Chapter 14: Problem 77
a) Find the vertex. b) Find the axis of symmetry. c) Determine whether there is a maximum or minimum value and find that value. $$g(x)=x^{2}-6$$
Short Answer
Expert verified
a) Vertex: (0, -6)
b) Axis of symmetry: x = 0
c) Minimum value: -6
Step by step solution
01
Find the vertex
For a quadratic function given by \(g(x) = ax^2+bx+c\), the vertex can be found using the formula: \[h = \frac{-b}{2a}, k=g(h)=ah^{2}+bh+c\]
In our given function, \(g(x) = x^2 - 6\), we have \(a = 1, b = 0\) and \(c = -6\).
Let's find the vertex coordinates (h, k):
\[h = \frac{-0}{2(1)} = 0\]
\[k = g(0) = (1)(0)^2 + 0(0) - 6 = -6\]
Thus, the vertex is at point \((0, -6)\).
02
Find the axis of symmetry
The axis of symmetry is a vertical line that passes through the vertex of the parabola. The equation of a vertical line is of the form \(x = h\), where \(h\) is the x-coordinate of the vertex.
From step 1, we found the vertex to be \((0, -6)\). Therefore, the axis of symmetry is \(x = 0\).
03
Determine if there is a maximum or minimum value and find that value
To determine if there's a maximum or minimum value, we need to look at the coefficient of the x^2 term in the function. If \(a > 0\), the parabola opens upwards, which means it has a minimum value. If \(a < 0\), the parabola opens downwards, which implies it has a maximum value.
In our given function, \(g(x) = x^2 - 6\), \(a = 1\), which is greater than 0. This means the parabola opens upwards and has a minimum value. This minimum value is the y-coordinate of the vertex, which is \(k = -6\).
In conclusion:
a) The vertex is at point \((0, -6)\).
b) The axis of symmetry is the line \(x = 0\).
c) The function has a minimum value of -6.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Vertex of a Parabola
The vertex of a parabola is a key point on its graph, representing the minimum or maximum value of a quadratic function. For any quadratic function of the form
For example, consider the function \( g(x) = x^2 - 6 \). In this case, \( a = 1, b = 0, \) and \( c = -6 \). Calculating the vertex:
The vertex not only indicates the lowest (or highest) point of the parabola depending on its orientation, but also plays a crucial role in understanding the parabola's shape and direction.
- \( g(x) = ax^2 + bx + c \),
- \( h = \frac{-b}{2a} \)
- \( k = g(h) = ah^2 + bh + c \).
For example, consider the function \( g(x) = x^2 - 6 \). In this case, \( a = 1, b = 0, \) and \( c = -6 \). Calculating the vertex:
- \( h = \frac{-0}{2(1)} = 0 \)
- \( k = g(0) = (1)(0)^2 + 0(0) - 6 = -6 \)
The vertex not only indicates the lowest (or highest) point of the parabola depending on its orientation, but also plays a crucial role in understanding the parabola's shape and direction.
Axis of Symmetry
The axis of symmetry in a quadratic function is a vertical line that passes through the vertex and divides the parabola into two mirror-image halves. For the general quadratic equation \( g(x) = ax^2 + bx + c \), the axis of symmetry can be identified by the formula:
For example, given the function \( g(x) = x^2 - 6 \), the vertex has an x-coordinate \( h = 0 \), making the axis of symmetry the line:
- \( x = h = \frac{-b}{2a} \)
For example, given the function \( g(x) = x^2 - 6 \), the vertex has an x-coordinate \( h = 0 \), making the axis of symmetry the line:
- \( x = 0 \)
Maximum and Minimum Values of Quadratic Functions
In quadratic functions, recognizing whether there is a maximum or minimum value is important for understanding the function's behavior. This is determined by examining the coefficient \( a \) in the standard quadratic form \( g(x) = ax^2 + bx + c \):
In the case of \( g(x) = x^2 - 6 \), with \( a = 1 \), the parabola opens upwards, meaning it has a minimum value. This minimum value occurs at the vertex \((0, -6)\), with \( k = -6 \) being the lowest point on the graph. Such evaluations of maximum or minimum values are valuable, especially when analyzing real-world scenarios modeled by quadratic equations, such as projectile motion or optimization problems.
- If \( a > 0 \), the parabola opens upwards and has a minimum value.
- If \( a < 0 \), the parabola opens downwards and has a maximum value.
In the case of \( g(x) = x^2 - 6 \), with \( a = 1 \), the parabola opens upwards, meaning it has a minimum value. This minimum value occurs at the vertex \((0, -6)\), with \( k = -6 \) being the lowest point on the graph. Such evaluations of maximum or minimum values are valuable, especially when analyzing real-world scenarios modeled by quadratic equations, such as projectile motion or optimization problems.