Chapter 31: Problem 20
Show that the given equation is a solution of the given differential equation. $$x y^{\prime}-3 y=x^{2}, \quad y=c x^{3}-x^{2}$$
Short Answer
Expert verified
The function \( y = cx^3 - x^2 \) satisfies the differential equation.
Step by step solution
01
Identify the Given Functions and Derivatives
First, identify the functions given in the problem. We have a differential equation \( x y' - 3y = x^2 \) and a potential solution \( y = cx^3 - x^2 \).Differentiate the given function \( y \) with respect to \( x \) to find \( y' \).
02
Differentiate the Given Function
Calculate the derivative of \( y = cx^3 - x^2 \) with respect to \( x \) to find \( y' \).\[ y' = \frac{d}{dx}(cx^3 - x^2) = 3cx^2 - 2x \]
03
Substitute into the Differential Equation
Now substitute \( y = cx^3 - x^2 \) and \( y' = 3cx^2 - 2x \) into the differential equation \( x y' - 3y = x^2 \).This gives us:\[ x(3cx^2 - 2x) - 3(cx^3 - x^2) = x^2 \]
04
Simplify the Equation
Expand the terms:1. Compute \( x(3cx^2 - 2x) = 3cx^3 - 2x^2 \).2. Compute \( 3(cx^3 - x^2) = 3cx^3 - 3x^2 \).Substitute these back into the equation:\[ 3cx^3 - 2x^2 - 3cx^3 + 3x^2 = x^2 \]
05
Combine Like Terms
Combine like terms in the equation:\[ 3cx^3 - 3cx^3 - 2x^2 + 3x^2 = x^2 \]Which simplifies to:\[ x^2 = x^2 \]
06
Verify the Solution
Since both sides of the equation equal \( x^2 \), the original function \( y = cx^3 - x^2 \) is indeed a solution to the differential equation.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Solution Verification
Verifying a solution to a differential equation involves ensuring that the proposed function satisfies the equation. In this case, our goal is to prove that \( y = cx^3 - x^2 \) is a solution to the differential equation \( x y' - 3y = x^2 \). By substituting \( y = cx^3 - x^2 \) and its derivative \( y' = 3cx^2 - 2x \) into the differential equation, we check if the two sides become equal.
- Substitute \( y \) and \( y' \) into the differential equation.
- Simplify both sides of the equation.
- If the left-hand side equals the right-hand side, verification is successful.
Differentiation
Differentiation is a fundamental concept in calculus that allows us to determine how a function changes at any given point. In the context of this problem, we need to find the derivative of a potential solution to check if it satisfies the differential equation. The given expression for \( y \) is \( y = cx^3 - x^2 \).
- Apply differentiation rules: the power rule, where the derivative of \( x^n \) is \( nx^{n-1} \).
- Calculate the derivative of \( y \): \( y' = 3cx^2 - 2x \).
Substitution Method
The substitution method in solving differential equations involves replacing the function and its derivative with their respective expressions in terms of \( x \). This technique is particularly helpful in simplifying and solving equations to check the validity of a potential solution.
- Substitute \( y = cx^3 - x^2 \) into the differential equation.
- Replace \( y' \) with its derivative, \( 3cx^2 - 2x \).
- Simplify the equation using basic algebraic manipulation.
Mathematical Proofs
Mathematical proofs are logical arguments that validate the truth of a mathematical statement. In verifying a solution for a differential equation, the proof involves showing that substituting the function and its derivative results in an identity or equality.
- Start by writing the differential equation and the proposed solution.
- Substitute and simplify each side to see if they match.
- If after simplification both sides are equal, a proof confirming the solution is achieved.