/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 51 Solve each inequality and graph ... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Solve each inequality and graph the solution on the number line. .7-x \leq 3 x-1

Short Answer

Expert verified
The solution to the inequality \( .7-x \leq 3x-1 \) is \( x \geq .425 \). This is represented on the number line by a filled in circle at \(.425\) with a line extending to the right to signify inclusion of all numbers greater than or equal to \(.425\).

Step by step solution

01

Rewriting the inequality

Rewrite the inequality \( .7 - x \leq 3x - 1 \) to put all x terms on one side and constants on the other. Subtracting \( .7 \) on both sides gives \( -x \leq 3x -1.7 \). Adding \( x \) to both sides gives \( 0 \leq 4x - 1.7 \)
02

Solve for x

Solving the resulting inequality \( 0 \leq 4x - 1.7 \) for \( x \) involves adding \( 1.7 \) on both sides to get \( 1.7 \leq 4x \). Finally, divide both sides by 4 to isolate \( x \), yielding \( x \geq .425 \). Note that the inequality symbol points towards \( x \) indicating that \( x \) is greater than or equal to \(.425\).
03

Graphing the Solution on the Number Line

To graph the solution \( x \geq .425 \) on the number line, mark \(.425\) on the number line and draw a circle around it. Since \( x \geq .425 \) includes \(.425\), fill in the circle to indicate that it is part of the solution. Draw a line extending to the right of \(.425\), indicating that all numbers greater than or equal to \(.425\) are part of the solution.

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