Chapter 28: Problem 5
Integrate each of the given functions. $$\int 4 e^{2 x+5} d x$$
Short Answer
Expert verified
The integral is \(2e^{2x+5} + C\).
Step by step solution
01
Simplifying the Integrand
Notice that the function to be integrated is given as \( 4e^{2x+5} \). We can simplify this expression by considering a substitution to make integration easier. Recognize that \( e^{2x+5} = e^{2x} imes e^5 \) as per the rules of exponents.
02
Make a Substitution
To simplify the integration, let's use substitution. Set \( u = 2x + 5 \), then the derivative of \( u \) with respect to \( x \) is \( \frac{du}{dx} = 2 \). Therefore, \( dx = \frac{du}{2} \). Substitute these into the integral.
03
Transforming the Integral
Substitute the values from Step 2 into the original integral:\[\int 4e^{2x+5} \, dx = 4 \int e^u \times \frac{du}{2} \]This simplifies to:\[2 \int e^u \, du \]
04
Integrate Using Known Formula
Now, integrate \( 2 \int e^u \, du \). It is well-known that \( \int e^u \ du = e^u + C \), where \( C \) is the constant of integration. Therefore, the integral becomes:\[2e^u + C \]
05
Substitute Back to Original Variable
Finally, substitute back \( u = 2x + 5 \) into the expression to get the final result:\[2e^{2x+5} + C\]
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Substitution Method
The substitution method is a fundamental technique in calculus used to simplify integration. It helps to transform a complex integral into a more manageable form. Here's how it works:
For example, in the exercise, the expression \( 4e^{2x+5} \) was simplified by setting \( u = 2x + 5 \). This changed the variable of integration from \( x \) to \( u \), making it easier to integrate. The derivative \( \frac{du}{dx} = 2 \) allowed us to replace \( dx \) with \( \frac{du}{2} \), simplifying the integration process.
The substitution method streamlines the calculation by reducing possible algebraic complexity, allowing focus on simpler integrals.
- Identify a part of the integral that can be replaced with a simpler variable, typically denoted as \( u \).
- Find the derivative of this part, which will help in replacing \( dx \) in the integral with \( du \).
- This method is particularly useful when dealing with composite functions, where a function is nested within another function.
For example, in the exercise, the expression \( 4e^{2x+5} \) was simplified by setting \( u = 2x + 5 \). This changed the variable of integration from \( x \) to \( u \), making it easier to integrate. The derivative \( \frac{du}{dx} = 2 \) allowed us to replace \( dx \) with \( \frac{du}{2} \), simplifying the integration process.
The substitution method streamlines the calculation by reducing possible algebraic complexity, allowing focus on simpler integrals.
Exponential Functions
Exponential functions are functions of the form \( e^{g(x)} \), where \( e \) is Euler's number, approximately equal to 2.718, and \( g(x) \) is any function of \( x \). These functions exhibit rapid growth or decay and have unique properties that make them interesting in calculus.
In the problem provided, the expression \( e^{2x+5} \) inherently includes both the exponential base \( e \) and the linear expression \( 2x+5 \). Transforming such expressions using the substitution method simplifies integration, as seen when \( e^{2x+5} \) becomes \( e^u \), reducing the complexity.
- The derivative and the integral of \( e^x \) are both \( e^x \). This property makes exponential functions easy to differentiate and integrate once transformed appropriately.
- In the context of integration, transformations often utilize exponential functions due to their continuous compounding nature, found in many natural growth and decay processes.
In the problem provided, the expression \( e^{2x+5} \) inherently includes both the exponential base \( e \) and the linear expression \( 2x+5 \). Transforming such expressions using the substitution method simplifies integration, as seen when \( e^{2x+5} \) becomes \( e^u \), reducing the complexity.
Integration by Substitution
Integration by substitution is a specific technique utilized to solve integrals that aren't straightforward. It's especially beneficial when dealing with complex exponentials, such as those involving \( e^{2x+5} \), as we saw in the exercise.
By performing a substitution:
For instance, when solving the integral \( \int 4e^{2x+5} \, dx \), using \( u = 2x + 5 \) turns the integral into \( 2 \int e^u \, du \). This process reveals the simpler integral form, allowing us to apply the known formula \( \int e^u \, du = e^u + C \). Hence, after integrating, we revert back to \( x \) by substituting \( u \) back to \( 2x + 5 \), obtaining the final result \( 2e^{2x+5} + C \).
This method not only simplifies the computational process but also provides clarity when navigating through complex functions.
By performing a substitution:
- Transform the integral into a simpler form, leveraging known integral formulas.
- Focus on the new integral in terms of \( u \) after the substitution of variables has been done.
- Once integrated in terms of \( u \), convert it back to the original variable.
For instance, when solving the integral \( \int 4e^{2x+5} \, dx \), using \( u = 2x + 5 \) turns the integral into \( 2 \int e^u \, du \). This process reveals the simpler integral form, allowing us to apply the known formula \( \int e^u \, du = e^u + C \). Hence, after integrating, we revert back to \( x \) by substituting \( u \) back to \( 2x + 5 \), obtaining the final result \( 2e^{2x+5} + C \).
This method not only simplifies the computational process but also provides clarity when navigating through complex functions.