Chapter 9: Problem 63
Graph. $$f(x)=x^{2}+2 x-3$$
Short Answer
Expert verified
The vertex of the parabola is (-1,-4), the function opens upwards, it intersects the x-axis at \(x = 1\) and \(x = -3\), and the y-intercept is at the point (0,-3).
Step by step solution
01
Identify Coefficients and Constant Term
In the given function \(f(x) = x^2 + 2x - 3\), we identify the coefficients for \(x^2\) and \(x\), and the constant term. We have \(a = 1\), \(b = 2\), and \(c = -3\).
02
Compute the Vertex of the Parabola
The vertex of the parabola, given the quadratic function in the form \(f(x) = ax^2 + bx + c\), can be found using the formula \(-b/(2a)\) for the x-value of the vertex, and plugging this x-value back into the function to find the y-value. In this case, the x-value of the vertex is \(-2/(2*1) = -1\). Plugging this back into the function, we find that the y-coordinate of the vertex is \((-1)^2 + 2*(-1) - 3 = -4\). So, the vertex of the parabola is \((-1,-4)\).
03
Determine Direction of Opening
The coefficient of the \(x^2\) term determines whether the parabola opens upwards or downwards. If \(a > 0\), the parabola opens upwards; if \(a < 0\), the parabola opens downwards. In this case, \(a = 1\), so the parabola opens upwards.
04
Find the Roots and Y-Intercept
The roots of the equation can be found by setting the equation equal to zero and solving for \(x\). Doing this, we get \(x^2 + 2x - 3 = 0\). Solving this quadratic equation through factoring gives us \((x - 1)(x + 3) = 0\). This gives two solutions: \(x = 1\) and \(x = -3\). The y-intercept is found by calculating the function value at \(x = 0\). Substituting \(x = 0\) into the function gives us \(0^2 + 2*0 - 3 = -3\). so the y-intercept is at (0, -3).
05
Draw the Graph
We now have all the necessary information to sketch the graph. We have the vertex at (-1, -4), the graph opens upwards, and it crosses the x-axis at \(x = 1\) and \(x = -3\), and the y-axis at (0, -3). We can now graph the equation of this function on a coordinate plane.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Vertex of a Parabola
The vertex of a parabola is a critical concept for understanding its graph. It is the highest or lowest point on the curve, depending on the direction of the opening. For a quadratic function of the form\( f(x) = ax^2 + bx + c \), the x-coordinate of the vertex can be found using \( x = -\frac{b}{2a} \). Once we have the x-value, we substitute it back into the function to find the y-coordinate.In the example \( f(x) = x^2 + 2x - 3 \), using \( a = 1 \) and \( b = 2 \), we calculate the vertex's x-coordinate as \( -\frac{2}{2(1)} = -1 \). Substituting \( -1 \) into the function gives us the y-coordinate: \( (-1)^2 + 2(-1) - 3 = -4 \). Therefore, the vertex is at \( (-1, -4) \).It's helpful for students to note that the vertex is a point of symmetry for the parabola. If you're graphing quadratic functions by hand, finding the vertex is a great starting point as it provides a reference around which the rest of the parabola is shaped.
Quadratic Roots
The roots of a quadratic function, also known as the zeroes or x-intercepts, are the values of \(x\) where the function equals zero. To find the roots of the function \(f(x) = ax^2 + bx + c\), we set the function equal to zero and solve the resulting equation.
Factoring to Find Roots
In the example \(x^2 + 2x - 3\), we see that factoring the quadratic yields \((x + 3)(x - 1) = 0\). This gives us two roots: \(x = -3\) and \(x = 1\). These roots represent the points where the parabola crosses the x-axis.- If a quadratic function has real roots, the parabola will intersect the x-axis at those points.
- If the roots are complex (not real), the parabola does not cross the x-axis.
Direction of Parabola Opening
The direction a parabola opens—upward or downward—is determined by the sign of the coefficient of the \(x^2\) term in the quadratic function \(f(x) = ax^2 + bx + c\). Here’s an easy rule for students to remember:
- If \(a > 0\), the parabola opens upward.
- If \(a < 0\), the parabola opens downward.