Chapter 7: Problem 16
Sketch the graph of each parabola by using the vertex, the \(y\) -intercept, and two other points, not including the \(x\) -intercepts. Check the graph using a calculator. $$y=-3 x^{2}-x$$
Short Answer
Expert verified
The parabola has a vertex at \(\left(\frac{1}{6}, -\frac{1}{4}\right)\), y-intercept \((0,0)\), and opens downwards.
Step by step solution
01
Identify the Vertex
For a parabola in the form \(y = ax^2 + bx + c\), the vertex \((h,k)\) can be found using \(h = -\frac{b}{2a}\). Here, \(a = -3\) and \(b = -1\). Calculate \(h\): \(h = -\frac{-1}{2(-3)} = \frac{1}{6}\). To find \(k\), substitute \(h\) into the equation: \(k = -3\left(\frac{1}{6}\right)^2 - \frac{1}{6} = -\frac{1}{12} - \frac{1}{6} = -\frac{3}{12} = -\frac{1}{4}\). Thus, the vertex is \(\left(\frac{1}{6}, -\frac{1}{4}\right)\).
02
Find the y-intercept
The y-intercept occurs where \(x = 0\). Substitute \(x = 0\) into the equation: \(y = -3(0)^2 - 0 = 0\). So, the y-intercept is the point \((0, 0)\).
03
Choose and Calculate Two Other Points
Select \(x = 1\) and \(x = -1\) to find two additional points on the parabola. For \(x = 1\), substitute into the equation: \(y = -3(1)^2 - 1 = -3 - 1 = -4\). So the point is \((1, -4)\). For \(x = -1\), \(y = -3(-1)^2 - (-1) = -3 + 1 = -2\). Thus the point is \((-1, -2)\).
04
Sketch the Graph
Plot the vertex \(\left(\frac{1}{6}, -\frac{1}{4}\right)\), the y-intercept \((0, 0)\), and the points \((1, -4)\) and \((-1, -2)\) on the graph. The parabola opens downward because \(a = -3\) is negative. Draw a smooth curve through these points.
05
Confirm Using a Calculator
Use a graphing calculator to verify the shape of the parabola. Input \(y = -3x^2 - x\) and check that the graph matches the sketched points and shape.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Vertex Calculation
Calculating the vertex of a parabola is the first step to understanding its mysterious curves. The vertex is a unique point on the graph, often the peak or bottom of the parabola. It acts as a pivotal indicator of where the graph changes direction. To find the vertex of a function given by the quadratic form \( y = ax^2 + bx + c \), follow these steps:
- Calculate the x-coordinate \( h \) of the vertex using the formula: \( h = -\frac{b}{2a} \).
- Find the y-coordinate \( k \) by substituting \( h \) back into the original equation. Compute \( y = a(h)^2 + bh + c \) to find \( k \).
Quadratic Function
The quadratic function forms the backbone of the beautiful parabolic curves we see in mathematics. It's expressed in the form \( y = ax^2 + bx + c \) and has distinctive properties. Here's why it matters:
- The quadratic function determines the shape of the parabola. The sign and value of \( a \) dictate whether it opens upwards or downwards.
- Parabolas can capture the paths of projectiles in physics or illustrate profit curves in economics.
- Understanding this function allows us to find key features like the vertex, axis of symmetry, and intercepts.
Graphing Techniques
Graphing a parabola requires precision and technique to achieve accuracy. Here's a simple guide to help you sketch the graph effectively:- **Start with the vertex**: It's the pivot of the parabola, which helps anchor the plot.- **Identify the y-intercept**: Substitute \( x = 0 \) into the function to find where the graph crosses the y-axis. For our function, this is the origin, or \( (0, 0) \).- **Select two additional points**: Choose convenient x-values to substitute into the equation for extra guidance on the graph's shape. For instance, using \( x = 1 \) and \( x = -1 \) gave us points \( (1, -4) \) and \( (-1, -2) \) respectively.- **Draw the parabola**: Connect these points smoothly, ensuring that the curve remains symmetrical around the vertex.Visualization transforms these calculated points into a meaningful graph, offering a complete picture of the quadratic equation in action.
Mathematical Verification
Verifying your graph ensures that your hand-drawn parabola aligns with the actual equation. This step confirms both the accuracy of your calculations and the precision of your drawing. Here's how to verify your graph:- **Use a graphing calculator**: Input your equation \( y = -3x^2 - x \) into the calculator. This confirms the structure and orientation of your graph through a quick visual.- **Cross-check plotted points**: Ensure the key points such as the vertex, y-intercept, and additional points align with those calculated.- **Double-check symmetry**: A downward-opening parabola like \( y = -3x^2 - x \), due to its negative \( a \) value, should exhibit symmetry about the line \( x = h \).Verification not only boosts confidence in your graphs but also sharpens analytical skills. With correct calculations and tools, you achieve mastery over graphing equations.