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Solve the triangles with the given parts. $$a=89.45, c=37.36, C=15.62^{\circ}$$

Short Answer

Expert verified
The angles are approximately \( A = 40.18^{\circ} \), \( B = 124.20^{\circ} \), and the side is \( b \approx 114.73 \).

Step by step solution

01

Apply the Law of Sines

Using the Law of Sines, we have the formula \( \frac{a}{\sin A} = \frac{c}{\sin C} \). Plugging in the given values, we have \( \frac{89.45}{\sin A} = \frac{37.36}{\sin 15.62^{\circ}} \).
02

Calculate \( \sin 15.62^{\circ} \)

Using a calculator, find \( \sin 15.62^{\circ} \approx 0.2698 \).
03

Solve for \( \sin A \)

Rearrange the equation from Step 1 to \( \sin A = \frac{89.45 \times \sin 15.62^{\circ}}{37.36} \). Substitute \( \sin 15.62^{\circ} = 0.2698 \).
04

Calculate \( \sin A \)

Compute the value, \( \sin A \approx \frac{89.45 \times 0.2698}{37.36} \approx 0.645 \).
05

Determine Angle A using Inverse Sine

Find \( A = \sin^{-1}(0.645) \approx 40.18^{\circ} \).
06

Calculate Angle B

Use the fact that the sum of angles in a triangle is \(180^{\circ}\). So, \(B = 180^{\circ} - A - C = 180^{\circ} - 40.18^{\circ} - 15.62^{\circ} \approx 124.20^{\circ} \).
07

Use the Law of Sines to Find Side b

Now, use the Law of Sines again: \( \frac{b}{\sin B} = \frac{c}{\sin C} \). Fill in the known values: \( \frac{b}{\sin 124.20^{\circ}} = \frac{37.36}{0.2698} \).
08

Calculate \( \sin 124.20^{\circ} \)

\( \sin 124.20^{\circ} \approx 0.829 \).
09

Solve for Side b

Rearrange to find \( b = \frac{37.36 \times 0.829}{0.2698} \approx 114.73 \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Law of Sines
The Law of Sines is an essential tool for solving triangles, especially when dealing with non-right triangles. This law connects the ratios of the length of a side of a triangle to the sine of its opposite angle. Mathematically, it is expressed as \( \frac{a}{\sin A} = \frac{b}{\sin B} = \frac{c}{\sin C} \). This relationship is particularly useful when you know:
  • Two angles and one side (AAS or ASA scenarios)
  • Two sides and an angle not between them (SSA scenario)
When applying the Law of Sines, ensure the use of angle and side pairs. In the exercise, we used it to find the unknown angles and sides by plugging the given values. Understanding this law helps you solve various triangle-related problems efficiently.
Triangle Angles
Triangles are fascinating geometrical shapes with three sides and three angles, and it's crucial to know that the sum of all interior angles in a triangle is always \(180^{\circ}\). This property is fundamental in finding the missing angles once one or two angles are known.

In the original exercise, we had angle \(C = 15.62^{\circ}\) and, after finding \(A\), we simply used the angle sum property:
\(B = 180^{\circ} - A - C\). This calculation allowed us to find the last angle in the triangle, ensuring the integrity of the triangle's properties and leading us to a complete solution.
Inverse Sine
Inverse trigonometric functions allow us to find angles when given trigonometric ratios. The inverse sine, denoted as \( \sin^{-1} \) or arcsin, is the function we use to determine an angle whose sine is a particular value.

In the solution approach of the exercise, upon obtaining \( \sin A \approx 0.645 \), the next logical step was to discover the measure of angle \(A\). Applying the inverse sine function, \( A = \sin^{-1}(0.645) \), provided us with the approximate angle of \(40.18^{\circ}\).

This process underscores how inverse functions are essential in transitioning from trigonometric values back to angular measurements, completing the steps necessary to solve for unknown angles in a triangle.
Solve Triangles
Solving a triangle means finding all its missing angles and side lengths, given some initial conditions. The approach often involves a combination of laws, formulas, and geometric properties.

In the given example, the following steps were utilized:
  • Application of the Law of Sines to find unknown angles and sides.
  • Using angle sum properties to find missing angles.
  • Employing inverse trigonometric functions to resolve angles from trigonometric ratios.
Each step builds upon the other, illustrating how interconnected these concepts are. Mastery of solving triangles requires understanding not just formulas but also recognizing which rules to apply and when.

By systematically applying these principles, you ensure a comprehensive solution, uncovering all angles and sides, leading to a fully solved triangle.

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Most popular questions from this chapter

Solve the given problems. In searching for a boat lost at sea, a Coast Guard cutter leaves a port and travels \(75.0 \mathrm{mi}\) due east. It then turns \(65^{\circ}\) north of east and travels another \(75.0 \mathrm{mi}\), and finally turns another \(65.0^{\circ}\) toward the west and travels another \(75.0 \mathrm{mi}\). What is its displacement from the port?

Use the law of sines to solve the given problems. The Pentagon (headquarters of the U.S. Department of Defense) is the largest office building in the world. It is a regular pentagon (five sides), 921 ft on a side. Find the greatest straight-line distance from one point on the outside of the building to another outside point (the length of a diagonal).

Solve the given problems. A scuba diver's body is directed downstream at \(75^{\circ}\) to the bank of a river. If the diver swims at \(25 \mathrm{m} / \mathrm{min}\), and the water is moving at \(5.0 \mathrm{m} / \mathrm{min},\) what is the diver's velocity?

Add the given vectors by components. $$\begin{aligned} &A=9.821, \theta_{A}=34.27^{\circ}\\\ &B=17.45, \theta_{B}=752.50^{\circ} \end{aligned}$$

Find the required horizontal and vertical components of the given vectors. Vertical wind sheer in the lowest \(100 \mathrm{m}\) above the ground is of great importance to aircraft when taking off or landing. It is defined as the rate at which the wind velocity changes per meter above ground. If the vertical wind sheer at \(50 \mathrm{m}\) above the ground is \(0.75(\mathrm{km} / \mathrm{h}) / \mathrm{m}\) directed at angle of \(40^{\circ}\) above the ground, what are its vertical and horizontal components?

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