/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 48 The expression \(f(x+h)-f(x)\) i... [FREE SOLUTION] | 91Ó°ÊÓ

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The expression \(f(x+h)-f(x)\) is frequently used in the study of calculus. (If necessary, refer to Section 3.1 for a review of functional notation.) Determine and then simplify this expression for the given functions. $$f(x)=\frac{3}{1-2 x}$$

Short Answer

Expert verified
The expression simplifies to \(\frac{6h}{(1-2x-2h)(1-2x)}\).

Step by step solution

01

Understand the Problem

We need to determine the expression \(f(x+h)-f(x)\) for \(f(x)=\frac{3}{1-2x}\). This difference is fundamental in calculus for concepts such as derivatives.
02

Substitute into the Expression

To find \(f(x+h)\), substitute \(x+h\) into the function \(f\): \[ f(x+h) = \frac{3}{1 - 2(x+h)}. \]Then, simplify inside the function: \[ f(x+h) = \frac{3}{1 - 2x - 2h}. \]
03

Formulate the Expression

Now that we have \(f(x+h)\), we write out the expression \(f(x+h) - f(x)\):\[ f(x+h) - f(x) = \frac{3}{1 - 2x - 2h} - \frac{3}{1 - 2x}. \]
04

Find a Common Denominator

The expression is a subtraction of two fractions, so we need a common denominator to combine them. The common denominator of \((1 - 2x - 2h)\) and \((1 - 2x)\) is:\[ (1 - 2x - 2h)(1 - 2x). \]
05

Combine the Fractions

Rewrite each fraction with the common denominator:\[ \frac{3(1 - 2x)}{(1 - 2x - 2h)(1 - 2x)} - \frac{3(1 - 2x - 2h)}{(1 - 2x - 2h)(1 - 2x)}. \]Now, combine into a single fraction:\[ \frac{3(1 - 2x) - 3(1 - 2x - 2h)}{(1 - 2x - 2h)(1 - 2x)}. \]
06

Simplify the Numerator

Simplify the numerator:\[ 3(1 - 2x) - 3(1 - 2x - 2h) = 3 - 6x - (3 - 6x - 6h). \]Simplify further:\[ = 3 - 6x - 3 + 6x + 6h = 6h. \]
07

Write the Simplified Expression

The expression \(f(x+h) - f(x)\) simplifies to:\[ \frac{6h}{(1 - 2x - 2h)(1 - 2x)}. \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding Derivatives
Derivatives are a fundamental concept in calculus and serve as a cornerstone for understanding change or rate of change in mathematical functions.
In basic terms, a derivative measures how a function's output value changes as the input changes.
This idea is incredibly useful for describing and predicting the behavior of functions.
  • Imagine you're tracking a car's speed. The derivative tells you how the speed increases or decreases over time.
  • In mathematical terms, if you have a function, say, of position over time, the derivative would be the velocity or speed that tells you how fast or slow the position changes.
The calculation of a derivative uses the concept of limits and the difference quotient. It allows us to approximate the tangent line's slope to the curve of a function at any given point. This slope is what we refer to as the derivative. In formal terms, if you have a function \( f(x) \), the derivative \( f'(x) \) is often represented by:\[f'(x) = \lim_{h \to 0} \frac{f(x+h) - f(x)}{h}\]This brings us to the next core concept: the functional notation.
Unpacking Functional Notation
Functional notation is a way of denoting functions in mathematics using symbols that make them easy to read and understand.
The function notation is written as \( f(x) \), where \( f \) is the name of the function, and \( x \) is the independent variable.
  • This notation allows more precise communication of the mathematical relationship between input and output.
  • It helps to

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