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Solve for \(u\) and \(v\) and then solve for \(x\) and \(y\). In this way, we see how to solve systems of equations involving reciprocals. $$\begin{aligned} &\frac{1}{x}+\frac{1}{y}=3\\\ &\frac{2}{x}+\frac{1}{y}=1 \end{aligned}$$

Short Answer

Expert verified
\( x = -\frac{1}{2} \) and \( y = \frac{1}{5} \).

Step by step solution

01

Introduce Variables for Reciprocals

Let \( u = \frac{1}{x} \) and \( v = \frac{1}{y} \). These substitutions can simplify the equations for solving.
02

Rewrite the Equations Using New Variables

Using \( u \) and \( v \), rewrite the system of equations as:\[ \begin{aligned} &u + v = 3 \ &2u + v = 1 \end{aligned} \]This is now a simpler system of linear equations.
03

Solve for One Variable

Subtract the first equation \( u + v = 3 \) from the second equation \( 2u + v = 1 \):\[ (2u + v) - (u + v) = 1 - 3 \]This simplifies to \( u = -2 \).
04

Substitute Back to Find the Other Variable

Substitute \( u = -2 \) back into the first equation \( u + v = 3 \):\[ -2 + v = 3 \]Solving for \( v \), we get \( v = 5 \).
05

Substitute Back to Original Variables

Recall that \( u = \frac{1}{x} \) and \( v = \frac{1}{y} \). So, \( \frac{1}{x} = -2 \) and \( \frac{1}{y} = 5 \).
06

Solve for \( x \) and \( y \)

Taking the reciprocal gives us \( x = \frac{1}{-2} = -\frac{1}{2} \) and \( y = \frac{1}{5} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Reciprocals
Reciprocals are a fundamental concept in mathematics that help to simplify complex expressions. A reciprocal of a number or variable is simply the inverse of that number. For example, the reciprocal of a number \( x \) is \( \frac{1}{x} \). If \( x \) is any nonzero number, multiplying it by its reciprocal yields 1, i.e., \( x \times \frac{1}{x} = 1 \). This property is particularly useful when dealing with fractions and solving equations that include reciprocals.

In systems of equations, introducing variables as reciprocals can transform complicated terms into simpler linear expressions. For instance, by letting \( u = \frac{1}{x} \) and \( v = \frac{1}{y} \), we can change a system involving reciprocals into one that is easier to manipulate.
Linear Equations
Understanding linear equations is key when solving systems of equations. A linear equation is any equation that can be written in the form \( ax + by = c \). In this form, the equation represents a straight line when graphed on a coordinate plane. Linear equations typically involve constants and variables, and do not include powers greater than one or products of variables.

When reciprocals are involved, transforming a system of complex equations into linear ones, as we did by introducing \( u \) and \( v \), allows us to leverage simple algebraic methods. The rewritten system becomes straightforward to solve due to its linear nature.
Variables and Substitutions
The concept of variables and substitutions is a powerful tool in solving equations. Variables act as placeholders for unknown values that we aim to determine. In the context of reciprocals and linear equations, substitutions are often used to simplify the problem.

By assigning variables to represent reciprocals, such as \( u = \frac{1}{x} \) and \( v = \frac{1}{y} \), we simplify each equation's form. This makes it easier to solve because it reduces the number of operations we need to perform. Substituting back once a solution is found allows us to express the original variables \( x \) and \( y \) in terms of easily solvable reciprocal values.
Solving Equations
Solving equations often involves a series of logical steps to find the values of one or more unknown variables. The process begins by identifying the type of equations presented and choosing an appropriate strategy, such as substitution or elimination.

For the given exercise, using subtraction helps simplify the linear equations further, as shown when obtaining \( u = -2 \) by subtracting the transformed equations. Once one variable is known, substituting it back into one of the equations provides the solution for the second variable. Finally, taking the reciprocal of these solutions lets us solve for the original variable values, \( x \) and \( y \).
  • Start by simplifying and rewriting equations.
  • Use algebraic methods like substitution.
  • Find the solution for one variable and use it to find others.
Thus, solving systems of equations often involves creative use of algebraic techniques and transformations to tackle initially complex problems.

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Most popular questions from this chapter

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