/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 36 Determine the appropriate functi... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Determine the appropriate functions. A satellite telephone is leased at a cost \(C\) of \(\$ 200\) plus \(\$ 10\) per minute \(t\) the phone is used. For \(t=f(C),\) find \(f(500)\)

Short Answer

Expert verified
The satellite phone is used for 30 minutes.

Step by step solution

01

Understanding the Problem Statement

We need to find a function for the minutes of call time, \(t\), based on the cost, \(C\). The cost is given by: \(C = 200 + 10t\). We are tasked with finding \(f(500)\), where \(f\) is the function describing minutes as a function of cost.
02

Express the Given Cost Equation in Terms of t

We start with the given equation \(C = 200 + 10t\). Our goal is to express \(t\) as a function of \(C\). So, isolate \(t\) by subtracting \(200\) from both sides: \(C - 200 = 10t\).
03

Solve for t in Terms of C

Now, we solve for \(t\) by dividing both sides by \(10\): \(t = \frac{C - 200}{10}\). This is the function \(f(C)\) we were looking for: \(f(C) = \frac{C - 200}{10}\).
04

Calculate f(500)

To find \(f(500)\), substitute \(C = 500\) into the function \(f(C) = \frac{C - 200}{10}\). Calculate: \(f(500) = \frac{500 - 200}{10} = \frac{300}{10} = 30\).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Linear Functions
Linear functions are mathematical expressions that create straight lines when plotted on a graph. In its most standard form, it is written as \( y = mx + b \), where \( m \) is the slope of the line and \( b \) is the y-intercept. This function shows a constant rate of change, meaning the change in \( y \) is proportional to the change in \( x \).
For the given problem, the original cost equation is a linear function \( C = 200 + 10t \). Here, 200 is the y-intercept, which represents the starting cost when no minutes are used. The slope is 10, indicating that for every additional minute, the cost increases by $10. Understanding the linear function's slope and y-intercept is crucial for interpreting real-world problems like cost analysis in business scenarios.
Inverse Functions
Inverse functions reverse the roles of inputs and outputs. When given a function \( f(x) \), finding its inverse, written as \( f^{-1}(x) \), involves swapping the input variable for the output variable. Inverse functions are useful when you need to determine the original input from a given output.
In our exercise, the cost function \( C = 200 + 10t \) describes cost \( C \) in terms of minutes \( t \). To find the function \( t = f(C) \), we perform the inverse operation. We respected the inverse process by reorganizing the formula to get \( t = \frac{C-200}{10} \). This way, given a specific cost, you can determine how many minutes were used, emphasizing the utilitarian aspect of inverse functions in everyday decision-making.
Cost Functions
Cost functions are mathematical models that describe how cost rises with certain variables. In business and economics, these functions are critical for predicting expenses based on factors like production or services rendered.
In this case, \( C = 200 + 10t \) is the cost function comprising a fixed cost of \(200 and a variable cost of \)10 per minute of phone use. The fixed cost is the initial expense irrespective of usage time, an essential factor when budgeting. The variable cost changes with the level of service usage, here quantified by the number of minutes spent on a call.
These elements of fixed and variable costs commonly appear in various user-centric services, affecting pricing strategies and consumer understanding of service charges.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Use the following table, which gives the fraction (as a decimal) of the total heating load of a certain system that will be supplied by a solar collector of area \(A\) (in \(\mathrm{m}^{2}\) ). Find the indicated values by linear interpolation. $$\begin{array}{l|c|c|c|c|c|c|c}f & 0.22 & 0.30 & 0.37 & 0.44 & 0.50 & 0.56 & 0.61 \\\\\hline A\left(\mathrm{m}^{2}\right) & 20 & 30 & 40 & 50 & 60 & 70 & 80\end{array}$$. For \(f=0.27,\) find \(A\).

Solve the indicated equations graphically. Assume all data are accurate to two significant digits unless greater accuracy is given. The length of a rectangular solar panel is \(12 \mathrm{cm}\) more than its width. If its area is \(520 \mathrm{cm}^{2},\) find its dimensions.

Use the following table that gives the rate R of discharge from a tank of water as a function of the height \(H\) of water in the tank. For Exercises 19 and \(20,\) plot the graph and find the values from the graph. For Exercises 21 and \(22,\) find the indicated values by linear interpolation. $$\begin{array}{l|c|c|c|c|c|c|c}\text {Height}(\mathrm{ft}) & 0 & 1.0 & 2.0 & 4.0 & 6.0 & 8.0 & 12 \\ \hline \text {Rate }\left(\mathrm{ft}^{3} / \mathrm{s}\right) & 0 & 10 & 15 & 22 & 27 & 31 & 35 \end{array}$$. Find \(R\) for \(H=1.7 \mathrm{ft}\).

A function and how it is to be shifted is given. Find the shifted function, and then display the given function and the shifted function on the same screen of a graphing calculator. $$y=3 x, \text { up } 1$$

Solve the given problems. The pressure loss \(L\) (in \(\mathrm{Ib} / \mathrm{in} .^{2}\) ) of a fire hose as a function of its flow rate \(Q\) (in 100 gal/min) is \(L=1.2 Q^{2}+1.5 Q\). Find \(L\) for \(Q=450 \mathrm{gal} / \mathrm{min}\).

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.