Chapter 9: Problem 3
Solve the triangles with the given parts. $$a=45.7, A=65.0^{\circ}, B=49.0^{\circ}$$
Short Answer
Expert verified
Angle C is 66°, side b is approximately 38.06, and side c is approximately 46.05.
Step by step solution
01
Find Angle C
In a triangle, the sum of the angles is always 180 degrees. We know two of the angles, A and B. Therefore, we can find angle C using the formula: \( C = 180^{\circ} - A - B \). Substitute the given values: \( C = 180^{\circ} - 65^{\circ} - 49^{\circ} = 66^{\circ} \).
02
Apply the Law of Sines to Find Side b
According to the Law of Sines, the ratio of the length of a side to the sine of its opposite angle is constant for all sides of a triangle. We can apply this law to find side \( b \): \( \frac{a}{\sin A} = \frac{b}{\sin B} \). Substitute the known values: \( b = \frac{45.7 \times \sin 49^{\circ}}{\sin 65^{\circ}} \).
03
Calculate Side b
Use a calculator to find \( b \): \( b \approx \frac{45.7 \times 0.7547}{0.9063} = \frac{34.49}{0.9063} \approx 38.06 \). Thus, side \( b \) is approximately 38.06 units long.
04
Apply the Law of Sines to Find Side c
With the Law of Sines still applicable, compute side \( c \): \( \frac{a}{\sin A} = \frac{c}{\sin C} \). Substitute the known values: \( c = \frac{45.7 \times \sin 66^{\circ}}{\sin 65^{\circ}} \).
05
Calculate Side c
Use a calculator to find \( c \): \( c \approx \frac{45.7 \times 0.9135}{0.9063} = \frac{41.74}{0.9063} \approx 46.05 \). Thus, side \( c \) is approximately 46.05 units long.
Unlock Step-by-Step Solutions & Ace Your Exams!
-
Full Textbook Solutions
Get detailed explanations and key concepts
-
Unlimited Al creation
Al flashcards, explanations, exams and more...
-
Ads-free access
To over 500 millions flashcards
-
Money-back guarantee
We refund you if you fail your exam.
Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Understanding the Law of Sines
When solving triangles, especially non-right triangles, the \(\(\textit{Law of Sines}\)\) is an invaluable tool. It's a mathematical rule that helps us find unknown parts of a triangle, like sides or angles, given sufficient information. The law states that the ratio of the length of a side of a triangle to the sine of its opposite angle is constant across all three sides. This can be written as:
\[\frac{a}{\sin A} = \frac{b}{\sin B} = \frac{c}{\sin C}\]
\[\frac{a}{\sin A} = \frac{b}{\sin B} = \frac{c}{\sin C}\]
- \(a, b,\) and \(c\) are the lengths of the sides opposite angles \(A, B,\) and \(C\).
- \(\sin A, \sin B,\) and \(\sin C\) are the sine values of these angles.
The Triangle Angle Sum Property
Triangles have a unique and straightforward property: the sum of their internal angles is always \(180^{\circ}\). This is known as the \(\(\textit{Triangle Angle Sum Property}\)\). Whether right, acute, or obtuse, this rule applies universally.
In our given exercise, we were provided two angles, \(A = 65^{\circ}\) and \(B = 49^{\circ}\). To determine the third angle \(C\), we simply subtract the sum of \(A\) and \(B\) from \(180^{\circ}\).
In our given exercise, we were provided two angles, \(A = 65^{\circ}\) and \(B = 49^{\circ}\). To determine the third angle \(C\), we simply subtract the sum of \(A\) and \(B\) from \(180^{\circ}\).
- This gives \(C = 180^{\circ} - A - B\).
- Substituting the given values, \(C = 180^{\circ} - 65^{\circ} - 49^{\circ} = 66^{\circ}\).
Effective Methods for Solving Triangles
Solving triangles refers to the process of calculating unknown sides and angles given a few known parts. There are several approaches, but primarily we leverage properties like the \(\(\textit{Law of Sines}\)\) and the \(\(\textit{Triangle Angle Sum}\)\). This process involves:
- \(\textbf{Identifying Known Values:}\) Start by noting all given sides and angles.
- \(\textbf{Using Angle Sum:}\) If two angles are known, use the triangle angle sum property to find the third angle.
- \(\textbf{Applying Law of Sines:}\) Use the law to find any unknown sides. Set up equations according to the format \(\frac{\text{side}}{\sin(\text{opposite angle})}\).
- \(\textbf{Calculate:}\) Use a calculator to solve these equations accurately.