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91Ó°ÊÓ

Factor the given expressions completely. $$4 p^{2}-25 p q+6 q^{2}$$

Short Answer

Expert verified
The expression factors to \((4p - q)(p - 6q)\).

Step by step solution

01

Identify the Structure

First, recognize the expression as a quadratic in terms of either variable, here in terms of \(p\), since it is written as \(4p^2 - 25pq + 6q^2\). Check if it fits the pattern \(ax^2 + bx + c\), which it does.
02

Check for Common Factors

Before attempting any other factorization method, check if there is a common factor across all terms in the expression \(4p^2 - 25pq + 6q^2\). Here, there are no common factors for all terms.
03

Use Quadratic Factoring Technique

Since the expression is quadratic in form \(ax^2 + bx + c\), apply factoring of quadratic expressions using trial and error or the AC method. Find two numbers that multiply to \(a imes c = 4 imes 6 = 24q^2\) and add up to \(-25q\).
04

Find Numbers that Fit

The two numbers that multiply to \(24q^2\) and add to \(-25q\) are \(-24q\) and \(-1q\). Replace the middle term \(-25pq\) with these two terms: \(4p^2 - 24pq - 1pq + 6q^2\).
05

Group and Factor by Grouping

Group the terms into pairs and factor each group: \((4p^2 - 24pq)\) and \((-1pq + 6q^2)\). Factor out the greatest common factor from each group: \(4p(p - 6q)\) and \(-q(p - 6q)\).
06

Combine Factorized Form

Both groups contain the common factor \((p - 6q)\). Combine the groups: \((4p - q)(p - 6q)\). This is the completely factored form of the expression.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Factoring Quadratics
Factoring quadratics is a fundamental method used to simplify quadratic expressions. When we talk about quadratic expressions, we focus on polynomials of the form \( ax^2 + bx + c \). Factoring involves finding two binomials whose product equals the original quadratic expression. This is crucial in simplifying expressions and solving equations.

Here's how you can approach factoring:
  • First, identify if the quadratic expression can be written in the form \( ax^2 + bx + c \).
  • Look for two numbers that multiply to give \( a \times c \) and add to \( b \).
  • Split the middle term accordingly to facilitate factoring by grouping.
  • Once split, group the terms and factor each group independently.
To exemplify, consider the quadratic expression \(4p^2 - 25pq + 6q^2\). Here, we needed to find numbers that multiply to \(24q^2\) and add to \(-25q\). These numbers were \(-24q\) and \(-1q\), allowing us to rewrite and factor by grouping.
Quadratic Formula
The quadratic formula is a powerful tool for solving quadratic equations of the form \( ax^2 + bx + c = 0 \). This formula provides a direct way to find the roots of any quadratic equation without needing to factor directly.

The quadratic formula is given by:\[ x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \]This formula comes from completing the square process and works for any discriminant (\(b^2 - 4ac\)) value, whether it's positive, zero, or negative.

Key points to consider:
  • If the discriminant \(b^2 - 4ac > 0\), there are two real and distinct solutions.
  • If \(b^2 - 4ac = 0\), there is exactly one real solution.
  • If \(b^2 - 4ac < 0\), there are no real solutions, only complex ones.
Although in our exercise we did not use the quadratic formula to solve, understanding it provides a comprehensive approach to tackling quadratic problems.
Polynomial Factorization
Polynomial factorization involves breaking down a polynomial into simpler terms, or "factors," that when multiplied together, give the original polynomial. It's a crucial skill, especially when working with higher-degree polynomials.

Methods to factor polynomials include:
  • Looking for a greatest common factor (GCF) that is shared by all terms.
  • Using special factoring techniques like difference of squares, perfect square trinomials, or sum/difference of cubes.
  • Applying factoring by grouping, especially for 4-term polynomials.
In our original exercise, polynomial factorization involved recognizing the structure of the expression as quadratic in nature and applying the appropriate method—factoring by grouping. The expression \(4p^2 - 25pq + 6q^2\) was rewritten and grouped to achieve a completely factored form: \((4p-q)(p-6q)\). Understanding when to use each factoring method will significantly enhance your ability to simplify and solve polynomial expressions efficiently.

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