Chapter 6: Problem 70
Factor the expressions completely. In Exercises 73 and \(74,\) it is necessary to set up the proper expression. Each expression comes from the technical area indicated. \(12\left(4-x^{2}\right)-2 x\left(4-x^{2}\right)-\left(4-x^{2}\right)^{2} \quad\) (container design)
Short Answer
Expert verified
Expression factored as \((4-x^2)(x^2 - 2x + 8)\).
Step by step solution
01
Recognize Common Terms
Observe that each term in the expression contains the factor \((4-x^2)\). Identify this common factor in all three components of the expression: \(12(4-x^2)\), \(-2x(4-x^2)\), and \(-(4-x^2)^2\).
02
Factor Out the Common Term
Factor \((4-x^2)\) out of the expression. This gives:\[(4-x^2)(12 - 2x - (4-x^2))\]
03
Simplify the Expression in Parentheses
Determine the expression inside the parentheses. Simplify it by expanding \(-(4-x^2)\) which gives \(-4 + x^2\). Substitute it back into the expression:\[12 - 2x - 4 + x^2 \] Simplifying further results in:\[x^2 - 2x + 8\]
04
Identify the Quadratic Expression
Examine the simplified expression \(x^2 - 2x + 8\). It is a quadratic expression. Check if it's factorable over real numbers.
05
Check Factorability of Quadratic
Attempt to factor \(x^2 - 2x + 8\) using the discriminant \(b^2 - 4ac\). Here \(a = 1\), \(b = -2\), \(c = 8\). The discriminant is:\[(-2)^2 - 4(1)(8) = 4 - 32 = -28\]A negative discriminant indicates the quadratic doesn't factor into real numbers.
06
Write the Final Expression
Since \(x^2 - 2x + 8\) is not factorable over real numbers, the completely factored expression is:\[(4-x^2)(x^2 - 2x + 8)\]
Unlock Step-by-Step Solutions & Ace Your Exams!
-
Full Textbook Solutions
Get detailed explanations and key concepts
-
Unlimited Al creation
Al flashcards, explanations, exams and more...
-
Ads-free access
To over 500 millions flashcards
-
Money-back guarantee
We refund you if you fail your exam.
Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Common Factor
When a mathematical expression involves multiple terms, a common factor allows us to simplify it by identifying and factoring out similar components across these terms. In our exercise, the expression \(12(4-x^2) - 2x(4-x^2) - (4-x^2)^2\) presents a notable common factor: \((4-x^2)\). This approach involves identifying a shared part in an expression that repeatedly appears in each term.
After spotting the common factor, factor it out much like you would take a common item from a group. This reduces complexity, facilitating further simplification. By doing this, each term in the expression can be rewritten, revealing a structure that's easier to handle:
After spotting the common factor, factor it out much like you would take a common item from a group. This reduces complexity, facilitating further simplification. By doing this, each term in the expression can be rewritten, revealing a structure that's easier to handle:
- Term 1: \(12(4-x^2)\)
- Term 2: \(-2x(4-x^2)\)
- Term 3: \(-(4-x^2)^2\)
Quadratic Expression
A quadratic expression is a polynomial of the general form \(ax^2 + bx + c\). Its defining feature is the square of the unknown variable \(x\), making it a fundamental cornerstone in algebra. In our specific example, the expression \(x^2 - 2x + 8\) arises after simplifying the terms contained in the expression previously factored by the common factor.
Quadratic expressions can take many forms and have various properties:
Quadratic expressions can take many forms and have various properties:
- The leading term, \(x^2\), constitutes the hallmark of a quadratic expression.
- Quadratic expressions can possess one, two, or no real roots depending on their construction.
- Quadratics appear in numerous real-world scenarios, from projectile motion paths to designing structures.
Factorability
Factorability deals with the potential to express a polynomial as a product of simpler terms. For quadratic expressions such as \(x^2 - 2x + 8\), checking factorability involves discerning whether it can be expressed as a product of two binomials in the form \((x - p)(x - q)\).
Here's how you check factorability:
Here's how you check factorability:
- If the quadratic can be expressed in terms of integer roots, it is factorable over the integers.
- A factorable quadratic over real numbers requires a non-negative discriminant.
- If no such binomials exist (as revealed by the discriminant), the quadratic remains unfactorable over the reals.
Discriminant
The discriminant, represented as \(b^2 - 4ac\) from the general quadratic formula \(ax^2 + bx + c\), acts as a critical tool in determining the properties of a quadratic expression. It's central to ascertaining factorability and the nature of the solutions.
The discriminant helps in analyzing quadratics by showing:
The discriminant helps in analyzing quadratics by showing:
- If the discriminant is positive, two distinct real solutions (roots) exist, meaning the expression is factorable over real numbers.
- If the discriminant equals zero, one real and repeated solution exists, indicating the quadratic is a perfect square trinomial.
- If the discriminant is negative, no real solutions exist. The roots are imaginary, and the quadratic is not factorable over the reals.