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A numerical expression is a mathematical sentence combining numbers and operations but without any variables. For instance, if you have the expression \(2 + 3\), it's a numerical expression because it involves the numbers 2 and 3 with the addition operation between them.

To simplify a numerical expression, you follow the order of operations, usually abbreviated as PEMDAS: Parentheses, Exponents, Multiplication and Division (from left to right), and Addition and Subtraction (from left to right). Using this method ensures that everyone solves the expression in the same way and gets the same result.

In our case, the expression \(2 + (-3)\) is simplified by first acknowledging that \(+ (-3)\) is the same as subtraction. Thus, the expression becomes \(2 - 3\) and simplifies to the integer \-1\, by performing the subtraction step.

An algebraic fraction contains variables as well as numbers. Generally, it's in the form of one algebraic expression divided by another, like \(\frac{a + b}{c + d}\), where \(a\), \(b\), \(c\), and \(d\) could be numbers, variables, or a mixture of both.

When you simplify algebraic fractions, you look to reduce the expression to its simplest form by factoring, canceling common factors, and simplifying the numerical operations if possible. For a simple algebraic fraction, as seen in our exercise \(\frac{2+(-3)}{-3-(-4)}\), think of the fraction as a division problem and simplify the numerator and the denominator separately before dividing them. If the numerator and denominator have common factors, they can be canceled out to simplify the algebraic fraction further.

Basic algebra introduces the concept of using symbols, typically letters, to represent numbers in equations and expressions. It's a step beyond numerical expressions because it allows for generalizations and solving for unknowns.

In basic algebra, you use the same order of operations as in numerical expressions, but you now need to consider how to handle the variables. For example, to simplify \(x + y - y\), you would cancel out the \(y\) terms since they are additive inverses, leaving just \(x\).

In the context of our problem, even though it looks like a numerical expression as there are no variables, you apply the same principles you would use in algebra. First, you simplify the parts within the parentheses, and then you tackle the division of the numerator by the denominator. Simplifying in steps can make even complicated algebraic expressions manageable.