Chapter 19: Problem 29
Find the first four terms of the indicated expansions by use of the binomial series. $$(1+x)^{8}$$
Short Answer
Expert verified
The first four terms of \((1+x)^8\) are 1, 8x, 28x², and 56x³.
Step by step solution
01
Understanding the Binomial Series
The binomial series for any expression \((1+x)^n\) is given by the formula:\[(1+x)^n = \sum_{k=0}^{\infty} \binom{n}{k} x^k\]where \(\binom{n}{k}\) is the binomial coefficient, computed as \(\frac{n!}{k!(n-k)!}\). We will use this to find the first four terms of the expansion for \((1+x)^8\).
02
Find the First Term
To find the first term, set \(k=0\) in the binomial series formula:\[\binom{8}{0} x^0 = 1,\]so the first term is 1.
03
Find the Second Term
For the second term, set \(k=1\) in the binomial formula:\[\binom{8}{1} x^1 = 8x.\]Here, \(\binom{8}{1} = 8\), so the second term is \(8x\).
04
Find the Third Term
Set \(k=2\) to find the third term:\[\binom{8}{2} x^2 = 28x^2.\]The binomial coefficient is \(\binom{8}{2} = 28\), so the third term is \(28x^2\).
05
Find the Fourth Term
Finally, set \(k=3\) to find the fourth term:\[\binom{8}{3} x^3 = 56x^3.\]Here, \(\binom{8}{3} = 56\), so the fourth term is \(56x^3\).
06
Combine the Terms
Combining all computed terms, the first four terms of the binomial expansion \((1+x)^8\) are:\[1 + 8x + 28x^2 + 56x^3.\]
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Binomial Coefficient
In mathematics, the binomial coefficient is a key concept used within the binomial theorem. It is denoted as \(\binom{n}{k}\) and is calculated with the formula:\[ \binom{n}{k} = \frac{n!}{k!(n-k)!} \]This notation represents the number of ways to choose \(k\) elements from a set of \(n\) elements. It plays a central role when expanding a binomial expression such as \((1+x)^n\). For example, when we calculate the values for \((1+x)^8\) as in the given exercise, we use the binomial coefficients to determine the specific multipliers for each term:
- \(\binom{8}{0} = 1\)
- \(\binom{8}{1} = 8\)
- \(\binom{8}{2} = 28\)
- \(\binom{8}{3} = 56\)
Binomial Expansion
The binomial expansion is a method to expand expressions of the form \((a+b)^n\) into sums of terms involving binomial coefficients. In the context of the exercise \((1+x)^8\), it involves expanding the expression into a polynomial.The expanded form using the binomial series is given by:\[ (1+x)^n = \sum_{k=0}^{n} \binom{n}{k} x^k \]This means each term in the expansion is a product of a binomial coefficient and a power of \(x\). Breaking it down again for \((1+x)^8\):
- The first term is \(1\), obtained by setting \(k=0\).
- The second term is \(8x\), as calculated with \(k=1\).
- The third term is \(28x^2\), found with \(k=2\).
- The fourth term is \(56x^3\), using \(k=3\).
Mathematical Induction
Mathematical induction is a powerful method of mathematical proof. Although not directly used in calculating a binomial expansion, it is frequently applied in many proofs involving binomial coefficients and series. Here's how induction works, step-by-step:
- Base Case: Prove that the statement holds for the initial value, typically \(n=0\) or \(n=1\).
- Inductive Step: Assume the statement is true for \(n=k\), and then prove it for \(n=k+1\).