Chapter 7: Problem 58
Rewrite each rational expression with the indicated denominator. $$ \frac{3 r}{5 r-5}=\frac{?}{15 r-15} $$
Short Answer
Expert verified
\(\frac{3r}{5r - 5} = \frac{9r}{15r - 15}\)
Step by step solution
01
Identify the Original Denominator
The original denominator in the given rational expression is \(5r - 5\).
02
Factor the Original Denominator
Factor the original denominator \(5r - 5\) to its simplest form: \( 5(r - 1) \).
03
Identify the Indicated Denominator
The indicated denominator is \(15r - 15\).
04
Factor the Indicated Denominator
Factor the indicated denominator \(15r - 15\) to its simplest form: \(15(r - 1)\).
05
Determine the Multiplication Factor
Determine the factor required to multiply the original denominator \(5(r - 1)\) to get the indicated denominator \(15(r - 1)\). Note that you must multiply the numerator and the denominator of the original fraction by the same factor. The factor is \(3\), as \(5 \times 3 = 15\).
06
Rewrite the Numerator
Multiply the original numerator \(3r\) by the factor \(3\) to obtain the new numerator: \(3r \times 3 = 9r\).
07
Express the New Rational Expression
Rewrite the rational expression with the new numerator and the indicated denominator: \(\frac{3r}{5r - 5} = \frac{9r}{15r - 15}\).
Unlock Step-by-Step Solutions & Ace Your Exams!
-
Full Textbook Solutions
Get detailed explanations and key concepts
-
Unlimited Al creation
Al flashcards, explanations, exams and more...
-
Ads-free access
To over 500 millions flashcards
-
Money-back guarantee
We refund you if you fail your exam.
Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
factoring polynomials
When working with rational expressions, factoring polynomials is a crucial step. Factoring simplifies the expressions and makes it easier to identify common denominators. In our problem, we start by factoring the original denominator, which is \(5r - 5\).
To factor this, we notice that both terms share a common factor of 5. We can then factor out the 5:
This simplification helps us to see the relation with the indicated denominator, \(15r - 15\).
Similar to the first step, we factor the indicated denominator:
By factoring polynomials, we break down the expressions into simpler, recognizable factors, which is essential for further steps.
To factor this, we notice that both terms share a common factor of 5. We can then factor out the 5:
- $$5r - 5 = 5(r - 1)$$
This simplification helps us to see the relation with the indicated denominator, \(15r - 15\).
Similar to the first step, we factor the indicated denominator:
- $$15r - 15 = 15(r - 1)$$
By factoring polynomials, we break down the expressions into simpler, recognizable factors, which is essential for further steps.
common denominators
Finding common denominators is a key part of working with rational expressions. In our exercise, we need to rewrite the original fraction with a different denominator. Once we have factored both the original and indicated denominators, we can easily identify the relationship.
The original and indicated denominators after factoring are:
Here, both denominators have the common factor \((r - 1)\). The original denominator needs to be multiplied by a certain factor to match the indicated denominator.
We notice that 5 must be multiplied by 3 to get 15:
The original and indicated denominators after factoring are:
- Original: $$5(r - 1)$$
- Indicated: $$15(r - 1)$$
Here, both denominators have the common factor \((r - 1)\). The original denominator needs to be multiplied by a certain factor to match the indicated denominator.
We notice that 5 must be multiplied by 3 to get 15:
- $$5 \times 3 = 15$$
fractions
Understanding how fractions work is essential when reworking rational expressions. In this problem, we rewrite the original fraction \(\frac{3r}{5r - 5}\) with a new denominator \(15r - 15\).
First, apply the factor of 3 to both the numerator and denominator:
By multiplying both parts by the factor determined previously, we keep the value of the fraction unchanged. The final expression is:
Understanding fractions and multiplication factors is vital in making these conversions seamlessly.
First, apply the factor of 3 to both the numerator and denominator:
- Numerator: $$3r \times 3 = 9r$$
- Denominator: $$5(r - 1) \times 3 = 15(r - 1)$$
By multiplying both parts by the factor determined previously, we keep the value of the fraction unchanged. The final expression is:
- $$\frac{9r}{15r - 15}$$
Understanding fractions and multiplication factors is vital in making these conversions seamlessly.