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Write a system of equations for each problem, and then solve the system. Kansas City and Denver are \(600 \mathrm{mi}\) apart. Two cars start from these cities, traveling toward each other. They pass each other after 6 hr. Find the rate of each car if one travels 30 mph slower than the other.

Short Answer

Expert verified
The speed of the car from Kansas City is 65 mph, and from Denver is 35 mph.

Step by step solution

01

- Define Variables

Let the speed of the car starting from Kansas City be denoted as \(r_1\), and the speed of the car starting from Denver be denoted as \(r_2\). According to the problem, \(r_2 = r_1 - 30\).
02

- Set Up Equations

The total distance covered by both cars together is \(600 \text{ miles}\). Since they travel toward each other, the sum of the distances each car travels, \(r_1 \times 6\) and \(r_2 \times 6\), is equal to \(600 \text{ miles}\). Therefore, we can set up the equation: \[6r_1 + 6r_2 = 600\].
03

- Substitute Expression

Substitute \(r_2 = r_1 - 30\) into the equation from Step 2: \[6r_1 + 6(r_1 - 30) = 600\]
04

- Simplify the Equation

Simplify the equation: \[6r_1 + 6r_1 - 180 = 600\] Combine like terms: \[12r_1 - 180 = 600\]
05

- Solve for \(r_1\)

Add 180 to both sides of the equation: \[12r_1 = 780\] Divide both sides by 12: \[r_1 = 65\]
06

- Find \(r_2\)

Substitute \(r_1 = 65\) back into the expression for \(r_2\): \[r_2 = r_1 - 30 = 65 - 30 = 35\]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding Algebraic Equations
Algebraic equations are the foundation of many mathematical problems. These equations include variables, constants, and arithmetic operations. In the given problem, we encounter two algebraic equations representing the speeds of two cars. An algebraic equation can be as simple as a single variable equating two numbers (e.g., \(x = 2\)) or more complex involving multiple variables and operations (e.g., \(6r_1 + 6r_2 = 600\)).

In our problem, by defining the speed of one car as \(r_1\) and knowing the second car's speed is 30 mph slower (\(r_2 = r_1 - 30\)), we set up relationships between the variables. Solving algebraic equations often involves:
  • Substituting known values
  • Simplifying terms
  • Isolating the variable
Steps in Solving Equations
To solve any equation, follow structured steps. We started by defining variables because it helps us translate word problems into mathematical form. Next, we set up the primary equation based on the relationship and distances: \(6r_1 + 6(r_1 - 30) = 600\). By substituting \(r_2 = r_1 - 30\) into the equation:

We simplify the equation into a single variable:
\ \[ 6r_1 + 6r_1 - 180 = 600 \]
Combining like terms, we get:
\ \[ 12r_1 - 180 = 600 \]
Isolate \(r_1\), first by adding 180:
\ \[ 12r_1 = 780 \]
Then, divide by 12:

\ \[ r_1 = 65 \].

Finally, we find the second variable \(r_2\) by substituting back: \ \[ r_2 = 65 - 30 = 35 \]

Each step is crucial to ensure precision. It helps prevent mistakes and confirm the solution matches all conditions in the problem.
Distance-Rate-Time Problems and Their Real-Life Application
Distance-rate-time problems link these three elements:
  • Distance (D): How far an object travels
  • Rate (R): Speed of the object
  • Time (T): Duration of the travel
These problems use the fundamental equation: \ \[ D = R \times T \]
In this problem, distances of two cars traveling towards each other add up. Each distance can be determined by multiplying their speed by travel time (6 hours): \ \[ D = r_1 \times 6 + (r_1 - 30) \times 6 \]
We can create equations to solve for unknowns. By understanding and setting up a system of equations, such problems become manageable and practical for real-life scenarios like travel planning or logistics. These problems also teach us how to break down complex scenarios into simpler steps, ensuring accurate solutions through logical problem-solving.

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Most popular questions from this chapter

Two of the top-grossing North American concert tours in 2008 were The Police and Madonna. Based on average ticket prices, it cost a total of \(\$ 1297\) to buy six tickets for The Police and frve tickets to a Madonna concert. Three tickets for The Police and four tickets for Madonna cost a total of \(\$ 854 .\) How much did an average ticket cost for each tour?

Write a system of equations for each problem, and then solve the system. RAGBRAI", the Des Moines Register's Annual Great Bicycle Ride Across Iowa, is the longest and oldest touring bicycle ride in the world. Suppose a cyclist began the \(471 \mathrm{mi}\) ride on July \(20,2008,\) in western Iowa at the same time that a car traveling toward it left eastern Iowa. If the bicycle and the car met after 7.5 hr and the car traveled \(35.8 \mathrm{mph}\) faster than the bicycle, find the average rate of each.

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Karen Walsh has twice as much money invested at \(5 \%\) simple annual interest as she does at \(4 \%\). If her yearly income from these two investments is \(\$ 350\), how much does she have invested at each rate?

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