Chapter 31: Problem 20
Solve the given differential equations. $$y^{\prime}-2 y=2 e^{2 x}$$
Short Answer
Expert verified
The solution is \( y = e^{2x}(2x + C) \).
Step by step solution
01
Identify the type of differential equation
The given differential equation is \( y' - 2y = 2e^{2x} \). This is a first-order linear differential equation.
02
Write the equation in standard linear form
Ensure the equation is in the form \( y' + Py = Q \). For this equation, it is already in the correct form with \( P = -2 \) and \( Q = 2e^{2x} \).
03
Determine the integrating factor
The integrating factor \( \,\mu(x) \,\) is given by \( e^{\int P \,dx} \). Hence, \( \mu(x) = e^{-2x} \).
04
Multiply through by the integrating factor
Multiply the entire differential equation by the integrating factor: \[e ^{-2x} y' - 2e^{-2x} y = 2 \].
05
Recognize the left side as a derivative
The left side of the equation, \( e^{-2x} y' - 2e^{-2x} y \), can be rewritten as the derivative: \( \frac{d}{dx}(e^{-2x} y) \).
06
Integrate both sides
Integrate both sides with respect to \( x \):\[ \int \frac{d}{dx} (e^{-2x} y) \, dx = \int 2 \, dx \].This results in \( e^{-2x} y = 2x + C \) where \( C \) is a constant of integration.
07
Solve for \( y \)
Solve the equation \( e^{-2x} y = 2x + C \) for \( y \):\[ y = e^{2x} (2x + C) \].
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Integrating Factor
To solve first-order linear differential equations, one technique is using an integrating factor. This method is especially useful for equations that can be expressed in the form \( y' + Py = Q \). When you have such an equation, the goal is to make the left side of the equation easily integrable.
### Creating the Integrating FactorThe integrating factor \( \mu(x) \) is derived from the exponential function. It's written as:
The true magic happens after this. By multiplying the entire differential equation by \( \mu(x) \), you turn it into a form that simplifies the integration process, reducing it to a straightforward derivative. This approach makes solving complex equations much more manageable.
### Creating the Integrating FactorThe integrating factor \( \mu(x) \) is derived from the exponential function. It's written as:
- \( \mu(x) = e^{\int P \,dx} \)
The true magic happens after this. By multiplying the entire differential equation by \( \mu(x) \), you turn it into a form that simplifies the integration process, reducing it to a straightforward derivative. This approach makes solving complex equations much more manageable.
Constant of Integration
In calculus and differential equations, integration often introduces a special constant, known as the constant of integration. It represents an entire family of solutions, as the process of differentiation effectively removes this constant.
### Emergence of the ConstantDuring integration, particularly when solving differential equations, the constant \( C \) arises. Consider integrating both sides of an equation, like we did in our example:
### Role of the ConstantThis constant helps describe all possible solutions to the differential equation. Without confining initial conditions or additional criteria, this constant remains arbitrary, giving a general solution. It's only when specific initial conditions are present that \( C \) can be determined precisely.
### Emergence of the ConstantDuring integration, particularly when solving differential equations, the constant \( C \) arises. Consider integrating both sides of an equation, like we did in our example:
- \( \int \frac{d}{dx} (e^{-2x} y) \, dx = \int 2 \, dx \)
### Role of the ConstantThis constant helps describe all possible solutions to the differential equation. Without confining initial conditions or additional criteria, this constant remains arbitrary, giving a general solution. It's only when specific initial conditions are present that \( C \) can be determined precisely.
Standard Linear Form
The process of solving a differential equation benefits greatly from the equation being in standard linear form. This type of form clearly distinguishes the components of the equation, making it easier to manipulate mathematically.
### Defining Standard Linear FormFor a first-order linear differential equation, the standard form is:
In our initial equation \( y' - 2y = 2e^{2x} \), rewriting it as \( y' + (-2)y = 2e^{2x} \) shows that it’s already in standard linear form, with \( P = -2 \) and \( Q = 2e^{2x} \).
Having an equation in this tidy format paves the way for implementing methods like the integrating factor seamlessly. It’s akin to organizing ingredients before baking – it helps ensure everything you need is right in front of you, organized and ready to use.
### Defining Standard Linear FormFor a first-order linear differential equation, the standard form is:
- \( y' + Py = Q \)
In our initial equation \( y' - 2y = 2e^{2x} \), rewriting it as \( y' + (-2)y = 2e^{2x} \) shows that it’s already in standard linear form, with \( P = -2 \) and \( Q = 2e^{2x} \).
Having an equation in this tidy format paves the way for implementing methods like the integrating factor seamlessly. It’s akin to organizing ingredients before baking – it helps ensure everything you need is right in front of you, organized and ready to use.