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Express the meaning of the given equation in a verbal statement, using the language of variation. ( \(k\) and \(\pi\) are constants.) $$s=\frac{k}{\sqrt[3]{t}}$$

Short Answer

Expert verified
The variable \( s \) inversely varies with the cube root of \( t \).

Step by step solution

01

Understanding Constants and Variables

In the equation \( s = \frac{k}{\sqrt[3]{t}} \), \( k \) and \( \pi \) are constants, but only \( k \) appears in this equation. \( s \) is the dependent variable that changes in response to \( t \), the independent variable.
02

Identifying the Type of Variation

Here, \( s \) is inversely varying with respect to \( \sqrt[3]{t} \). This means as \( t \) increases, \( s \) decreases and vice versa because \( s \) is in the numerator while \( \sqrt[3]{t} \) is in the denominator.
03

Verbalizing the Equation

The equation means that \( s \) varies inversely with the cube root of \( t \). As the cube root of \( t \) increases, \( s \) decreases, and as the cube root of \( t \) decreases, \( s \) increases. This inverse relationship is modulated by the constant \( k \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Dependent Variable
In the equation \( s = \frac{k}{\sqrt[3]{t}} \), the term we call the *dependent variable* is \( s \). The value of \( s \) depends on the value of another variable within the equation.
More specifically, its behavior is controlled by the independent variable, which in this case is \( t \).
When we're discussing the concept of dependent variables in mathematics, we often think of them as outcomes or results. These outcomes change when the input—here, the independent variable—changes.
In our specific equation, as \( t \) changes, so does the value of \( s \). For example, if you substitute a different value of \( t \), \( s \) will generate a new result based on that value of \( t \) and the constant \( k \).
Understanding this relationship helps us draw conclusions about how these variables interact in inverse variation scenarios. It’s essential since these ideas often appear in various fields from physics to economics.
Independent Variable
In any mathematical relationship, we talk about the *independent variable* as the cause of change. In our equation, \( t \) is the independent variable. It rows the outcomes of the dependent variable \( s \).
Think of independent variables as the inputs or sources of variation. You can control them, and by manipulating their values, you observe corresponding changes in the dependent variable.
In the context of the equation \( s = \frac{k}{\sqrt[3]{t}} \), as you alter \( t \), you directly influence \( s \). For example, increasing \( t \) will result in an increase in its cube root, leading to a decrease in \( s \), due to the inverse relationship stated by the structure of the equation.
Understanding how the independent variable impacts the dependent variable is crucial. It allows us to predict outcomes given specific inputs, especially in models involving inverse variation.
Cube Root
The cube root function, denoted as \( \sqrt[3]{t} \), is a critical aspect of our equation. It reveals how the variable \( t \) influences the outcome variable \( s \).
Understanding cube roots involves recognizing that a cube root of a number \( t \) is a value that, when multiplied by itself three times, gives \( t \).
In the context of the equation, the cube root modifies \( t \) before its impact on \( s \) is assessed. This modification is essential because \( s \) varies inversely with this transformed \( t \). A small increase in \( t \) can lead to a less than proportional increase in \( \sqrt[3]{t} \), due to the nature of the cube root operation.
In inverse variation, the complexity of relationships often holds the key to understanding deeper principles across scientific and mathematical disciplines. Cube roots, in particular, slow down the rate of change, demonstrating the non-linear nature of such equations.

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Most popular questions from this chapter

Solve the given applied problems involving variation. The average speed \(s\) of oxygen molecules in the air is directly proportional to the square root of the absolute temperature \(T\). If the speed of the molecules is \(460 \mathrm{m} / \mathrm{s}\) at \(273 \mathrm{K},\) what is the speed at \(300 \mathrm{K} ?\)

Solve the given applied problems involving variation. The power gain \(G\) by a parabolic microwave dish varies directly as the square of the diameter \(d\) of the opening and inversely as the square of the wavelength \(\lambda\) of the wave carrier. Find the equation relating \(G, d,\) and \(\lambda\) if \(G=5.5 \times 10^{4}\) for \(d=2.9 \mathrm{m}\) and \(\lambda=3.0 \mathrm{cm}\).

Answer the given questions by setting up and solving the appropriate proportions. Given that \(10^{4} \mathrm{cm}^{2}=10^{6} \mathrm{mm}^{2},\) what area in square centimeters is \(2.50 \times 10^{5} \mathrm{mm}^{2} ?\)

Answer the given questions by setting up and solving the appropriate proportions. By weight, the ratio of chlorine to sodium in table salt is 35.46 to 23.00. How much sodium is contained in \(50.00 \mathrm{kg}\) of salt?

Solve the given applied problems involving variation. The force \(F\) between two parallel wires carrying electric currents is inversely proportional to the distance \(d\) between the wires. If a force of \(0.750 \mathrm{N}\) exists between wires that are \(1.25 \mathrm{cm}\) apart, what is the force between them if they are separated by \(1.75 \mathrm{cm} ?\)

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