/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 32 Perform the indicated matrix mul... [FREE SOLUTION] | 91Ó°ÊÓ

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Perform the indicated matrix multiplications on a calculator, using the following matrices. For matrix \(A, A^{2}=A \times A\) $$A=\left[\begin{array}{rrr} 2 & -3 & -5 \\ -1 & 4 & 5 \\ 1 & -3 & -4 \end{array}\right] B=\left[\begin{array}{rrr} 1 & -2 & -6 \\ -3 & 2 & 9 \\ 2 & 0 & -3 \end{array}\right] C=\left[\begin{array}{rrr} 1 & -3 & -4 \\ -1 & 3 & 4 \\ 1 & -3 & -4 \end{array}\right]$$ Show that \(C^{2}=O\)

Short Answer

Expert verified
Matrix \( C^2 \) results in the zero matrix \( O \).

Step by step solution

01

Understand the Problem

We need to show that multiplying matrix \( C \) by itself results in the zero matrix \( O \). This means we need to calculate \( C^2 = C \times C \) and verify that all elements of the resulting matrix are zero.
02

Set Up the Multiplication

Write down the multiplication of matrix \( C \) with itself. Matrix \( C \) is given as: \[C = \begin{bmatrix}1 & -3 & -4 \-1 & 3 & 4 \1 & -3 & -4\end{bmatrix}\] Set up \( C \times C \) where each element of the resulting matrix \( C^2 \) will be calculated using the dot product of rows from the first \( C \) and columns from the second \( C \).
03

Calculate Each Element of C²

Compute each element for \( C^2 \) by taking the dot product of the corresponding row and column. For example, the element in the first row and first column of \( C^2 \) is:\[(1 \cdot 1) + (-3 \cdot -1) + (-4 \cdot 1) = 1 + 3 - 4 = 0\]Repeat this process for each element in the resulting matrix. Calculate for first row, second column:\[(1 \cdot -3) + (-3 \cdot 3) + (-4 \cdot -3) = -3 - 9 + 12 = 0\]Continue this process for all 9 elements of \( C^2 \) matrix.
04

Write the Resulting Matrix

After computing all elements, the resulting matrix \( C^2 \) is:\[C^2 = \begin{bmatrix}0 & 0 & 0 \0 & 0 & 0 \0 & 0 & 0\end{bmatrix}\]All elements are zero, thus we have shown that \( C^2 = O \), the zero matrix.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Zero Matrix
A zero matrix is a special type of matrix where every entry is zero. It is denoted by the symbol \( O \). This matrix plays a significant role in matrix operations, serving as the additive identity in matrix addition. In other words, adding a zero matrix to any given matrix will return that same matrix unchanged.

This concept is somewhat similar to adding zero to a number: it does not change the value of the number. For example, if you have matrix \( C \) and you add a zero matrix \( O \) to it, you will simply get matrix \( C \) again.

Moreover, when it comes to matrics multiplication, multiplying any matrix by a zero matrix will always result in a zero matrix. This is because each element of the resulting matrix is calculated as a sum of products that all involve zero, hence resulting in zero. Understanding the role of the zero matrix can greatly enhance your grasp of fundamental matrix operations.
Matrix Exponentiation
Matrix exponentiation refers to the process of multiplying a matrix by itself a certain number of times. For example, if you have a matrix \( A \), then \( A^2 \) means \( A \times A \), and \( A^3 \) means \( A \times A \times A \). This operation is only defined for square matrices, where the number of rows is equal to the number of columns.

When dealing with matrices, exponents are particularly meaningful in simplifying powers of matrices and solving linear recurrence relations among other applications. However, calculating high powers of matrices manually can be computationally expensive, and in practice, algorithms or calculators are often used.

In the context of the original exercise, it’s clear why matrix exponentiation was important. The task involved showing if matrix \( C \) when squared, results in the zero matrix. This type of problem often appears in exploring the properties of matrices, such as whether they are nilpotent (a matrix \( A \) is nilpotent if there exists some positive integer \( k \) such that \( A^k = O \)).

Matrix exponentiation provides a foundation for more advanced matrix operations, including matrix functions and transformations in fields such as computer graphics and system dynamics.
Dot Product
The dot product is a key operation in matrix multiplications and is essential for calculating each element of the resulting matrix during these operations. To perform a dot product, you multiply corresponding elements from two sequences of numbers and then sum these products.

In the context of multiplying matrices, the dot product of a row from the first matrix and a column from the second matrix yields a single scalar result that becomes one entry in the resulting matrix. For example, when multiplying two matrices \( A \) and \( B \), you take the first row of \( A \) and the first column of \( B \), then use their dot product to find the element at the first row, first column of the resultant matrix.

Formally, if the first matrix is of size \( n \times m \) and the second matrix is of size \( m \times p \), their product is an \( n \times p \) matrix. The dot product is utilized within this calculation to sum products of corresponding elements from rows and columns.

For example, if one row is \([a_1, a_2, a_3]\) and a corresponding column is \([b_1, b_2, b_3]\), the dot product would be \(a_1b_1 + a_2b_2 + a_3b_3\). This simple yet powerful concept underlies much more complex calculations in linear algebra.

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Most popular questions from this chapter

Solve the indicated systems of equations using the inverse of the coefficient matrix. In Exercises \(35-40,\) it is necessary to set up the appropriate equations. A research chemist wants to make \(10.0 \mathrm{L}\) of gasoline containing 2.0\% of a new experimental additive. Gasoline without additive and two mixtures of gasoline with additive, one with \(5.0 \%\) and the other with \(6.0 \%,\) are to be used. If four times as much gasoline without additive as the \(5.0 \%\) mixture is to be used, how much of each is needed?

Solve the given systems of equations by using the inverse of the coefficient matrix. Use a calculator to perform the necessary matrix operations and display the results and the check. See Example 4. $$\begin{aligned} &4 x-y+2 z-2 t+u=-15\\\ &8 x+y-z+4 t-2 u=26\\\ &2 x-6 y-2 z+t-u=10\\\ &2 x+5 y+z-3 t+8 u=-22\\\ &4 x-3 y+2 z+4 t+2 u=-4 \end{aligned}$$

Make the indicated changes in the determinant at the right, and then solve the indicated problem. Assume the elements are nonzero, unless otherwise specified. $$\left|\begin{array}{lll} a & b & c \\ d & e & f \\ g & h & i \end{array}\right|$$ By what factor is the value of the determinant changed if all elements are doubled?

Solve the given problems using Gaussian elimination. Solve the system \(x+2 y=6,2 x+a y=4\) and show that the solution depends on the value of \(a\). What value of \(a\) does the solution show may not be used?

Solve the given problems. The matrix A \(=\left[\begin{array}{rrr}2 & -1 & 1 \\ -1 & 4 & -3 \\ 1 & -3 & 2\end{array}\right]\) is symmetric (note the elements on opposite sides of the main diagonal are equal). Show that \(A^{-1}\) is also symmetric.

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