Chapter 23: Problem 10
Find the derivative of each of the functions by using the definition. $$y=-\frac{1}{4} x^{2}$$
Short Answer
Expert verified
The derivative of \( y = -\frac{1}{4}x^2 \) is \( y' = -\frac{1}{2}x \).
Step by step solution
01
Recall the Definition of the Derivative
The derivative of a function \( f(x) \) at a point \( x \) is given by the limit definition: \[ f'(x) = \lim_{h \to 0} \frac{f(x+h) - f(x)}{h} \]. We will use this definition to find the derivative of \( y = -\frac{1}{4}x^2 \).
02
Substitute the Function into the Definition
Substitute \( f(x) = -\frac{1}{4}x^2 \) into the limit definition. We need \( f(x + h) \), which will be \( -\frac{1}{4}(x+h)^2 \). Thus, \[ f'(x) = \lim_{h \to 0} \frac{-\frac{1}{4}(x+h)^2 - \left(-\frac{1}{4}x^2\right)}{h} \].
03
Expand and Simplify the Expression
First expand \((x + h)^2\) to get \(x^2 + 2xh + h^2\). Then place it back into the expression:\[ -\frac{1}{4}(x^2 + 2xh + h^2) = -\frac{1}{4}x^2 - \frac{1}{2}xh - \frac{1}{4}h^2 \].Substitute back:\[ \lim_{h \to 0} \frac{-\frac{1}{4}x^2 - \frac{1}{2}xh - \frac{1}{4}h^2 + \frac{1}{4}x^2}{h} \].
04
Simplify Further and Cancel Terms
The expression simplifies to:\[ \lim_{h \to 0} \frac{ -\frac{1}{2}xh - \frac{1}{4}h^2}{h} \].Factor out \(h\) from the numerator:\[ \lim_{h \to 0} \frac{h(-\frac{1}{2}x - \frac{1}{4}h)}{h} \].Cancel \(h\) in the numerator and denominator to get:\[ \lim_{h \to 0} (-\frac{1}{2}x - \frac{1}{4}h) \].
05
Evaluate the Limit
Since \( h \) approaches 0, substitute \( h = 0 \) into the expression:\[ -\frac{1}{2}x - \frac{1}{4}(0) = -\frac{1}{2}x \].Thus, the derivative of \( y = -\frac{1}{4}x^2 \) is \( y' = -\frac{1}{2}x \).
Unlock Step-by-Step Solutions & Ace Your Exams!
-
Full Textbook Solutions
Get detailed explanations and key concepts
-
Unlimited Al creation
Al flashcards, explanations, exams and more...
-
Ads-free access
To over 500 millions flashcards
-
Money-back guarantee
We refund you if you fail your exam.
Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Understanding the Limit Definition of a Derivative
The derivative of a function at a particular point gives us the function's slope or rate of change at that specific location. To understand what this means, we utilize the limit definition of a derivative.
In simple terms, the limit definition provides a formula to find the derivative by considering how the function behaves as it approaches a given point.Here's the limit definition of the derivative:
In simple terms, the limit definition provides a formula to find the derivative by considering how the function behaves as it approaches a given point.Here's the limit definition of the derivative:
- The formula: \[ f'(x) = \lim_{h \to 0} \frac{f(x+h) - f(x)}{h} \]
- This expression essentially computes the ratio of change in the function's value (numerator) to a small change in the input value, \( h \) (denominator).
- As \( h \) gets infinitely close to zero, the ratio approaches the function's instantaneous rate of change, or its derivative at \( x \).
Function Differentiation Simplified
Differentiation refers to the process of finding the derivative of a function. It's like finding the instant speed of a moving car by looking at its position over a tiny, tiny distance. In our exercise, we're differentiating a specific function:
- The function: \( y = -\frac{1}{4}x^2 \)
- We're using the limit definition to determine how this function changes as \( x \) changes.
- Substitute the function into the limit formula.
- Expand and simplify the expression algebraically.
- Carefully take the limit as \( h \) approaches zero.
Exploring Polynomial Functions
Polynomial functions are a set of algebraic expressions that consist of variables raised to whole number powers. They can be as simple as a single constant or as complex as an expression with multiple terms and variables.The function from our exercise, \( y = -\frac{1}{4}x^2 \), is a classic example of a polynomial function. Here’s a quick breakdown:
- The term \(-\frac{1}{4}x^2\) indicates a quadratic polynomial due to the \( x^2 \) term.
- The degree of the polynomial is 2 since the highest exponent is 2.
- It's a simple expression, making it a great starting point for understanding derivatives.