/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 68 The number of bacteria in a cult... [FREE SOLUTION] | 91影视

91影视

Log out

Learning Materials

Features

Discover

Chapter 15: Problem 68

The number of bacteria in a culture doubles every day. If a culture begins with 1000 bacteria, how many bacteria are present after 7 days?

Short Answer

Expert verified
There are 128,000 bacteria in the culture after 7 days.

Step by step solution

01

Understand the exponential growth formula

In problems involving exponential growth, we can use the formula \(N = N_0 * 2^t\), where \(N\) is the final number of bacteria, \(N_0\) is the initial number of bacteria, and \(t\) is the time (in days, in this case). Since we have all the values except for \(N\), it is a plug and chug problem.
02

Identify the given values

In this case, we are given the initial number of bacteria, \(N_0 = 1000\), and the number of days, \(t = 7\).
03

Substitute the given values into the formula

Substitute the given values for \(N_0\) and \(t\) in the formula: \(N = 1000 * 2^7\)
04

Calculate the result

Now, calculate the value of \(N\): \(N = 1000 * 2^7 = 1000 * 128\) \(N = 128000\) Finally, there are 128,000 bacteria in the culture after 7 days.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Use the formula for \(S_{n}\) to find the sum of the terms of each geometric sequence. $$\sum_{i=1}^{8} 5(2)^{i}$$

Find the indicated term of each binomial expansion. $$\left(2 y^{2}+z\right)^{10} ; \text { eighth term }$$

Evaluate each binomial coefficient. $$\left(\begin{array}{l}4 \\\2\end{array}\right)$$

Use the binomial theorem to expand each expression. $$(h+4)^{4}$$

Use the binomial theorem to expand each expression. $$\left(w^{3}+2\right)^{3}$$
See all solutions

Recommended explanations on Math Textbooks

Discrete Mathematics

Read Explanation

Logic and Functions

Read Explanation

Mechanics Maths

Read Explanation

Probability and Statistics

Read Explanation

Statistics

Read Explanation

Decision Maths

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.