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A varies directly as \(x,\) and \(B\) varies directly as \(x,\) although not in the same proportion as \(A .\) All numbers are positive. Show that \(A+B\) varies directly as \(x\)

Short Answer

Expert verified
Thus, \( A + B \) varies directly as \( x \).

Step by step solution

01

Understanding Direct Variation

Let's first understand the problem: 'A varies directly as x' means that there is a constant relationship between A and x such that \( A = kx \), where \( k \) is a constant. Similarly, 'B varies directly as x' implies that \( B = mx \) for some constant \( m \).
02

Express A and B in Terms of x

From the definitions, we express \( A \) and \( B \) in terms of \( x \): \( A = kx \) \( B = mx \)
03

Examine A+B

Now, we consider the expression for \( A + B \). Substituting the expressions for \( A \) and \( B \), we get: \( A + B = kx + mx \).
04

Factor Out x

To simplify \( kx + mx \), we factor out \( x \): \( A + B = (k + m)x \).
05

Conclude Direct Variation of A+B

The expression \((k + m)x\) means that \( A + B \) is a product of \( x \) and the constant \( (k + m) \). Therefore, \( A + B \) varies directly as \( x \), with the constant \( k + m \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Constant of Variation
When discussing direct variation, we often refer to something called the "constant of variation." This constant is crucial when two variables change in direct proportion to each other.

Let's explore what this means. If a variable \( A \) varies directly as another variable \( x \), it implies a direct proportion between \( A \) and \( x \). We can express this relationship with a mathematical equation: \( A = kx \). Here, \( k \) is the constant of variation, representing the rate at which \( A \) changes with respect to \( x \).

Similarly, if another variable \( B \) varies directly as \( x \), we write \( B = mx \). This implies that \( B \) changes with \( x \) according to a different constant, \( m \). It indicates a separate direct relationship with its own rate of change. Both \( k \) and \( m \) are constants of variation, but they might not be equal.
  • The constant of variation is unique to each direct variation relationship.
  • It helps us understand how rapidly or slowly a variable changes in response to another.
  • This concept allows for solving various real-world problems involving proportional relationships.
Mathematical Expressions
Mathematical expressions are a backbone of algebra. In their simplest form, they show relationships between numbers and variables. Consider the expression \( A = kx \). This is a mathematical expression representing the direct variation between \( A \) and \( x \).

Expressions help interpret and solve equations. For instance, given \( A = kx \) and \( B = mx \), we can explore what happens when we combine these, writing \( A + B = kx + mx \). This is again a mathematical expression showing the sum of \( A \) and \( B \) in terms of \( x \).
  • Expressions allow us to model situations using variables and constants.
  • They help encapsulate relationships like direct variation in an algebraic form.
  • Algebraic manipulation of expressions is fundamental in solving equations and evaluating mathematical statements.
Factoring in Algebra
Factoring in algebra is a method used to simplify mathematical expressions and solve equations. It involves breaking down an expression into its simplest parts that can be multiplied together to give the original expression.

Consider the expression \( kx + mx \). Both terms share a common factor, \( x \). To simplify, we use the technique of factoring to pull \( x \) out of the expression, resulting in \( (k + m)x \). This step is crucial because it leads us to an expression that clearly represents a direct variation: \( A + B = (k + m)x \).
  • Factoring helps in simplifying complex expressions by highlighting common factors.
  • It makes understanding relationships between variables more straightforward, as seen with factored expressions showing direct variation.
  • In solving equations, factoring can sometimes reveal solutions or simplify the path to solving more complicated problems.

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Most popular questions from this chapter

Solve the given applied problems involving variation. The \(f\) -number lens setting of a camera varies directly as the square root of the time \(t\) that the film is exposed. If the \(f\) -number is 8 (written as \(f / 8\) ) for \(t=0.0200\) s, find the \(f\) -number for \(t=0.0098\) s.

Solve the given applied problems involving variation. The time \(t\) required to empty a wastewater-holding tank is inversely proportional to the cross-sectional area \(A\) of the drainage pipe. If it takes \(2.0 \mathrm{h}\) to empty a tank with a drainage pipe for which \(A=48\) in. \(^{2}\), how long will it take to empty the tank if \(A=68\) in. \(^{2} ?\)

Find the required ratios. The electric current in a given circuit is the ratio of the voltage to the resistance. What is the current ( \(1 \mathrm{V} / 1 \Omega=1 \mathrm{A}\) ) for a circuit where the voltage is \(24.0 \mathrm{mV}\) and the resistance is \(10.0 \Omega ?\)

Solve the given applied problems involving variation. The power gain \(G\) by a parabolic microwave dish varies directly as the square of the diameter \(d\) of the opening and inversely as the square of the wavelength \(\lambda\) of the wave carrier. Find the equation relating \(G, d,\) and \(\lambda\) if \(G=5.5 \times 10^{4}\) for \(d=2.9 \mathrm{m}\) and \(\lambda=3.0 \mathrm{cm}\).

Answer the given questions by setting up and solving the appropriate proportions. Of Earth's water area, the Pacific Ocean covers \(46.0 \%,\) and the Atlantic Ocean covers \(23.9 \% .\) Together they cover a total of \(2.53 \times 10^{8} \mathrm{km}^{2} .\) What is the area of each?

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