/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 54 Solve for \(y\) in terms of \(x\... [FREE SOLUTION] | 91Ó°ÊÓ

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Solve for \(y\) in terms of \(x\) $$\pi \log _{4} x+\log _{4} y=1$$

Short Answer

Expert verified
The solution is: \(y = 4 \times x^{-\pi}\).

Step by step solution

01

Isolate the Logarithm Involving y

Start with the original equation: \(\pi \log_{4} x + \log_{4} y = 1\). To isolate \(\log_{4} y\), subtract \(\pi \log_{4} x\) from both sides of the equation. This gives us \(\log_{4} y = 1 - \pi \log_{4} x\).
02

Apply the Exponential Function

We need to solve for \(y\), so we remove the logarithm by using the definition of a logarithm, which implies \(x = 4^{\log_{4} x}\). Therefore, \(y = 4^{1 - \pi \log_{4} x}\).
03

Simplify the Exponent

Let's simplify the exponent. The expression \(4^{1 - \pi \log_{4} x}\) can be separated as \(4^{1} \times 4^{(-\pi \log_{4} x)}\). Further simplifying gives \(4 \times x^{-\pi}\) because \(4^{\log_{4} x} = x\) and using laws of exponents.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Exponential Functions
Exponential functions are mathematical expressions where a variable appears as an exponent. For example, when we have an equation like \(y = 4^x\), this is an exponential function, where 4 is the base and \(x\) is the exponent. They are vital in many fields of science and mathematics because they describe phenomena such as population growth, radioactive decay, and interest calculations.

In our exercise, the equation \(y = 4^{1 - \pi \log_{4} x}\) showcases an exponential function. Here, the base is 4, and the exponent is the expression \(1 - \pi \log_{4} x\). Understanding exponential functions is crucial because they help us transform logarithmic equations into more simplified expressions by eliminating the logarithm and expressing the variable directly in terms of the base exponent.

This transformation is particularly useful when you need to solve for a specific variable, making complex equations more manageable and easier to solve.
Laws of Exponents
The laws of exponents are crucial rules that govern how to manipulate expressions with exponents. Here are some of the basic laws that are frequently used:
  • Product of Powers: \(a^m \times a^n = a^{m+n}\)
  • Power of a Power: \((a^m)^n = a^{m \times n}\)
  • Power of a Product: \((ab)^m = a^m \times b^m\)
  • Zero Exponent: \(a^0 = 1\) for any non-zero \(a\)
  • Negative Exponent: \(a^{-n} = \frac{1}{a^n}\)
In the step-by-step solution, the laws of exponents were applied to simplify the equation \(y = 4^{1 - \pi \log_{4} x}\) into \(4 \times x^{-\pi}\). This simplification uses the properties that allow us to split exponents and turn products into simpler terms. Understanding how these laws work and when to apply them helps in breaking down difficult-looking exponential terms into much simpler components.
Isolating Variables
Isolating variables is a fundamental step in solving equations. It involves rearranging the equation so that one variable is on one side of the equation, usually the left, while the rest of the terms are on the other side.

In our exercise, the first step was to isolate \(\log_{4} y\). We started with the equation \(\pi \log_{4} x + \log_{4} y = 1\). By subtracting \(\pi \log_{4} x\) from both sides, we isolated \(\log_{4} y\) as \(\log_{4} y = 1 - \pi \log_{4} x\).

This process of isolating variables is especially important because it sets the stage for further simplification and solution of the equation. By focusing on one variable, it becomes easier to apply other mathematical principles and solve the equation entirely, making this a vital skill in algebra and calculus.

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Most popular questions from this chapter

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