Chapter 31: Problem 41
Solve the given problems. On a wildlife refuge, the deer population grows at a rate of \(10 \%\) per year due to reproduction. However, approximately 20 deer are hit and killed by cars each year. Therefore, the rate of growth is given by \(\frac{d P}{d t}=0.1 P-20,\) where \(P\) is the population of deer and \(t\) is the time in years. Express \(P\) as a function of \(t\).
Short Answer
Step by step solution
Understand the Differential Equation
Separate Variables
Integrate Both Sides
Solve for \(P\)
Isolate \(P\)
Include Initial Conditions If Given
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Population Growth
By modeling this population change with a differential equation, {\[\frac{dP}{dt} = 0.1P - 20\], we gain insights into how growth dynamics can be mathematically expressed and analyzed. The equation tells us that the population rate directly depends on the current number of deer, making it a perfect example of exponential growth tempered by a fixed downward adjustment due to car accidents.
Integration
- The left side of the equation integrates to \(\frac{1}{0.1} \ln|0.1P - 20|\), this step involves finding an antiderivative that simplifies the fraction into a manageable form.
- On the other side, the integral of \(dt\)results in \(t + C\), where \(C\)is the constant of integration.
Separation of Variables
- Reorganize terms: \(\frac{dP}{0.1P - 20} = dt\)This crucial process simplifies the problem and separates it into two parts that can be integrated independently.
Mathematical Modeling
- The model: \(\frac{dP}{dt} = 0.1P - 20\)encapsulates these dynamics, creating a simplified mathematical representation of a complex biological process.
Through mathematical modeling, one can make predictions, guide decisions, or evaluate possible solutions to problems, enabling a better understanding and management of the real-world phenomena.