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91Ó°ÊÓ

Perform each division using the "long division" process. $$ \frac{3 k^{3}-4 k^{2}-6 k+10}{k-2} $$

Short Answer

Expert verified
Quotient: \(3k^{2} + 2k - 2\), Remainder: \6\.

Step by step solution

01

Set Up the Long Division

Write down the polynomial division in long division format. The divisor is \(k - 2\) and the dividend is \(3k^{3} - 4k^{2} - 6k + 10\).
02

Divide the First Terms

Divide the first term of the dividend \(3k^{3}\) by the first term of the divisor \(k\). This gives \(3k^{2}\). Write \(3k^{2}\) above the division bar.
03

Multiply and Subtract

Multiply \(3k^{2}\) by \(k - 2\), resulting in \(3k^{3} - 6k^{2}\). Subtract \(3k^{3} - 6k^{2}\) from \(3k^{3} - 4k^{2} - 6k + 10\), leaving \(2k^{2} - 6k + 10\).
04

Repeat Division

Now divide \(2k^{2}\) by \(k\), which gives \(2k\). Write \(2k\) above the division bar next to \(3k^{2}\).
05

Multiply and Subtract Again

Multiply \(2k\) by \(k - 2\), resulting in \(2k^{2} - 4k\). Subtract \(2k^{2} - 4k\) from \(2k^{2} - 6k + 10\), yielding \(-2k + 10\).
06

Final Division Step

Divide \(-2k\) by \(k\), which gives \(-2\). Write \(-2\) above the division bar next to \(2k\).
07

Multiply and Subtract Final Time

Multiply \(-2\) by \(k - 2\), resulting in \(-2k + 4\). Subtract \(-2k + 4\) from \(-2k + 10\), giving a remainder of \(6\).
08

Write the Final Answer

The quotient is \(3k^{2} + 2k - 2\) with a remainder of \(6\). Thus, the answer is \(3k^{2} + 2k - 2 + \frac{6}{k-2}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

polynomial division
Polynomial division is a method for dividing a polynomial by another polynomial of lesser degree. It is similar to long division with numbers, but here we divide expressions. You arrange the polynomials in descending order of power and follow the steps just like regular long division.

In our exercise, we are dividing the polynomial \(3k^{3} - 4k^{2} - 6k + 10\) by \(k - 2\). We start by dividing the first term of the numerator by the first term of the denominator. Then, we multiply, subtract, and bring down the next term to repeat the process.
  • This continues until all terms are processed.
  • Like numerical long division, this method systematically reduces the polynomial degree.
Understanding polynomial division helps solve complex algebraic problems and simplifies expressions, which is essential in calculus and other advanced math topics.
algebraic expressions
Algebraic expressions are combinations of variables, constants, and operators (like addition and subtraction). They represent mathematical relationships in a concise form. When dividing polynomials, each part of the expression needs careful handling to ensure accuracy.

In our example, the dividend is the algebraic expression \(3k^{3} - 4k^{2} - 6k + 10\). The divisor is another expression, \(k - 2\). Each step involves:
  • Dividing terms
  • Multiplying and subtracting accurately
  • Keeping track of positive and negative signs
Using and understanding algebraic expressions in polynomial division is key. It allows for breaking down complex problems and finding solutions systematically. Practicing these makes advanced topics easier to handle and understand.
remainder in division
When dividing polynomials, you may end up with a remainder. This is the part of the dividend that isn't perfectly divisible by the divisor. In numerical terms, it’s similar to the 'leftover' amount when one number doesn't divide evenly into another.

In our division problem, after completing the steps, we are left with a remainder of 6. This means that \(3k^{3} - 4k^{2} - 6k + 10\) divided by \(k - 2\) has:
  • A quotient of \(3k^{2} + 2k - 2\)
  • A remainder of 6
So, the result is written as: \(3k^{2} + 2k - 2 + \frac{6}{k-2}\).

This remainder term represents what’s left over and is important in understanding the solution fully. Practicing and identifying remainders helps in mastering polynomial division and prepares you for advanced algebra and calculus.

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Most popular questions from this chapter

The special product $$ (x+y)(x-y)=x^{2}-y^{2} $$ $$ \text { can be used to perform some multiplication problems. Here are two examples.} $$ $$ \begin{aligned} 51 \times 49 &=(50+1)(50-1) \\ &=50^{2}-1^{2} \\ &=2500-1^{2} \\ &=2499 \end{aligned} \quad | \begin{aligned} 102 \times 98 &=(100+2)(100-2) \\ &=100^{2}-2^{2} \\ &=10,000-4 \\ &=9996 \end{aligned} $$ Once these patterns are recognized, multiplications of this type can be done mentally. Use this method to calculate each product mentally. $$ 20 \frac{1}{2} \times 19 \frac{1}{2} $$

Match each expression in Column I with the equivalent expression in Column II. Choices in Column II may be used once, more than once, or not at all. An Exercise \(17, x \neq 0 .\). I (a) \(x^{0}\) (b) \(-x^{0}\) (c) \(7 x^{0}\) (d) \((7 x)^{0}\) (e) \(-7 x^{0}\) (f) \((-7 x)^{0}\) II A. 0 B. 1 C. -1 D. 7 E. -7 F. \(\frac{1}{7}\)

Use scientific notation to calculate the answer to each problem. Astronomers using the Spitzer Space Telescope discovered a twisted double- helix nebula, a conglomeration of dust and gas stretching across the center of the Milky Way galaxy. This nebula is \(25,000\) light-years from Earth. If one light-year is about \(6,000,000,000,000\) (that is, 6 trillion) miles, about how many miles is the twisted double-helix nebula from Earth?

If an object is projected upward under certain conditions, its height in feet is given by the trinomial $$ -16 x^{2}+60 x+80 $$ where \(x\) is in seconds. Evaluate this polynomial for \(x=2.5 .\) Use the result to fill in the blanks: If___ \(-\) seconds have elapsed, the height of the object is __ feet.

Use scientific notation to calculate the answer to each problem. In \(2008,\) the U.S. government collected about \(\$ 4013\) per person in personal income taxes. If the population was \(304,000,000,\) how much did the government collect in taxes for \(2008 ?\)

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