Chapter 28: Problem 17
Integrate each of the functions. $$\int[\ln (x+1)]^{2} \frac{d x}{x+1}$$
Short Answer
Expert verified
\( \int [\ln(x+1)]^2 \frac{dx}{x+1} = \frac{[\ln(x+1)]^3}{3} + C \).
Step by step solution
01
Simplify the Integral
Start by examining the integral \( \int [\ln(x+1)]^2 \frac{dx}{x+1} \). We can simplify it by letting \( u = \ln(x+1) \). This substitution simplifies \( dx \) to \( du = \frac{1}{x+1} \, dx \), which matches the \( \frac{dx}{x+1} \) in the integral. This transforms the integral to \( \int u^2 \, du \).
02
Integrate with Respect to u
Integrate \( u^2 \) with respect to \( u \). The integral of \( u^n \) is \( \frac{u^{n+1}}{n+1} \) for \( n eq -1 \). Thus, \( \int u^2 \, du = \frac{u^3}{3} + C \), where \( C \) is the constant of integration.
03
Substitute Back in Terms of x
Replace \( u \) back with \( \ln(x+1) \) to transform the integral back in terms of \( x \). The result is \( \frac{[\ln(x+1)]^3}{3} + C \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Substitution Method
The substitution method is a powerful technique used in calculus to simplify complex integrals. This method often involves changing variables to transform a difficult integral into an easier one. For instance, in the original exercise, the substitution was made by letting \( u = \ln(x+1) \).
This new variable \( u \) replaces the original expression to make integration straightforward. Here's why substitution works:
Consequently, substitution is an essential method for handling intricate expressions and facilitating integration.
This new variable \( u \) replaces the original expression to make integration straightforward. Here's why substitution works:
- Transforms and simplifies the integration process.
- It matches the transformation with parts of the integral already present, which makes it easier to solve.
- The differential \( du \) is derived from the new substitution, where \( du = \frac{1}{x+1} \, dx \). This perfectly aligns with the integral's differential part \( \frac{dx}{x+1} \).
Consequently, substitution is an essential method for handling intricate expressions and facilitating integration.
Definite Integral
A definite integral signifies the computation of the area under a curve defined by a function, over a specified interval \([a, b]\). Despite not featuring in this particular exercise, understanding definite integrals is crucial in calculus.
It is frequently represented as \( \int_{a}^{b} f(x) \, dx \). Key features include:
Understanding definite integrals not only helps in calculating indicative numeric outcomes but also in analyzing functions over prescribed intervals.
It is frequently represented as \( \int_{a}^{b} f(x) \, dx \). Key features include:
- The result is a specific value, representing the precise area between the curve and the x-axis, within the bounds.
- It requires the Fundamental Theorem of Calculus which connects differentiation and integration.
- Calculating involves finding the antiderivative of the function and evaluating it at the bounds; that is \( F(b) - F(a) \).
Understanding definite integrals not only helps in calculating indicative numeric outcomes but also in analyzing functions over prescribed intervals.
Indefinite Integral
Indefinite integrals represent a family of functions and are foundational in understanding the process of integration in calculus.
In the exercise given, the integral \( \int [\ln(x+1)]^2 \frac{dx}{x+1} \) was computed as an indefinite integral resulting in \( \frac{[\ln(x+1)]^3}{3} + C \), where \( C \) denotes the constant of integration.
Some key points:
Comprehending indefinite integrals ensures a better grasp of how functions accumulate quantities, a central aspect of integral calculus.
In the exercise given, the integral \( \int [\ln(x+1)]^2 \frac{dx}{x+1} \) was computed as an indefinite integral resulting in \( \frac{[\ln(x+1)]^3}{3} + C \), where \( C \) denotes the constant of integration.
Some key points:
- Unlike definite integrals, indefinite integrals lack limits \(a\) and \(b\); no interval, just the antiderivative.
- The outcome captures all possible antiderivatives of a function, as represented by the arbitrary constant \( C \).
- \( \int f(x) \, dx \) gives a function \( F(x) + C \), meaning \( F(x) \) is the antiderivative of \( f(x) \).
Comprehending indefinite integrals ensures a better grasp of how functions accumulate quantities, a central aspect of integral calculus.