/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 53 Write the slope-intercept equati... [FREE SOLUTION] | 91Ó°ÊÓ

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Write the slope-intercept equation of the line that passes through the given point and is perpendicular to the given line. $$(2,5), 4 x-y=7$$

Short Answer

Expert verified
The slope-intercept form of the line perpendicular to the given line ([4x - y = 7]) that passes through the point (2, 5) is \(y = -1/4x + 5.5\).

Step by step solution

01

Find the Slope of the Given Line

First, rearrange the equation of the given line into the slope-intercept form, 'y = mx + c'. This gives 'y = 4x - 7'. The coefficient of 'x' is the slope of the given line, so the slope 'm' is 4.
02

Determine the Perpendicular Slope

The slope of the line perpendicular to the given line is the negative reciprocal of its slope. Therefore, if the slope of the given line is 4, the slope of the line that is perpendicular to it is -1/4.
03

Apply the Point-Slope Form

Use the point-slope form \(y - y1 = m(x - x1)\) with the point (2,5) and the perpendicular slope -1/4. Substituting these values into the formula gives \(y - 5 = -1/4(x - 2)\).
04

Convert to Slope-Intercept Form

Lastly, convert this equation back to the slope-intercept form 'y = mx + c'. Distribute -1/4 to (x - 2) and add 5 both sides to rearrange the equation as desired. This gives \(y = -1/4x + 5.5\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Slope-Intercept Form
The slope-intercept form of a linear equation is one of the most commonly used forms to represent a straight line. It is expressed as \( y = mx + c \). Here, \( m \) represents the slope of the line, and \( c \) indicates the y-intercept, which is the point where the line crosses the y-axis. This form is particularly useful because it provides clear, immediate information about the line's inclination (through the slope) and position (through the intercept).
To transform an equation into slope-intercept form, one must manipulate the equation to solve for \( y \). This often involves rearranging terms and operations until the equation looks like the standard form. Once in this form, interpreting properties of a line, such as its steepness or upward/downward direction, becomes straightforward.
For example, when a line equation is expressed as \( y = 4x - 7 \), it tells us that the line has a slope of 4, meaning it rises 4 units vertically for every 1 unit it moves horizontally.
Point-Slope Form
The point-slope form is another essential way to write equations of lines. It is formatted as \( y - y_1 = m(x - x_1) \), where \( m \) represents the slope of the line, and \((x_1, y_1)\) are the coordinates of a point through which the line passes. This form is particularly handy when you have a known point and a slope and need to quickly construct the equation of the line.
While it might not immediately give you the y-intercept, the point-slope form is quite flexible. You can easily rearrange it into the slope-intercept form to find additional properties of the line. Using this form means you'll need to plug in your specific slope and point values, as shown with the point \((2, 5)\) and the perpendicular slope \(-\frac{1}{4}\). This gives you \( y - 5 = -\frac{1}{4}(x - 2) \), straightforwardly outlining the line's equation through those specific parameters.
Negative Reciprocals
Negative reciprocals are a crucial concept when dealing with perpendicular lines. When two lines are perpendicular, the product of their slopes is \(-1\). This relationship stems from the concept of negative reciprocals: take the slope of one line (\( m \)), and the slope of its perpendicular line is \(-\frac{1}{m} \).
Understanding how to find the negative reciprocal can help in various geometry and algebra problems. If a line has a slope of 4, the slope of a line perpendicular to it will be \(-\frac{1}{4}\). This drastically changes the line's direction, ensuring the two lines intersect at a right angle.
This property is useful when needing to establish perpendicularity between lines, a frequent requirement in coordinate geometry tasks. Once you grasp this concept, identifying or building perpendicular lines from slope output becomes a much smoother process.

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