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Integrate each of the given expressions. $$\int \frac{2 x^{2} d x}{\sqrt{2 x^{3}+1}}$$

Short Answer

Expert verified
\( \int \frac{2x^2 \, dx}{\sqrt{2x^3 + 1}} = \frac{2}{3} \sqrt{2x^3 + 1} + C \)

Step by step solution

01

Identify the Integral Type

The integral \( \int \frac{2x^2 \, dx}{\sqrt{2x^3 + 1}} \) requires substitution due to the composite function inside the square root. Notice that the expression under the square root is \( 2x^3 + 1 \), which suggests a substitution approach.
02

Choose an Appropriate Substitution

Set \( u = 2x^3 + 1 \). Then, compute the derivative of \( u \) with respect to \( x \): \( \frac{du}{dx} = 6x^2 \), so \( du = 6x^2 \, dx \). Therefore, \( x^2 \, dx = \frac{1}{6} \, du \).
03

Substitute and Simplify the Integral

Substituting \( u = 2x^3 + 1 \) into the integral, we have: \[ \int \frac{2x^2 \, dx}{\sqrt{u}} \] Substitute \( x^2 \, dx = \frac{1}{6} \, du \), then: \[ \int \frac{2 \times \frac{1}{6} \, du}{\sqrt{u}} = \frac{1}{3} \int u^{-1/2} \, du \].
04

Integrate With Respect to \( u \)

The integral \( \int u^{-1/2} \, du \) can be solved using the power rule for integrals: \[ \int u^{n} \, du = \frac{u^{n+1}}{n+1} + C \], where \( n eq -1 \). In our case, \( n = -1/2 \): \[ \frac{1}{3} \left[ \frac{u^{1/2}}{1/2} \right] + C = \frac{1}{3} \cdot 2u^{1/2} + C = \frac{2}{3} \sqrt{u} + C \].
05

Back-Substitute in Terms of \( x \)

Replace \( u \) back with the original expression \( 2x^3 + 1 \): \[ \frac{2}{3} \sqrt{2x^3 + 1} + C \]. This gives the final answer for the original integral.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Integration by Substitution
Integration by substitution is a powerful technique used to simplify complicated integrals by changing variables. It is particularly useful when dealing with composite functions, such as when there is an expression inside a function that complicates the integration. The concept is analogous to the chain rule in differentiation. To apply integration by substitution, you typically:
  • Identify a part of the integrand that can be easily switched to a new variable (usually seen as a function followed by its derivative).
  • Choose a suitable substitution, often denoted by setting the troublesome part equal to a new variable, say \( u \).
  • Differentiate your substitution to express everything in terms of \( du \) and adjust your integral accordingly.
  • Solve the new integral in simpler form, then return to the original variables by back-substituting.
In our original exercise, choosing \( u = 2x^3 + 1 \) simplified both the expression under the square root and the remaining part of the integrand, allowing for straightforward substitution.
Power Rule for Integration
The power rule for integration is a fundamental tool that allows us to integrate functions of the form \( x^n \). This rule states that for any real number \( n \) other than \( -1 \), the integral of \( x^n \) with respect to \( x \) is:\[ \int x^n \, dx = \frac{x^{n+1}}{n+1} + C, \]where \( C \) is the constant of integration. If \( n = -1 \), the integral simplifies to the natural logarithm \( \ln{|x|} + C \).
In our problem, once the substitution has been made, the expression transforms into \( u^{-1/2} \). Here, the power rule applies by recognizing \( n = -1/2 \). Solving for this using the power rule provides the integral value, transitioning smoothly back from \( u \) to \( x \) through back-substitution.
Integration Techniques
There are various integration techniques, but knowing which to apply comes with practice and understanding of the integrand form:
  • Integration by Parts: Useful when the integrand is a product of two functions where one can be easily differentiated and the other integrated.
  • Trigonometric Integration: Involves identities and substitutions when dealing with trigonometric functions.
  • Partial Fraction Decomposition: Beneficial for rational functions where the numerator degree is less than the denominator.
  • Integration by Substitution: As detailed earlier, great for reversing the effects of the chain rule.
For the given problem, integration by substitution was the most effective approach because it simplified the integrand from a complicated rational expression into a more basic power function of \( u \). This showcases the importance of selecting the right technique based on the form of the integrand, cruising through to a solution quickly and effectively.

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