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Determine whether the ordered pair is a solution of the given system. (OBJECTIVE 1 ) $$\left(2, \frac{1}{3}\right),\left\\{\begin{array}{c} x-3 y=1 \\ -2 x+6 y=-6 \end{array}\right.$$

Short Answer

Expert verified
No, the ordered pair \((2, \frac{1}{3})\) is not a solution to the given system of equations.

Step by step solution

01

Substitute into Equation 1

The first step is to substitute the values for x and y from the ordered pair into the first equation. Substituting \(x=2\) and \(y=\frac{1}{3}\) into the first equation \(x-3y=1\) gives \(2 - 3(\frac{1}{3})\) which simplifies to \(2 - 1 =1\). Because the right side is equal to the left side, this shows that the ordered pair satisfies the first equation.
02

Substitute into Equation 2

Substitute the values for x and y from the ordered pair into the second equation. Substituting \(x=2\) and \(y=\frac{1}{3}\) into the second equation \(-2x+6y=-6\) gives \(-2(2) + 6(\frac{1}{3})\), which simplifies to \(-4 + 2 = -2\). Because the right side is not equal to the left side, this shows that the ordered pair does not satisfy the second equation.
03

Evaluate the Results

From the results in the previous steps, the given ordered pair \(2, \frac{1}{3}\) is not a solution to the system of equations. To be a solution, the ordered pair needs to satisfy or make true both equations in the system. But in this case, the ordered pair only satisfies the first equation but fails to satisfy the second.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Ordered Pairs
In algebra, an ordered pair is a pair of numbers used to locate a point on a coordinate plane or to provide a solution to a system of equations. An ordered pair is always written in the form \( (x, y) \) where \( x \) is the first element, representing the horizontal position, and \( y \) is the second element, representing the vertical position.

Understanding ordered pairs is crucial when working with systems of equations because each equation represents a line on a graph, and where those lines intersect is the ordered pair \( (x, y) \) that is the solution to the system. When we say an ordered pair 'satisfies' an equation, we mean when we substitute \( x \) and \( y \) into the equation, the equation holds true. If the pair does not satisfy an equation, it means the equation is not true when \( x \) and \( y \) are substituted in. It's important to check the ordered pair against all equations in the system to determine if it is indeed the solution.
Substitution Method
The substitution method is one of the fundamental techniques used to solve systems of equations. This method involves rearranging one of the equations to solve for one variable in terms of the others, and then 'substituting' this expression into another equation.

For example, if we have an equation like \( x = 2y + 3 \) and we need to solve a system, we can use the expression \( 2y + 3 \) in place of \( x \) in other equations of the system. This can often simplify the process by reducing the system to one equation with one variable, which can then be solved directly.

Using the substitution method can sometimes be more straightforward than other methods, such as elimination, especially when the equation can be easily rearranged to isolate one variable. However, it's essential to perform substitutions correctly and to carry through any arithmetic carefully to ensure the correct solution is found.
Algebraic Reasoning
Algebraic reasoning refers to the process of forming, manipulating, and relating algebraic expressions in order to solve problems. It involves recognizing patterns, understanding the properties of numbers and operations, and applying logical thinking to arrive at a solution.

When we apply algebraic reasoning to systems of equations, we look at how changes in one variable affect another. For instance, when we substitute variables, as in the substitution method, we rely on our understanding of algebraic relationships to manipulate the equations. We also use reasoning when we determine whether an ordered pair is a solution to the system, as we need to consider if the pair meets all the requirements set by the equations.

Algebraic reasoning enables us to work through complex problems systematically and is thus a key tool in mathematics. Developing proficiency in algebraic reasoning not only helps in solving equations but also in many other areas of math and science.

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Most popular questions from this chapter

The number of canoes sold at a marina depends on price. As the price gets higher, fewer canoes will be sold. The equation that relates the price of a canoe to the number sold is called a demand equation. Suppose that the demand equation for canoes is $$ p=-\frac{1}{2} q+1,300 $$ where \(p\) is the price and \(q\) is the number sold at that price. The number of canoes produced also depends on price. As the price gets higher, more canoes will be manufactured. The equation that relates the number of canoes produced to the price is called a supply equation. Suppose that the supply equation for canoes is $$ p=\frac{1}{3} q+\frac{1,400}{3} $$ where \(p\) is the price and \(q\) is the number produced at that price. The equilibrium price is the price at which supply equals demand. Find the equilibrium price.

Graph the solution. $$\left\\{\begin{array}{l}2 x-y<4 \\\x+y \geq-1\end{array}\right.$$

Use two equations in two variables to solve each application. An investment of \(\$ 950\) at one rate of interest and \(\$ 1,200\) at a higher rate together generate an annual income of \(888.50 .\) If the investment rates differ by \(2 \% .\) find the lower rate.

Determine whether each ordered pair is a solution of the given inequality. SEE EXAMPLE 1. (OBJECTIVE 1) Determine whether each ordered pair is a solution of \(x+y>4\) a. (0,4) b. (1,5) c. \(\left(-1, \frac{1}{2}\right)\) d. \(\left(-\frac{3}{4}, 7\right)\)

Use two equations in two variables to solve each application. One catcher's mitt and ten outfielder's gloves cost $$ 239.50 .\( How much does each cost if one catcher's mitt and five outfielder's gloves cost $$ 134.50 ?\)

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