Chapter 5: Problem 26
Find each product. $$ 4 z^{3}\left(8 z^{2}+5 z y-3 y^{2}\right) $$
Short Answer
Expert verified
32z^5 + 20z^4y - 12z^3y^2
Step by step solution
01
- Distribute 4z^3 to Each Term
Multiply each term inside the parentheses by the term outside. Start by distributing the term \(4z^3\) to each term inside the parentheses: \(8z^2, 5zy, -3y^2\).
02
- Multiply \(4z^3\) by \(8z^2\)
Multiply \(4z^3\) by \(8z^2\): \(4z^3 \times 8z^2 = 32z^{5}\).
03
- Multiply \(4z^3\) by \(5zy\)
Multiply \(4z^3\) by \(5zy\): \(4z^3 \times 5zy = 20z^4y\).
04
- Multiply \(4z^3\) by \(-3y^2\)
Multiply \(4z^3\) by \(-3y^2\): \(4z^3 \times -3y^2 = -12z^3y^2\).
05
- Combine All Terms
Combine all the multiplied terms to get the final product: \(32z^5 + 20z^4y - 12z^3y^2\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Distributive Property
The distributive property is a fundamental concept in algebra that allows us to multiply a single term by each term within a set of parentheses. This property is essential when dealing with polynomial multiplication. In the given exercise, we need to distribute \(4z^3\) to each term inside the parentheses: \(8z^2 + 5zy - 3y^2\).
Let’s break this down:
By distributing correctly, we ensure that each term within the parentheses is accounted for. Combining these products gives us the final result: \(32z^5 + 20z^4y - 12z^3y^2\).
Let’s break this down:
- We multiply \(4z^3\) by \(8z^2\) to get \(32z^5\).
- Next, we multiply \(4z^3\) by \(5zy\) to get \(20z^4y\).
- Finally, we multiply \(4z^3\) by\(-3y^2\) to get \(-12z^3y^2\).
By distributing correctly, we ensure that each term within the parentheses is accounted for. Combining these products gives us the final result: \(32z^5 + 20z^4y - 12z^3y^2\).
Exponent Rules
Understanding exponent rules is crucial when performing polynomial multiplication. The two main rules to remember are:
In our exercise, as we multiply terms, we need to apply the first rule. For instance:
These simple rules help simplify expressions quickly and accurately.
- When multiplying like bases, add the exponents: If you have \(a^m \times a^n\), the result is \(a^{m+n}\).
- When raising a power to a power, multiply the exponents: If you have \((a^m)^n\), the result is \(a^{m \times n}\).
In our exercise, as we multiply terms, we need to apply the first rule. For instance:
- \(4z^3 \times 8z^2 = 32z^{3+2} = 32z^5\).
- \(4z^3 \times 5zy = 20z^{3+1}y = 20z^4y\).
- \(4z^3 \times -3y^2 = -12z^3y^2\) (since there is no z in the second term, we keep the exponents as they are).
These simple rules help simplify expressions quickly and accurately.
Algebraic Expressions
An algebraic expression is a mathematical phrase that can contain numbers, variables, and operation symbols. It represents a specific value.
In the exercise, our initial expression is \(4z^3(8z^2 + 5zy - 3y^2)\).
To solve it:
Algebraic expressions are used across mathematics to generalize rules and formulas, paving the way for more complex problem-solving.
In the exercise, our initial expression is \(4z^3(8z^2 + 5zy - 3y^2)\).
To solve it:
- We distribute \(4z^3\), as explained before, to each term within the parentheses. Each multiplication follows the exponent rules.
- This results in each term being simplified to \(32z^5, 20z^4y,\) and \(-12z^3y^2\).
- Combining these gives us the final algebraic expression: \(32z^5 + 20z^4y - 12z^3y^2\).
Algebraic expressions are used across mathematics to generalize rules and formulas, paving the way for more complex problem-solving.