \(d = \frac{(z + a)}{k}\) Thus, the solution for the second equation is \(d = \frac{(z + a)}{k}\).

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