Chapter 13: Problem 11
Evaluate the exponential function \(y=4^{x}\) for the given values of \(x\). $$x=0.5$$
Short Answer
Expert verified
The value of the function at \(x=0.5\) is 2.
Step by step solution
01
Substitute the Value of x
Start by substituting the given value of \(x = 0.5\) into the exponential function \(y = 4^x\). This gives us \(y = 4^{0.5}\).
02
Simplify the Exponent
Next, recognize that \(4^{0.5}\) is equivalent to the square root of 4. This is because raising a number to the power of \(0.5\) is the same as taking the square root of that number.
03
Calculate the Square Root
Calculate the square root of 4. Since \(\sqrt{4} = 2\), this simplifies to \(y = 2\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Understanding Exponential Growth
Exponential growth is a process where quantities increase rapidly following a consistent multiplier per time period. This is often observed in nature, populations, and compound interest scenarios. Unlike linear growth, which increases by a set amount, exponential growth involves multiplication by a constant factor, leading the values to skyrocket.
In an exponential function like \(y = 4^x\), the number 4 is the base, and \(x\) is the exponent. Depending on \(x\), the output of the function changes significantly. With positive integers, the outputs escalate rapidly. But when \(x\) is a fraction, the function behaves differently, providing subtler effects such as fractional outputs or roots of the base.
In an exponential function like \(y = 4^x\), the number 4 is the base, and \(x\) is the exponent. Depending on \(x\), the output of the function changes significantly. With positive integers, the outputs escalate rapidly. But when \(x\) is a fraction, the function behaves differently, providing subtler effects such as fractional outputs or roots of the base.
- Exponential functions with whole number bases grow significantly as exponents increase.
- Even small changes in the exponent can dramatically affect the results.
- For base values greater than 1, the function results will grow larger than the original base.
Steps to Evaluating Functions
Evaluating functions involves finding the output value for a given function input. This process is critical in solving mathematical problems and understanding how functions behave.
When evaluating an exponential function like \(y = 4^x\), the main objective is to substitute the given value of \(x\) into the function and simplify. Following these steps ensures clear and correct results:
When evaluating an exponential function like \(y = 4^x\), the main objective is to substitute the given value of \(x\) into the function and simplify. Following these steps ensures clear and correct results:
- **Substitute the Value**: Replace \(x\) in the function with the specified value. For example, if \(x = 0.5\), the equation becomes \(y = 4^{0.5}\).
- **Simplify the Expression**: Recognize patterns or mathematical properties, such as roots or fractions, to simplify the calculation.
- **Calculate**: Perform the necessary arithmetic or algebraic calculations to find the final answer. Here, recognizing that \(4^{0.5}\) equates to the square root of 4 makes it straightforward to solve.
The Concept of Square Roots
A square root is a number that, when multiplied by itself, yields the original number. This mathematical concept is foundational and ubiquitous in various calculations and real-world applications.
For example, the square root of 4 is 2, because \(2 \times 2 = 4\). When dealing with powers, especially fractional exponents like \(0.5\), understanding square roots becomes invaluable.
For example, the square root of 4 is 2, because \(2 \times 2 = 4\). When dealing with powers, especially fractional exponents like \(0.5\), understanding square roots becomes invaluable.
- **Fractional Exponents**: An exponent of \(0.5\) indicates taking the square root of the base. So, \(4^{0.5} = \sqrt{4}\).
- **Real-World Application**: Square roots often appear in geometry, involving areas and dimensions, and in physics, when dealing with velocities and accelerations.
- **Mathematical Simplification**: Recognizing when to apply square roots can simplify complex algebraic expressions or function evaluations.