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Find the domain and range of the given functions. $$T(t)=2 t^{4}+t^{2}-1$$

Short Answer

Expert verified
Domain: \((-\infty, \infty)\), Range: \([-1, \infty)\)

Step by step solution

01

Understanding the Domain

The domain of a real-valued function consists of all real numbers for which the function is defined. Since the function is a polynomial, it is defined for all real numbers. Therefore, the domain of the function \( T(t) = 2t^4 + t^2 - 1 \) is all real numbers, expressed as \( (-\infty, \infty) \).
02

Identifying the Range Characteristics

To determine the range of the polynomial \( T(t) = 2t^4 + t^2 - 1 \), we note that both terms \( 2t^4 \) and \( t^2 \) are non-negative for all real \( t \), and the term \( 2t^4 \) dominates as \( t \) becomes larger because it is the highest degree term. This polynomial opens upwards because the coefficient of \( t^4 \) is positive.
03

Finding the Minimum Point

Since the polynomial opens upwards and has even degree, it has a minimum point. To find this minimum point, we compute the first derivative \( T'(t) = 8t^3 + 2t \) and set it to zero. Solving \( 8t^3 + 2t = 0 \) gives \( t(8t^2 + 2) = 0 \), which has solutions \( t = 0 \), since \( 8t^2 + 2 \) cannot be zero (as the quadratic's discriminant is negative).
04

Evaluating the Function at Critical Points

We evaluate \( T(t) \) at the critical point \( t = 0 \) to find the local minimum value. Substituting \( t = 0 \) into \( T(t) \), we get \( T(0) = 2(0)^4 + (0)^2 - 1 = -1 \). This local minimum helps in determining the range.
05

Determining the Range

Since the polynomial \( T(t) \) opens upwards and has minimum value \( T(0) = -1 \), the range of the function consists of all values \( y \) such that \( y \geq -1 \). Therefore, the range is \([ -1, \infty) \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Polynomial Functions
Polynomial functions are mathematical expressions involving a sum of powers of a variable, each multiplied by a coefficient. The general format for a polynomial function might look like this:
  • \( f(x) = a_n x^n + a_{n-1} x^{n-1} + \ldots + a_1 x + a_0 \)
Where:
  • \( a_n, a_{n-1}, \ldots, a_1, a_0 \) are constants called coefficients.
  • \( n \) is a non-negative integer.
Polynomial functions are important because they are continuous and differentiable, which means they can be used to model a wide range of real-world phenomena. In the exercise, the polynomial function is given by \( T(t) = 2t^4 + t^2 - 1 \). This is a quartic polynomial, meaning the highest power of \( t \) is four.
Real-Valued Functions
Real-valued functions are those where the input domain contains real numbers, and the output range gives real numbers as well. They are fundamental in describing real-world situations because they can take any value on the real number line.
In practical terms, for a real-valued function, you can input any real number, and the result will always be a real number. The given function, \( T(t) = 2t^4 + t^2 - 1 \), is real-valued since it is defined and outputs real numbers for all \( t \in \mathbb{R} \).
Understanding the domain of real-valued functions, especially polynomial ones like in this exercise, is straightforward because they are typically defined for all real numbers, meaning their domain is \( (-\infty, \infty) \).
Derivative
The derivative of a function represents the rate of change of the function's output with respect to its input. It tells us how fast or slow a function is changing at any given point. The derivative is often denoted as \( f'(x) \) or \( \frac{df}{dx} \).
For polynomial functions, derivatives can easily be computed using the power rule, which states that if \( f(x) = ax^n \), then \( f'(x) = n \cdot ax^{n-1} \). In the exercise, the derivative of \( T(t) = 2t^4 + t^2 - 1 \) is found to be \( T'(t) = 8t^3 + 2t \). This derivative will help identify critical points where the function might have a maximum, minimum, or a point of inflection.
When the derivative equals zero, these points are called critical points.
Critical Points
Critical points of a function are the points where the first derivative is zero or undefined. These points are significant because they can indicate where the function has a local maximum, local minimum, or a saddle point.
In the exercise, to find the critical points of \( T(t) = 2t^4 + t^2 - 1 \), we set its derivative \( T'(t) = 8t^3 + 2t \) equal to zero, getting \( t(8t^2 + 2) = 0 \). Solving this yields \( t = 0 \) as the critical point since \( 8t^2 + 2 \) does not equate to zero.
Evaluating the function at this critical point, \( T(0) = -1 \) shows that it corresponds to a local minimum of the function. This information is crucial to finding the range of the polynomial, as the range starts from this minimum value at \( -1 \) and goes to infinity, i.e., \( [ -1, \infty) \).

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