Chapter 2: Problem 53
Solve inequality. Write the solution set in interval notation, and graph it. \(\frac{2}{3}(p+3)>\frac{5}{6}(p-4)\)
Short Answer
Expert verified
The solution set is \( -\infty, 32 \).
Step by step solution
01
- Distribute the fractions
Distribute \(\frac{2}{3}\) and \(\frac{5}{6}\) through the parentheses: \[ \frac{2}{3} \times (p + 3) > \frac{5}{6} \times (p - 4) \] which results in \[ \frac{2}{3}p + 2 > \frac{5}{6}p - \frac{10}{3} \]
02
- Eliminate fractions by finding a common multiple
To eliminate the fractions, multiply every term by the least common multiple of 3 and 6, which is 6: \[ 6 \times \frac{2}{3}p + 6 \times 2 > 6 \times \frac{5}{6}p - 6 \times \frac{10}{3} \] This simplifies to: \[ 4p + 12 > 5p - 20 \]
03
- Arrange terms to isolate the variable
Subtract \5p\ from both sides: \[ 4p + 12 - 5p > -20 \] which simplifies to: \[ -p + 12 > -20 \]
04
- Isolate the variable
Subtract 12 from both sides: \[ -p > -32 \] Multiply both sides by \(-1\) to solve for \p\: \[ p < 32 \]
05
- Write the solution set in interval notation
In interval notation, the solution is \( -\infty, 32 \)
06
- Graph the solution on a number line
Draw a number line and shade the region to the left of 32, with an open circle at 32 to indicate that 32 is not included in the solution.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Interval Notation
Interval notation is a way to describe sets of numbers, where the intervals denote the range of values that satisfy certain conditions. For instance, when we say \( p < 32 \), it means that every number less than 32 is a part of the solution. We represent this in interval notation as \( (-\infty, 32) \). The round brackets, also called parentheses, indicate that the endpoints are not included.
To better understand:
To better understand:
- Use parentheses \( ( \) and \( ) \) for values that are NOT included in the interval.
- Use square brackets \[ \) and \( \] for values that ARE included in the interval.
Algebraic Manipulation
Algebraic manipulation is the process of rearranging and simplifying algebraic expressions using various rules and properties. Here’s a step-by-step guide using the given problem:
1. Distribute the fractions: Multiply \( \frac{2}{3} \) and \( \frac{5}{6} \) through the parentheses:
\[ \frac{2}{3}(p + 3) = \frac{2}{3}p + 2 \]
\[ \frac{5}{6}(p - 4) = \frac{5}{6}p - \frac{10}{3} \]
2. Eliminate fractions: Multiply every term by 6 (LCM of 3 and 6):
\[ 6 \times \frac{2}{3}p + 6 \times 2 > 6 \times \frac{5}{6}p - 6 \times \frac{10}{3} \] This simplifies to:
\[ 4p + 12 > 5p - 20 \]
3. Isolate the variable: Move all terms involving \( p \) to one side and constants to the other:
Subtract \( 5p \) from both sides:
\[ 4p + 12 - 5p > -20 \]
which simplifies to: \[ -p + 12 > -20 \]
Subtract 12 from both sides:
\[ -p > -32 \]
Multiply both sides by \( -1 \) (remember to reverse the inequality):
\[ p < 32 \]
1. Distribute the fractions: Multiply \( \frac{2}{3} \) and \( \frac{5}{6} \) through the parentheses:
\[ \frac{2}{3}(p + 3) = \frac{2}{3}p + 2 \]
\[ \frac{5}{6}(p - 4) = \frac{5}{6}p - \frac{10}{3} \]
2. Eliminate fractions: Multiply every term by 6 (LCM of 3 and 6):
\[ 6 \times \frac{2}{3}p + 6 \times 2 > 6 \times \frac{5}{6}p - 6 \times \frac{10}{3} \] This simplifies to:
\[ 4p + 12 > 5p - 20 \]
3. Isolate the variable: Move all terms involving \( p \) to one side and constants to the other:
Subtract \( 5p \) from both sides:
\[ 4p + 12 - 5p > -20 \]
which simplifies to: \[ -p + 12 > -20 \]
Subtract 12 from both sides:
\[ -p > -32 \]
Multiply both sides by \( -1 \) (remember to reverse the inequality):
\[ p < 32 \]
Graphing Inequalities
Graphing inequalities shows a visual representation of their solution sets. When we graph the inequality \( p < 32 \) on a number line:
Remember:
- Draw a number line.
- Mark the point 32 with an open circle to indicate it is not included.
- Shade the region to the left of 32, showing all values less than 32.
Remember:
- An open circle means the number is not included (e.g., less than or greater than).
- A closed circle means the number is included (e.g., less than or equal to, or greater than or equal to).