Chapter 7: Problem 19
Use a calculator to solve the given equations. Round solutions to the nearest hundredth. If there are no real roots, state this. $$-3 x^{2}+9 x-5=0$$
Short Answer
Expert verified
The solutions are approximately 0.74 and 2.26.
Step by step solution
01
Identify the Equation Format
The given equation is a quadratic equation in the standard form: \[-3x^2 + 9x - 5 = 0\] where \(a = -3\), \(b = 9\), and \(c = -5\).
02
Calculate the Discriminant
The discriminant \(D\) of a quadratic equation \(ax^2 + bx + c = 0\) is given by the formula: \[D = b^2 - 4ac\] Substitute \(a = -3\), \(b = 9\), and \(c = -5\) into the formula:\[D = 9^2 - 4(-3)(-5) = 81 - 60 = 21\] Since \(D > 0\), the equation has two real roots.
03
Use the Quadratic Formula
The quadratic formula to find the roots is: \[x = \frac{-b \pm \sqrt{D}}{2a}\] Substitute \(b = 9\), \(D = 21\), and \(a = -3\) into the formula:\[x = \frac{-9 \pm \sqrt{21}}{-6}\]
04
Calculate the Roots Using a Calculator
First, calculate \(\sqrt{21}\) using a calculator to get approximately 4.58. Next, find the two roots:\[x_1 = \frac{-9 + 4.58}{-6} \approx \frac{-4.42}{-6} \approx 0.74\]\[x_2 = \frac{-9 - 4.58}{-6} \approx \frac{-13.58}{-6} \approx 2.26\]
05
Round to Nearest Hundredth
The roots calculated are approximately 0.7367 and 2.2633. When rounded to the nearest hundredth, the roots are 0.74 and 2.26, respectively.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Discriminant
In the world of quadratic equations, the discriminant is a powerful tool. It helps determine the nature of the roots without actually solving the equation. The discriminant is simply a number that can be calculated directly from the coefficients of a quadratic equation in the form: \[ ax^2 + bx + c = 0 \]The formula to find the discriminant is:\[ D = b^2 - 4ac \]Here's why the discriminant matters:
- If \( D > 0 \), the quadratic equation has two distinct real roots.
- If \( D = 0 \), there is exactly one real root (which is a repeated root, also known as a double root).
- If \( D < 0 \), the equation has no real roots, meaning the solutions are complex numbers.
Quadratic Formula
The quadratic formula provides a straightforward method to find solutions, or roots, for any quadratic equation. The formula works as follows:\[ x = \frac{-b \pm \sqrt{D}}{2a} \]Where:
- \( b \) is the coefficient of the linear term \( x \)
- \( D \) is the discriminant calculated through \( D = b^2 - 4ac \)
- \( a \) is the coefficient of \( x^2 \)
- Once as "\( -b + \sqrt{D} \)"
- Once as "\( -b - \sqrt{D} \)"
Real Roots
Real roots refer to the solutions of the quadratic equation that are real numbers. These no-nonsense solutions are the values of \( x \) that satisfy the equation, and they can be plotted on a real number line.Let's break down how we obtained the real roots in our example:
- We had \( x_1 = \frac{-9 + 4.58}{-6} \) and \( x_2 = \frac{-9 - 4.58}{-6} \).
- Using a calculator to simplify these gave us the approximate roots: \( x_1 = 0.74 \) and \( x_2 = 2.26 \).