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Find the derivatives of the given functions. $$y=\log _{2} 6 x$$

Short Answer

Expert verified
The derivative of \( y = \log_2(6x) \) is \( \frac{1}{x \ln 2} \).

Step by step solution

01

Recall the Derivative of a Logarithm

To find the derivative of a logarithmic function, we need to remember that the derivative of \( a \log_b(x) \) is \( \frac{a}{x \ln(b)} \). This is because the change in the natural logarithm rule involving a base change.
02

Change of Base Formula

We know that \( \log_b(x) = \frac{\ln(x)}{\ln(b)} \). So, \( \log_2(6x) = \frac{\ln(6x)}{\ln 2} \). Now, our function is expressed with natural logarithms.
03

Derivative of the Natural Logarithm

The derivative of \( \ln(u) \) with respect to \( x \) is \( \frac{1}{u} \frac{du}{dx} \). Here \( u = 6x \) so, \( \frac{d}{dx}(\ln(6x)) = \frac{1}{6x} \cdot 6 = \frac{1}{x} \).
04

Apply the Derivative Formula

Using the derivative formula from Step 3, the derivative of \( \frac{\ln(6x)}{\ln 2} \) is \( \frac{1}{\ln 2} \cdot \frac{1}{x} = \frac{1}{x \ln 2} \).
05

Write the Final Derivative

The derivative of the function \( y = \log_2(6x) \) is \( \frac{1}{x \ln 2} \), which is derived from applying the chain rule and properties of logarithms.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Logarithm
Logarithms are mathematical operations that help us find the exponent needed to raise a specific base to achieve a particular number. In simpler terms, if you have a number "a" and want to find which power you need to raise "b" (the base) to get "a", you use logarithms. For example, if we take the expression \(2^3 = 8\), the corresponding logarithm would be \(\log_2(8) = 3\). This concept extends to various bases, not just to base 10 or base 2.
  • Logarithms allow for simplifying complex multiplicative relationships into simpler additive ones.
  • They have applications in many fields, such as science, engineering, and finance, for growth processes, decay, and interest calculations.
Grasping the idea of logarithms is crucial because they are foundational to understanding more advanced calculus concepts, including differentiating and integrating exponential and logarithmic functions.
Change of Base Formula
Sometimes we need to convert logs of one base to another that's more convenient for calculation, especially when dealing with derivatives. The Change of Base Formula is an essential tool for this. The formula is as follows:\[\log_b(x) = \frac {\ln(x)}{\ln(b)}\]This means that if you have a logarithm of base \(b\) and need to express it in terms of natural logarithms (which are usually easier to differentiate), you can use this conversion. This is how we can rewrite expressions like \(\log_2(6x)\) in terms of the natural logarithm, allowing us to utilize calculus rules more effectively.
  • This formula is useful because most scientific calculators can only calculate common and natural logs.
  • It aids in finding derivatives of logarithmic functions efficiently.
This concept is also significant when working with logarithms in multiple contexts and bases.
Natural Logarithm
The natural logarithm, denoted as \(\ln(x)\), is a logarithm that uses the constant \(e\) (approximately 2.718) as its base. It is notably important because of its simplicity when applied in calculus.
  • \(\ln(x)\) is frequently used in calculus because its derivative is straightforward: \(\frac{1}{x}\).
  • It is the inverse of the exponential function \(e^x\). This inversion property allows for simplifications in exponential equations.
In calculus, natural logarithms are favored due to their convenient properties when differentiating and integrating, particularly with exponential and logarithmic functions. The natural logarithm plays a key role in continuously compounded interest and naturally occurring growth or decay processes.
Chain Rule
The Chain Rule is a fundamental concept in calculus used to differentiate composite functions. A composite function is a function within another function, and the chain rule allows us to take derivatives of such functions efficiently. Mathematically, if you have a function \(y = g(f(x))\), the derivative \(\frac{dy}{dx}\) is given by\[\frac{dy}{dx} = g'(f(x)) \cdot f'(x)\]This rule states that you take the derivative of the outer function \(g\) evaluated at the inner function \(f(x)\) and multiply it by the derivative of the inner function \(f\).
  • This technique is crucial when dealing with layered functions, such as exponential, logarithmic, and trigonometric functions.
  • It is commonly covered in the context of implicit differentiation as well.
The chain rule was applied in the derivation of the logarithmic function in the exercise, enabling us to successfully find the derivative of \(\log_2(6x)\). It is an essential toolkit for solving complex differentiation problems in calculus.

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Most popular questions from this chapter

Solve the given problems by finding the appropriate derivative. A metal bar is heated, and then allowed to cool. Its temperature \(T\) \(\left(\text { in }^{\circ} \mathrm{C}\right)\) is found to be \(T=15+75 e^{-0.25 t},\) where \(t\) (in min) is the time of cooling. Find the time rate of change of temperature after 5.0 min.

Solve the given problems. Display the graph of \(y=e^{x}\) on a calculator. Using the derivative feature, evaluate \(d y / d x\) for \(x=2\) and compare with the value of \(y\) for \(x=2\).

When air friction is considered, the time \(t\) (in s) it takes a certain falling object to attain a velocity \(v\) (in ft/s) is given by \(t=5 \ln \frac{16}{16-0.1 v} \cdot\) Find \(d t / d v\) for \(v=100 \mathrm{ft} / \mathrm{s}\).

Use the following information. The hyperbolic sine of \(u\) is defined as \(\sinh u=\frac{1}{2}\left(e^{u}-e^{-u}\right)\) Figure 27.30 shows the graph of \(y=\sinh x\). The hyperbolic cosine of \(u\) is defined as \(\cosh u=\frac{1}{2}\left(e^{u}+e^{-u}\right)\) Figure 27.31 shows the graph of \(y=\cosh x\). These functions are called hyperbolic functions since, if \(x=\cosh u\) and \(y=\sinh u, x\) and \(y\) satisfy the equation of the hyperbola \(x^{2}-y^{2}=1\). Verify the fact that the exponential expressions for the hyperbolic sine and hyperbolic cosine given above satisfy the equation of the hyperbola.

Solve the given problems. A camera is on the starting line of a drag race \(15.0 \mathrm{m}\) from a racing car. After 1.5 s the car has traveled \(30.0 \mathrm{m}\) and the camera is rotating at 0.75 rad/s while filming the car. What is the speed of the car at this time?

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