Chapter 20: Problem 38
Prove the given identities. $$\frac{\cos ^{3} \theta+\sin ^{3} \theta}{\cos \theta+\sin \theta}=1-\frac{1}{2} \sin 2 \theta$$
Short Answer
Expert verified
Use sum of cubes and trig identities to prove that \(\frac{\cos ^{3} \theta+\sin ^{3} \theta}{\cos \theta+\sin \theta}=1-\frac{1}{2} \sin 2 \theta\).
Step by step solution
01
Recognize the Identity Formula
We start by recognizing an identity formula. Notice that the numerator \(rac{ ext{cos}^{3} heta + ext{sin}^{3} heta}{ ext{cos} heta + ext{sin} heta}\) resembles the sum of cubes formula: \[ a^3 + b^3 = (a+b)(a^2 - ab + b^2) \]. This hints that we can factor the numerator using this formula.
02
Apply the Sum of Cubes Formula
Let \(a = ext{cos} heta\) and \(b = ext{sin} heta\). Applying the sum of cubes formula, we can express:\[ ext{cos}^{3} heta + ext{sin}^{3} heta = ( ext{cos} heta + ext{sin} heta)( ext{cos}^{2} heta - ext{cos} heta ext{sin} heta + ext{sin} ^{2} heta) \].Dividing both sides by \( ext{cos} heta + ext{sin} heta\), we simplify the fraction to:\[ ext{cos}^{2} heta - ext{cos} heta ext{sin} heta + ext{sin} ^{2} heta \].
03
Simplify Using Pythagorean Identity
By the Pythagorean identity, \( ext{cos}^{2} heta + ext{sin} ^{2} heta = 1\). Therefore, the expression simplifies further:\[ 1 - ext{cos} heta ext{sin} heta \].
04
Relate to Double Angle Identity
Recall the double angle identity for sine: \( ext{sin} 2 heta = 2 ext{sin} heta ext{cos} heta\). Thus, \( ext{cos} heta ext{sin} heta = \frac{1}{2} ext{sin} 2 heta\). Substitute this into the simplified expression:\[ 1 - \frac{1}{2} ext{sin} 2 heta \].
05
Verify Both Sides of the Equation
Both sides of the original identity are now identical after simplification:\[ \frac{ ext{cos}^{3} heta + ext{sin}^{3} heta}{ ext{cos} heta + ext{sin} heta} = 1 - \frac{1}{2} ext{sin} 2 heta \].Thus, the identity is proven.
Unlock Step-by-Step Solutions & Ace Your Exams!
-
Full Textbook Solutions
Get detailed explanations and key concepts
-
Unlimited Al creation
Al flashcards, explanations, exams and more...
-
Ads-free access
To over 500 millions flashcards
-
Money-back guarantee
We refund you if you fail your exam.
Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Sum of Cubes
In trigonometry and algebra, the sum of cubes is a formula used to factor expressions where two terms, each raised to the power of three, are added together. This formula is expressed as:\[ a^3 + b^3 = (a+b)(a^2 - ab + b^2) \]In this exercise, the formula is applied to factor trigonometric expressions like \( \cos^3 \theta + \sin^3 \theta \). This formula helps simplify the original expression by recognizing that the numerator can be rewritten in a product form.To effectively use the sum of cubes formula:
- Identify terms that match the form \( a^3 + b^3 \).
- Assign \( a = \cos \theta \) and \( b = \sin \theta \).
- Apply the sum of cubes formula to rewrite the expression.
Pythagorean Identity
The Pythagorean Identity is a crucial element in trigonometry, linking the square of sine and cosine functions to the number 1:\[ \cos^2 \theta + \sin^2 \theta = 1 \]This identity is derived from the Pythagorean theorem and underlies many simplifications in trigonometry.In our problem, after factoring with the sum of cubes formula, we end up with a term \( \cos^2 \theta + \sin^2 \theta \), which equals 1 according to the Pythagorean Identity. This simple substitution significantly simplifies the expression.Steps to apply the Pythagorean Identity:
- Identify the parts of the expression that can be rewritten using the identity, \( \cos^2 \theta + \sin^2 \theta \).
- Replace \( \cos^2 \theta + \sin^2 \theta \) with 1.
Double Angle Identity
The double angle identity for sine provides a useful relationship for manipulating expressions involving products of sine and cosine. Specifically, it states:\[ \sin 2\theta = 2 \sin \theta \cos \theta \]This identity expresses the sine of double the angle in terms of functions of \( \theta \).Within our exercise, after applying the Pythagorean Identity, we are left with \( 1 - \cos \theta \sin \theta \). By recognizing that \( \cos \theta \sin \theta \) can be written as \( \frac{1}{2} \sin 2\theta \) using the double angle identity for sine, the problem simplifies even further.When using the double angle identity:
- Note when a trigonometric expression involves \( \sin \theta \cos \theta \).
- Use \( \sin 2\theta = 2 \sin \theta \cos \theta \) to express products like \( \cos \theta \sin \theta \) as \( \frac{1}{2} \sin 2\theta \).
- Substitute and simplify accordingly.